a. Losing sequentiality: In B+ tree index or file organization, the leaf nodes loose sequentiality because of the following reasons: Here, even if the leaf nodes are adjoining each other in the tree, in the disk they may be located at different places...

Question

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Answer 1

Expert Solution & Answer

Chapter 14, Problem 9PE

Explanation of Solution

a.

Losing sequentiality:

In B+ tree index or file organization, the leaf nodes loose sequentiality because of the following reasons:

Here, even if the leaf nodes are adjoining each other in the tree, in the disk they may be located at different places...

Explanation of Solution

b.

i.

Worst-case occupancy:

Simply rebuilding the indices can help to restore this sequentiality in the file organization.

Consider the given alternative reorganization to restore this sequentiality.

Here, every n-block unit and every B+ tree’s node are half filled.

So, the worst-case occupancy will be 25%.

ii.

Allocating leaf nodes:

“No”, the given situation is not possible.

It is because of the following reasons:

Consider the scenario when the n-block unit splits;

One n-block unit will contain the first “n/2” leaf pages.

The second n-block unit will contain the remaining leaf pages.

So, each split in the n-block will preserve the order.

As a result, the nodes in each n-block unit will always be successive.

iii.

Numbers of seeks required:

First consider the case of a n-page block,

Here, while scanning the B+ tree, the leaf page might turn out to be non-sequential...

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Students have asked these similar questions

Design a dynamic programming algorithm for the Coin-change problem described below: Input: An amount of money C and a set of n possible coin values with an unlimited supply of each kind of coin. Output: The smallest number of coins that add up to C exactly, or output that no such set exists. The algorithm must take O(n C) time. You must also write and explain the recurrence. Example 1: Input: C24, Coin values = = [1, 5, 10, 25, 50] Output: 6 (since 24 = 10+ 10+1+1 +1 + 1) Example 2: Input: C = 86, Coin values = [1, 5, 6, 23, 35, 46, 50] Output: 2 (since 86 = 46+35+5)

Design a dynamic programming algorithm for the Longest Common Subsequence problem de- scribed below Input: Two strings x = x1x2 xm and y = Y1Y2... Yn Output: The length of the longest subsequence that is common to both x and y. . The algorithm must take O(m n) time. You must also write and explain the recurrence. (I want the largest k such that there are 1 ≤ i₁ < ... < ik ≤ m and 1 ≤ j₁ < ... < jk ≤ n such that Xi₁ Xi2 Xik = Yj1Yj2 ··· Yjk) Example 1: Input: x = 'abcdefghijklmnopqrst' and y = 'ygrhnodsh ftw' Output: 6 ('ghnost' is the longest common subsequence to both strings) Example 2: Input: x = 'ahshku' and y = ‘asu' Output: 3 ('asu' is the longest common subsequence to both strings)

Design a dynamic programming algorithm for the problem described below Input: A list of numbers A = = [a1,..., an]. Output: A contiguous subsequence of numbers with the maximum sum. The algorithm must take O(n) time. You must also write and explain the recurrence. (I am looking for an i ≥ 1 and k ≥ 0 such that a + ai+1 + ···ai+k has the largest possible sum among all possible values for i and k.) Example 1: Input: A[5, 15, -30, 10, -5, 40, 10]. Output: [10, 5, 40, 10] Example 2: Input: A = [7, 5, 7, 4, -20, 6, 9, 3, -4, -8, 4] Output: [6,9,3]

Answer 2

Expert Solution & Answer

Chapter 14, Problem 9PE

Explanation of Solution

a.

Losing sequentiality:

In B+ tree index or file organization, the leaf nodes loose sequentiality because of the following reasons:

Here, even if the leaf nodes are adjoining each other in the tree, in the disk they may be located at different places...

Explanation of Solution

b.

i.

Worst-case occupancy:

Simply rebuilding the indices can help to restore this sequentiality in the file organization.

Consider the given alternative reorganization to restore this sequentiality.

Here, every n-block unit and every B+ tree’s node are half filled.

So, the worst-case occupancy will be 25%.

ii.

Allocating leaf nodes:

“No”, the given situation is not possible.

It is because of the following reasons:

Consider the scenario when the n-block unit splits;

One n-block unit will contain the first “n/2” leaf pages.

The second n-block unit will contain the remaining leaf pages.

So, each split in the n-block will preserve the order.

As a result, the nodes in each n-block unit will always be successive.

iii.

Numbers of seeks required:

First consider the case of a n-page block,

Here, while scanning the B+ tree, the leaf page might turn out to be non-sequential...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Expert Solution & Answer

Chapter 14, Problem 9PE

Explanation of Solution

a.

Losing sequentiality:

In B+ tree index or file organization, the leaf nodes loose sequentiality because of the following reasons:

Here, even if the leaf nodes are adjoining each other in the tree, in the disk they may be located at different places...

Explanation of Solution

b.

i.

Worst-case occupancy:

Simply rebuilding the indices can help to restore this sequentiality in the file organization.

Consider the given alternative reorganization to restore this sequentiality.

Here, every n-block unit and every B+ tree’s node are half filled.

So, the worst-case occupancy will be 25%.

ii.

Allocating leaf nodes:

“No”, the given situation is not possible.

It is because of the following reasons:

Consider the scenario when the n-block unit splits;

One n-block unit will contain the first “n/2” leaf pages.

The second n-block unit will contain the remaining leaf pages.

So, each split in the n-block will preserve the order.

As a result, the nodes in each n-block unit will always be successive.

iii.

Numbers of seeks required:

First consider the case of a n-page block,

Here, while scanning the B+ tree, the leaf page might turn out to be non-sequential...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Expert Solution & Answer

Chapter 14, Problem 9PE

Explanation of Solution

a.

