Explanation Given Information: The sequence, a n = ( − 1 ) n + 1 ( n 2 − 1 ) , 1 ≤ n ≤ 3 . Calculation: Consider the sequence, a n = ( − 1 ) n + 1 ( n 2 − 1 ) , 1 ≤ n ≤ 3 . The term, 1 ≤ n ≤ 3 means that domain is restricted to the first three positive integers indicating that the sequence is finite. Now, the terms of the sequence, a n = ( − 1 ) n + 1 ( n 2 − 1 ) is calculated in the table shown below, n a n = ( - 1 ) n + 1 ( n 2 - 1 ) 1 a 1 = ( − 1 ) </

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Chapter 14.2, Problem 13PE

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To calculate: The terms of sequence, an=(−1)n+1(n2−1), 1≤n≤3.

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Chapter 14.2, Problem 12PE

Chapter 14.2, Problem 14PE

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Chapter 14 Solutions

BEGINNING AND INTERMEDIATE AGEBRA

Ch. 14.1 - Prob. 1SP Ch. 14.1 - Prob. 2SP Ch. 14.1 - Evaluate the expressions. 3. 1! Ch. 14.1 - Prob. 4SP Ch. 14.1 - Prob. 5SP Ch. 14.1 - Prob. 6SP Ch. 14.1 - Write out the first three terms of ( x + y ) 5 .Ch. 14.1 - 8. Use the binomial theorem to expand . Ch. 14.1 - Use the binomial theorem to expand ( 2 a − 3 b 2 )...Ch. 14.1 - Find the fourth term of ( x + y ) 8 .

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The terms of sequence, a n = ( − 1 ) n + 1 ( n 2 − 1 ) , 1 ≤ n ≤ 3 .

Solution Summary: The author calculates the terms of the sequence, a_n=(-1).

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To calculate: The terms of sequence, an=(−1)n+1(n2−1), 1≤n≤3.

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Chapter 14 Solutions