Explanation Given: The function is lim ( x , y ) → ( − 2 , 1 ) 2 x 2 4 x + y . Calculation: The function is lim ( x , y ) → ( − 2 , 1 ) 2 x 2 4 x + y . Let f ( x , y ) = 2 x 2 4 x + y . This is a rational function and the denominator of the function is not equal to zero at ( − 2 , 1 ) . 4 x + y = 4 ( − 2 ) + 1 = − 8 + 1 = − 7 ≠ 0 So, f ( x , y ) is continuous at point ( − 2 , 1 ) ...

Loose-leaf Version for Calculus: Early Transcendentals Combo 3e & WebAssign for Calculus: Early Transcendentals 3e (Life of Edition)

3rd Edition

ISBN: 9781319019846

Author: Jon Rogawski, Colin Adams

Publisher: W. H. Freeman

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Chapter 14.2, Problem 4E

To determine

Evaluate the limit using continuity.

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Chapter 14.2, Problem 3E

Chapter 14.2, Problem 5E

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Chapter 14 Solutions

Loose-leaf Version for Calculus: Early Transcendentals Combo 3e & WebAssign for Calculus: Early Transcendentals 3e (Life of Edition)

Ch. 14.1 - Prob. 1PQ Ch. 14.1 - Prob. 2PQ Ch. 14.1 - Prob. 3PQ Ch. 14.1 - Prob. 4PQ Ch. 14.1 - Prob. 5PQ Ch. 14.1 - Prob. 1E Ch. 14.1 - Prob. 2E Ch. 14.1 - Prob. 3E Ch. 14.1 - Prob. 4E Ch. 14.1 - Prob. 5E

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