Campbell Biology
12th Edition
ISBN: 9780135188743
Author: Urry
Publisher: PEARSON
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Chapter 14.1, Problem 1CC
DRAW IT Ø Pea plants heterozygous for flower position and stem length (AaTt) are allowed to self-pollinate, and 400 of the resulting seeds are planted. Draw a Punnett Square for this cross. How many offspring would be predicted to have terminal flowers and be dwarf? (See Table 14.1.)
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DRAW IT Pea plants heterozygousfor flower position and stem length(AaTt) are allowed to self-pollinate,and 400 of the resulting seeds areplanted. Draw a Punnett square forthis cross. How many offspring wouldbe predicted to have terminal flowers and be dwarf? (See Table 14.1.)
Chapter 14 Solutions
Campbell Biology
Ch. 14.1 - DRAW IT Pea plants heterozygous for flower...Ch. 14.1 - WHAT IF? List all gametes that could be made by a...Ch. 14.1 - MAKE CONNECTIONS In some pea plant crosses, the...Ch. 14.2 - Prob. 1CCCh. 14.2 - Two organisms, with genotypcs BbDD and BBDd, are...Ch. 14.2 - WHAT IF? Three characters (flower color, seed...Ch. 14.3 - What two properties, one structural and one...Ch. 14.3 - If a man with type AB blood marries a woman with...Ch. 14.3 - WHAT IF? A rooster with gray feathers and a hen...Ch. 14.4 - Prob. 1CC
Ch. 14.4 - Prob. 2CCCh. 14.4 - Prob. 3CCCh. 14.4 - MAKE CONNECTIONS In Table 14.1, note the...Ch. 14 - When Mendel did crosses of true-breeding purple-...Ch. 14 - DRAW IT Redraw the Punnett Square on The right...Ch. 14 - Inheritance patterns are often more complex than...Ch. 14 - Both members of a couple know that they are...Ch. 14 - Prob. 1TYUCh. 14 - A man with type A blood marries a woman with type...Ch. 14 - A man has six fingers on each hand and six toes on...Ch. 14 - Prob. 4TYUCh. 14 - Flower position, stem length, and seed shape are...Ch. 14 - Hemochromatosis is an inherited disease caused by...Ch. 14 - The genotype of F1, individuals in a tetrahybrid...Ch. 14 - What is the probability that each of thc following...Ch. 14 - Prob. 9TYUCh. 14 - Prob. 10TYUCh. 14 - In tigers, a recessive allele of a particular gene...Ch. 14 - In maize (com) plants,a dominant allele I inhibits...Ch. 14 - The pedigree belowtraces the inheritance of...Ch. 14 - Imagine that you are a genetic counselor, and a...Ch. 14 - EVOLUTION CONNECTION Over the past half century,...Ch. 14 - SCIENTIFIC INQUIRY You are handed a mystery pea...Ch. 14 - Prob. 17TYUCh. 14 - SYNTHESIZE YOUR KNOWLEDGE Just for fun, imagine...
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- Y = yellow, y = green; R = round seed, r = wrinkled seed Dihybrid cross: If you mate YyRr x YyRr then what proportion of offspring will be green and wrinkled? 6/16 3/16 O 1/16 O 9/16arrow_forwardA pea plant is heterozygous for three genes (Tt Rr Yy), whereT = tall, t = dwarf, R = round seeds, r = wrinkled seeds, Y = yellowseeds, and y = green seeds. Tall, round, and yellow are the dominanttraits. What is the probability that an offspring from self-fertilizationof this plant will be tall with wrinkled, yellow seeds?arrow_forwardSuppose a purple flower heterozygous for stem size is crossed with a large stem (dominant) purple flower. What are the possible genotypes and phenotypes of offspring?arrow_forward
- A triploid plant has 18 chromosomes (i.e., 6 chromosomes perset). If we assume a gamete has an equal probability of receivingone or two copies of each of the six types of chromosome, whatare the odds of this plant producing a haploid or a diploid gamete?What are the odds of producing an aneuploid gamete? If theplant is allowed to self-fertilize, what are the odds of producing aeuploid offspring?arrow_forward. In nature, the plant Plectritis congesta is dimorphic forfruit shape; that is, individual plants bear either winglessor winged fruits, as shown in the illustration.Wingless fruit Winged fruitPlants were collected from nature before floweringand were crossed or selfed with the following results:Number of progenyPollination Winged WinglessWinged (selfed) 91 1*Winged (selfed) 90 30Wingless (selfed) 4* 80Winged × wingless 161 0Winged × wingless 29 31Winged × wingless 46 0Winged × winged 44 0*Phenotype probably has a nongenetic explanation.Interpret these results, and derive the mode ofinheritance of these fruit-shaped phenotypes. Usesymbols. What do you think is the nongeneticexplanation for the phenotypes marked by asterisks inthe table?arrow_forwardas: For pea plant, yellow seeds coat are dominant ov green seed coat, and long stems are dominant over she stem. Determine the phenotype and genotype rations the F1 offspring from cross-pollination of a heterozygous yellow seed coat, a homozygous long stem plant.arrow_forward
- 17)arrow_forwardGgTt pea plants can produce _____ type(s) of gamete(s), but a ggtt plant can produce _____ type(s) of gamete(s). explainarrow_forwardIdentify the genotypes of the pea flower plants for each generation P (Guadretieding parents) Phenotypes Purple flowers : Genotypes White flowers 1 2 F1 Gerleyatids) Phenotypes All purple flowers : Genotypes 3 Self- or cross-pollination F2 Generation Phenotypes Purple flowers : Genotypes White flowers 4arrow_forward
- Consider a corn plant dihybrid for the traits of purple and smooth kernels. When allowed to self-fertilize, 489 offspring are produced. How many of these offspring are expected to exhibit the traits of yellow and smooth kernels?arrow_forwardRound seed is dominant over wrinkled. Yellow cotyledon is dominant overgreen. Full pod is dominant over constricted. The genes for these traits arefound on separate chromosomes. If a trihybrid plant is self-fertilized, whatproportion of the progeny will have round seeds in constricted pods?Express answer in fraction form.arrow_forwardA pea plant that is (RrYy) is allowed to self-fertilize. Round seed(R) is dominant to wrinkled (r), and yellow seed (Y) is dominant togreen (y). What is the probability of producing the following groupof five seeds: two round, yellow; one round, green; one wrinkled,yellow; and one wrinkled, green?arrow_forward
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