
The
To compare: The results with the U.S. figures.

Answer to Problem 13E
The sample mean of the average population is 50,662.2 and the sample mean of pupils per teacher is 11.92
There is large difference between the sample and the population means in the average population, and the sample there is no large difference between the sample and the population mean in the pupils per teacher
Explanation of Solution
Calculation:
Answers will vary. One of the possible answers is given below:
The data with serial numbers is,
State number | States | Pupils per teacher | Teacher’s average pay |
1 | AL | 16.0 | 47,571 |
2 | AK | 14.9 | 59,672 |
3 | AZ | 18.9 | 46,952 |
4 | AR | 12.7 | 14,700 |
5 | CA | 21.4 | 68,203 |
6 | CO | 17.0 | 49,202 |
7 | CT | 13.2 | 64,350 |
8 | DE | 14.4 | 57,080 |
9 | FL | 15.9 | 46,708 |
10 | GA | 14.4 | 53,112 |
11 | HI | 15.2 | 55,063 |
12 | ID | 18.2 | 46,283 |
13 | IL | 14.9 | 62,077 |
14 | IN | 16.7 | 49,986 |
15 | IA | 13.8 | 49,626 |
16 | KS | 13.7 | 46,657 |
17 | KY | 15.8 | 49,543 |
18 | LA | 14.0 | 48,903 |
19 | ME | 11.1 | 46,106 |
20 | MD | 14.3 | 63,971 |
21 | MA | 13.6 | 69,273 |
22 | MI | 17.1 | 57,958 |
23 | MN | 15.4 | 52,431 |
24 | MS | 31.9 | 45,644 |
25 | MO | 13.3 | 45,317 |
26 | MT | 13.4 | 45,759 |
27 | NE | 13.4 | 46,227 |
28 | NV | 18.5 | 51,524 |
29 | NH | 12.7 | 51,443 |
30 | NJ | 12.0 | 65,130 |
31 | NM | 14.9 | 46,258 |
32 | NY | 11.8 | 71,633 |
33 | NC | 14.8 | 46,850 |
34 | ND | 12.1 | 42,964 |
35 | OH | 17.1 | 55,958 |
36 | OK | 15.5 | 47,691 |
37 | OR | 18.7 | 55,224 |
38 | PA | 14.0 | 59,156 |
39 | RI | 13.0 | 59,686 |
40 | SC | 14.8 | 47,508 |
41 | SD | 13.4 | 38,837 |
42 | TN | 14.7 | 46,290 |
43 | TX | 14.5 | 48,261 |
44 | UT | 22.4 | 45,885 |
45 | VT | 9.8 | 49,084 |
46 | VA | 11.7 | 50,015 |
47 | WA | 19.3 | 53,003 |
48 | WV | 14.3 | 45,959 |
49 | WI | 14.8 | 51,264 |
50 | WY | 12.3 | 55,861 |
There are many ways to divide the population into clusters. Here, the population is divided into cluster based on ranges of pupils per teacher.
Procedure for selecting the 10 samples by using cluster sampling is as follows:
- In the given data the highest value of pupils per teacher is 31.9 and least value of pupils per teacher is 9.8.
- Divide the given data into 5 clusters, based on the
range of pupils per teacher - The range obtained is 22.1, divide the range by 5, and length of the interval would be 4.42.
- Arrangement of intervals with range 4.42 as follows.
9.8-14.22 |
14.23-18.65 |
18.66-23.08 |
23.09-27.51 |
27.52-31.94 |
- Arrange all the values of pupils per teacher according to the intervals and each interval is named as cluster1, cluster2, cluster3, cluster4, cluster5.
- The following table represents the 5 clusters, which are arranged according to the intervals.
