BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)
10th Edition
ISBN: 9781305967359
Author: STARR
Publisher: CENGAGE L
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 14, Problem 9SA
Alleles for Tay-Sachs disease are inherited in an autosomal recessive pattern. Why would two parents with a normal
a. Both parents are homozygous for a Tay-Sachs allele. |
b. Both parents are heterozygous for a Tay-Sachs allele. |
c. New mutations gave rise to Tay-Sachs in the child. |
d. b or c |
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
If a genetic disease is inherited on the basis of an autosomal dominant gene, one would expect
to find which of the following?
A. Affected fathers have only affected children.
B. Affected mothers never have affected sons.
C. If both parents are affected, all of their offspring have the disease.
D. If a child has the disease, one of his or her grandparents also had the disease.
What is Mendelian inheritance?
a. Mendelian genes code an entire phenotype so that children will not be clones of their parents.
b. Mendelian genetics are those genes that code for dominant or recessive illnesses but only if no polygenic traits cancel them out.
c. Mendelian genes sit at one loci with one allele from Mom and one allele from Dad.
d. Mendelian genetics is when two or more genes at two or more loci express one trait
A is a dominant gene for normal pigment, and a is its recessive allele for albinism (and pink eyes). B is a dominant gene for brown eyes, and b is its recessive allele (blue). What is the mother's genotype if two brown-eyed parents have fraternal twins, one with blue eyes and one with pink eyes (albino)?
a. AaBb b. AaBB c. aaBb d. aabb e. AABB
Chapter 14 Solutions
BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)
Ch. 14 - Constructing a family pedigree is particularly...Ch. 14 - Prob. 2SACh. 14 - Prob. 3SACh. 14 - Prob. 4SACh. 14 - Prob. 5SACh. 14 - A trait that is present in a male child but not in...Ch. 14 - Color blindness is a case of ________ inheritance....Ch. 14 - Prob. 8SACh. 14 - Alleles for Tay-Sachs disease are inherited in an...Ch. 14 - Prob. 10SA
Ch. 14 - Prob. 11SACh. 14 - Prob. 12SACh. 14 - Prob. 13SACh. 14 - Klinefelter syndrome XXY can be easily diagnosed...Ch. 14 - Match the chromosome terms appropriately. ___...Ch. 14 - Does the phenotype indicated by the red circles...Ch. 14 - Human females have two X chromosomes XX; males...Ch. 14 - Somatic cells of individuals with Down syndrome...Ch. 14 - An allele responsible for Marfan syndrome Section...Ch. 14 - Both Duchenne muscular dystrophy and color...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Both of Ruth's parents have a round face, a dominant trait. Ruth, however, was born with a square face. What does Ruth's phenotype imply about her parents' genes? a. Ruth's parents are both heterozygous when it comes to their facial shape. b. When it comes to facial shape, Ruth's parents gave her one dominant gene and one recessive gene. c. Ruth's parents are both homozygous when it comes to their facial shape. d. Ruth's sister also has a square face.arrow_forwardTwo albino parents have four unaffected children. If albinism in the parents is given by mutations on two different genes (A and B) and complementation is observed in all four children, what are the genotypes of the parents? A. AaBb and AABB B. AABb and AaBB C. both parents are AaBb D. AAbb and BBaaarrow_forwardWebbed fingers is inherited as an X-linked disease An unaffected male marries an affected female. a. Draw a Punnett square of the possible offspring. b. List the phenotypes of the possible children c. Draw a pedigree that displays the inheritance in you Punnett squarearrow_forward
- If a genetic disease is inherited as an autosomal recessive, one would expect to find which of the following? A. Two affected individuals never have an unaffected child. B. Two affected individuals have affected male offspring but no affected female children. C. If a child has the disease, one of his or her grandparents will have had it. D. In a marriage between an affected individual and an unaffected one, all the children are unaffected.arrow_forwardPolydactyly is a congenital physical anomaly in in humans, dogs, cats; and having supernumerary fingers or toes. If it is an autosomal dominant trait, when is a genotype of a person that shows normal phenotype? a. heterozygous recessive b. heterozygous dominant c. homozygous recessive d. homozygous dominantarrow_forwardThe condition phenylketonuria is caused by a recessive allele. There are two carriers who have progeny.a. Give the gene notation. b. Give the expected genotypic and phenotypic ratios. c. What is the probability that their child will be heterozygous if they have a normal child?d. What is the probability of having two affected children and one normal child if they have three children?arrow_forward
- Duchenne muscular dystrophy is sex linked and usually affects only males. Victims of the disease become progressively weaker, starting early in life.a. What is the probability that a woman whose brother has Duchenne’s disease will have an affected child?b. If your mother’s brother (your uncle) had Duchenne’s disease, what is the probability that you have received the allele?c. If your father’s brother had the disease, what is the probability that you have received the allele?arrow_forwardAlkaptonuria is a metabolic disorder in which affected people produce black urine. Alkaptonuria results from an allele (a) that is recessive to the allele for normal metabolism (A). Sally has normal metabolism, but her brother has alkaptonuria. Sally’s father has alkaptonuria, and her mother has normal metabolism. a. Give the genotypes of Sally, her mother, her father, and her brother.b. If Sally’s parents have another child, what is the probability that this child will have alkaptonuria?c. If Sally marries a man with alkaptonuria, what is the probability thattheir first child will have alkaptonuria?arrow_forwardA trait that is present in a male child but not in either of his parents is characteristic of inheritance. a. autosomal dominant b. autosomal recessive c. X-linked recessive d. It is impossible to answer this question without more informationarrow_forward
- Tay-Sach's disease is caused by one gene. The disease is recessive. Is it possible for two healthy people to have a child with the disease? A. Yes B. No Is it possible for two people who both have the disease to have a healthy child? A. Yes B. Noarrow_forwardIn a trait that follows Mendelian rules of inheritance, what is the only way an organism can have the recessive phenotype? A. By having the homozygous recessive genotype B. By being heterozygous for that genotype C. It is not possible to get the recessive phenotype in Mendelian genetics D. If one parent is homozygous recessive for that trait, any offspring are guaranteed the recessive phenotype E. By being homozygous dominant for that genotypearrow_forwardPlease choose the correct answer. If a recessive mutation kills an individual during the early stages of its development, what is the possible mode of inheritance exhibited if a recessive F1 with heterozygous parents survives? a. epigenetic inheritance b. maternal inheritance c. maternal effect d. organelle inheritancearrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
How to solve genetics probability problems; Author: Shomu's Biology;https://www.youtube.com/watch?v=R0yjfb1ooUs;License: Standard YouTube License, CC-BY
Beyond Mendelian Genetics: Complex Patterns of Inheritance; Author: Professor Dave Explains;https://www.youtube.com/watch?v=-EmvmBuK-B8;License: Standard YouTube License, CC-BY