Losing sequentiality:

In B+ tree index or file organization, the leaf nodes loose sequentiality because of the following reasons:

Here, even if the leaf nodes are adjoining each other in the tree, in the disk they may be located at different places...

Explanation of Solution

b.

i.

Worst-case occupancy:

Simply rebuilding the indices can help to restore this sequentiality in the file organization.

Consider the given alternative reorganization to restore this sequentiality.

Here, every n-block unit and every B+ tree’s node are half filled.

So, the worst-case occupancy will be 25%.

ii.

Allocating leaf nodes:

“No”, the given situation is not possible.

It is because of the following reasons:

Consider the scenario when the n-block unit splits;

One n-block unit will contain the first “n/2” leaf pages.

The second n-block unit will contain the remaining leaf pages.

So, each split in the n-block will preserve the order.

As a result, the nodes in each n-block unit will always be successive.

iii.

Numbers of seeks required:

First consider the case of a n-page block,

Here, while scanning the B+ tree, the leaf page might turn out to be non-sequential...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 14, Problem 9PE

Explanation of Solution

a.

Losing sequentiality:

In B+ tree index or file organization, the leaf nodes loose sequentiality because of the following reasons:

Here, even if the leaf nodes are adjoining each other in the tree, in the disk they may be located at different places...

Explanation of Solution

b.

i.

Worst-case occupancy:

Simply rebuilding the indices can help to restore this sequentiality in the file organization.

Consider the given alternative reorganization to restore this sequentiality.

Here, every n-block unit and every B+ tree’s node are half filled.

So, the worst-case occupancy will be 25%.

ii.

Allocating leaf nodes:

“No”, the given situation is not possible.

It is because of the following reasons:

Consider the scenario when the n-block unit splits;

One n-block unit will contain the first “n/2” leaf pages.

The second n-block unit will contain the remaining leaf pages.

So, each split in the n-block will preserve the order.

As a result, the nodes in each n-block unit will always be successive.

iii.

Numbers of seeks required:

First consider the case of a n-page block,

Here, while scanning the B+ tree, the leaf page might turn out to be non-sequential...

Answer 8

Chapter 14, Problem 9PE

Explanation of Solution

a.

Losing sequentiality:

In B+ tree index or file organization, the leaf nodes loose sequentiality because of the following reasons:

Here, even if the leaf nodes are adjoining each other in the tree, in the disk they may be located at different places...

Answer 9

Chapter 14, Problem 9PE

Explanation of Solution

a.

Losing sequentiality:

In B+ tree index or file organization, the leaf nodes loose sequentiality because of the following reasons:

Here, even if the leaf nodes are adjoining each other in the tree, in the disk they may be located at different places...

Answer 10

Explanation of Solution

b.

i.

Worst-case occupancy:

Simply rebuilding the indices can help to restore this sequentiality in the file organization.

Consider the given alternative reorganization to restore this sequentiality.

Here, every n-block unit and every B+ tree’s node are half filled.

So, the worst-case occupancy will be 25%.

ii.

Allocating leaf nodes:

“No”, the given situation is not possible.

It is because of the following reasons:

Consider the scenario when the n-block unit splits;

One n-block unit will contain the first “n/2” leaf pages.

The second n-block unit will contain the remaining leaf pages.

So, each split in the n-block will preserve the order.

As a result, the nodes in each n-block unit will always be successive.

iii.

Numbers of seeks required:

First consider the case of a n-page block,

Here, while scanning the B+ tree, the leaf page might turn out to be non-sequential...

Answer 11

Explanation of Solution

b.

i.

Worst-case occupancy:

Simply rebuilding the indices can help to restore this sequentiality in the file organization.

Consider the given alternative reorganization to restore this sequentiality.

Here, every n-block unit and every B+ tree’s node are half filled.

So, the worst-case occupancy will be 25%.

ii.

Allocating leaf nodes:

“No”, the given situation is not possible.

It is because of the following reasons:

Consider the scenario when the n-block unit splits;

One n-block unit will contain the first “n/2” leaf pages.

The second n-block unit will contain the remaining leaf pages.

So, each split in the n-block will preserve the order.

As a result, the nodes in each n-block unit will always be successive.

iii.

Numbers of seeks required:

First consider the case of a n-page block,

Here, while scanning the B+ tree, the leaf page might turn out to be non-sequential...

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

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Check out a sample textbook solution

See solution

Answer 15

Ch. 14 - Prob. 1PE Ch. 14 - Prob. 2PE Ch. 14 - Prob. 3PE Ch. 14 - Prob. 4PE Ch. 14 - Prob. 5PE Ch. 14 - Prob. 7PE Ch. 14 - Prob. 8PE Ch. 14 - Prob. 9PE Ch. 14 - Prob. 10PE Ch. 14 - Prob. 11PE

a. Losing sequentiality: In B+ tree index or file organization, the leaf nodes loose sequentiality because of the following reasons: Here, even if the leaf nodes are adjoining each other in the tree, in the disk they may be located at different places...

Explanation of Solution

a. Losing sequentiality: In B+ tree index or file organization, the leaf nodes loose sequentiality because of the following reasons: Here, even if the leaf nodes are adjoining each other in the tree, in the disk they may be located at different places...

Explanation of Solution

Want to see the full answer?

Chapter 14 Solutions

a.

Losing sequentiality:

In B+ tree index or file organization, the leaf nodes loose sequentiality because of the following reasons:

Here, even if the leaf nodes are adjoining each other in the tree, in the disk they may be located at different places...