Cluster1:
States | Pupils per teacher | Teacher’s average pay |
VT | 9.8 | 49,084 |
ME | 11.1 | 46,106 |
VA | 11.7 | 50,015 |
NY | 11.8 | 71,633 |
NJ | 12.0 | 65,130 |
ND | 12.1 | 42,964 |
WY | 12.3 | 55,861 |
AR | 12.7 | 14,700 |
NH | 12.7 | 51,443 |
RI | 13.0 | 59,686 |
CT | 13.2 | 64,350 |
MO | 13.3 | 45,317 |
MT | 13.4 | 45,759 |
NE | 13.4 | 46,227 |
SD | 13.4 | 38,837 |
MA | 13.6 | 69,273 |
KS | 13.7 | 46,657 |
IA | 13.8 | 49,626 |
LA | 14.0 | 48,903 |
PA | 14.0 | 59,156 |
Cluster2:
States | Pupils per teacher | Teacher’s average pay |
MD | 14.3 | 63,971 |
WV | 14.3 | 45,959 |
DE | 14.4 | 57,080 |
GA | 14.4 | 53,112 |
TX | 14.5 | 48,261 |
TN | 14.7 | 46,290 |
NC | 14.8 | 46,850 |
SC | 14.8 | 47,508 |
WI | 14.8 | 51,264 |
AK | 14.9 | 59,672 |
IL | 14.9 | 62,077 |
NM | 14.9 | 46,258 |
HI | 15.2 | 55,063 |
U.S. | 15.3 | 55,202 |
MN | 15.4 | 52,431 |
OK | 15.5 | 47,691 |
KY | 15.8 | 49,543 |
FL | 15.9 | 46,708 |
AL | 16.0 | 47,571 |
IN | 16.7 | 49,986 |
CO | 17.0 | 49,202 |
Ml | 17.1 | 57,958 |
OH | 17.1 | 55,958 |
ID | 18.2 | 46,283 |
NV | 18.5 | 51,524 |
Cluster3:
States | Pupils per teacher | Teacher’s average pay |
OR | 18.7 | 55,224 |
AZ | 18.9 | 46,952 |
WA | 19.3 | 53,003 |
CA | 21.4 | 68,203 |
UT | 22.4 | 45,885 |
Cluster 5:
State | Pupils per teacher | Teacher’s average pay |
MS | 31.9 | 45,644 |
From the above clusters, select cluster 1 and from that select the first 10 samples for calculating the means.
Calculate means for pupils per teacher and average population as follows.
States | Pupils per teacher | Average population |
VT | 9.8 | 49,084 |
ME | 11.1 | 46,106 |
VA | 11.7 | 50,015 |
NY | 11.8 | 71,633 |
NJ | 12.0 | 65,130 |
ND | 12.1 | 42,964 |
WY | 12.3 | 55,861 |
AR | 12.7 | 14,700 |
NH | 12.7 | 51,443 |
RI | 13.0 | 59,686 |
Total | 119.2 | 506,622 |
The sample mean of pupil per teacher is,
The population mean of pupils per teacher is
The sample mean of teacher’s average pay is,
The population mean for teacher’s average pay is,
Thus, the sample mean of teacher’s average pay is 50,662.2 and the sample mean of pupils per teacher is 11.92. Also the population mean of teacher’s average pay is 51,477.16, and the population mean of pupils per teacher is 15.234.
Comparison of means:
In U.S., the number of pupils per teacher is 15.3 and the teacher’s average pay is 55,202.
There is large difference between the number of pupils per teacher in the U.S. and the sample mean and also in the average of teacher’s pay of the sample is less than the U.S. teacher’s average pay.
It is clear that the sample there is large difference between the sample and the population means in the average population, and the sample there is no large difference between the sample and the population mean in the pupils per teacher.
Want to see more full solutions like this?
Chapter 14 Solutions
Elementary Statistics: A Step By Step Approach
- An electronics company manufactures batches of n circuit boards. Before a batch is approved for shipment, m boards are randomly selected from the batch and tested. The batch is rejected if more than d boards in the sample are found to be faulty. a) A batch actually contains six faulty circuit boards. Find the probability that the batch is rejected when n = 20, m = 5, and d = 1. b) A batch actually contains nine faulty circuit boards. Find the probability that the batch is rejected when n = 30, m = 10, and d = 1.arrow_forwardTwenty-eight applicants interested in working for the Food Stamp program took an examination designed to measure their aptitude for social work. A stem-and-leaf plot of the 28 scores appears below, where the first column is the count per branch, the second column is the stem value, and the remaining digits are the leaves. a) List all the values. Count 1 Stems Leaves 4 6 1 4 6 567 9 3688 026799 9 8 145667788 7 9 1234788 b) Calculate the first quartile (Q1) and the third Quartile (Q3). c) Calculate the interquartile range. d) Construct a boxplot for this data.arrow_forwardPam, Rob and Sam get a cake that is one-third chocolate, one-third vanilla, and one-third strawberry as shown below. They wish to fairly divide the cake using the lone chooser method. Pam likes strawberry twice as much as chocolate or vanilla. Rob only likes chocolate. Sam, the chooser, likes vanilla and strawberry twice as much as chocolate. In the first division, Pam cuts the strawberry piece off and lets Rob choose his favorite piece. Based on that, Rob chooses the chocolate and vanilla parts. Note: All cuts made to the cake shown below are vertical.Which is a second division that Rob would make of his share of the cake?arrow_forward
- Three players (one divider and two choosers) are going to divide a cake fairly using the lone divider method. The divider cuts the cake into three slices (s1, s2, and s3). If the choosers' declarations are Chooser 1: {s1 , s2} and Chooser 2: {s2 , s3}. Using the lone-divider method, how many different fair divisions of this cake are possible?arrow_forwardTheorem 2.6 (The Minkowski inequality) Let p≥1. Suppose that X and Y are random variables, such that E|X|P <∞ and E|Y P <00. Then X+YpX+Yparrow_forwardTheorem 1.2 (1) Suppose that P(|X|≤b) = 1 for some b > 0, that EX = 0, and set Var X = 0². Then, for 0 0, P(X > x) ≤e-x+1²² P(|X|>x) ≤2e-1x+1²² (ii) Let X1, X2...., Xn be independent random variables with mean 0, suppose that P(X ≤b) = 1 for all k, and set oσ = Var X. Then, for x > 0. and 0x) ≤2 exp Σ k=1 (iii) If, in addition, X1, X2, X, are identically distributed, then P(S|x) ≤2 expl-tx+nt²o).arrow_forward
- Theorem 5.1 (Jensen's inequality) state without proof the Jensen's Ineg. Let X be a random variable, g a convex function, and suppose that X and g(X) are integrable. Then g(EX) < Eg(X).arrow_forwardCan social media mistakes hurt your chances of finding a job? According to a survey of 1,000 hiring managers across many different industries, 76% claim that they use social media sites to research prospective candidates for any job. Calculate the probabilities of the following events. (Round your answers to three decimal places.) answer parts a-c. a) Out of 30 job listings, at least 19 will conduct social media screening. b) Out of 30 job listings, fewer than 17 will conduct social media screening. c) Out of 30 job listings, exactly between 19 and 22 (including 19 and 22) will conduct social media screening. show all steps for probabilities please. answer parts a-c.arrow_forwardQuestion: we know that for rt. (x+ys s ا. 13. rs. and my so using this, show that it vye and EIXI, EIYO This : E (IX + Y) ≤2" (EIX (" + Ely!")arrow_forward
- Theorem 2.4 (The Hölder inequality) Let p+q=1. If E|X|P < ∞ and E|Y| < ∞, then . |EXY ≤ E|XY|||X|| ||||qarrow_forwardTheorem 7.6 (Etemadi's inequality) Let X1, X2, X, be independent random variables. Then, for all x > 0, P(max |S|>3x) ≤3 max P(S| > x). Isk≤narrow_forwardTheorem 7.2 Suppose that E X = 0 for all k, that Var X = 0} x) ≤ 2P(S>x 1≤k≤n S√2), -S√2). P(max Sk>x) ≤ 2P(|S|>x- 1arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
- MATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th...StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C...StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage Learning
- Elementary Statistics: Picturing the World (7th E...StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. Freeman





