Explanation Given: Volume of the vessel is 2 .75 L . Temperature is 950 K . Equilibrium constant K p is 0.355 . Initial moles of SO 2 is 0 .100 mol . Initial moles of O 2 is 0 .100 mol . Explanation: Calculate the initial pressure of SO 2 by using the ideal gas equation as follows: P SO 2 = n SO 2 × R × T V = ( 0.100 mol ) × ( 0.082057 L atm mol − 1 K − 1 ) × 950 K 2.75 L = 2.83 atm For O 2 , number of moles, temperature, and volume are same. Therefore, its initial pressure will also be 2.83 atm . For the given reaction: 2SO 2 ( g ) + O 2 ( g ) ⇌ 2 SO 3 ( g ) Let x atm of O 2 reacts to reach the equilibrium. Construct the ICE table as follows: P SO 2 P O 2 P SO 3 Initial pressure ( atm ) 2.83 2.83 0 Change ( atm ) − 2 x − x + 2 x Equilibrium partial pressure ( atm ) 2.83 − 2 x 2

Chemistry: A Molecular Approach & Student Solutions Manual for Chemistry: A Molecular Approach, Books a la Carte Edition Package

1st Edition

ISBN: 9780321955517

Author: Nivaldo J. Tro

Publisher: PEARSON

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Chapter 14, Problem 94E

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To determine: The total pressure at equilibrium.

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Chapter 14, Problem 93E

Chapter 14, Problem 95E

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Chemistry: A Molecular Approach & Student Solutions Manual for Chemistry: A Molecular Approach, Books a la Carte Edition Package

Ch. 14 - Prob. 1SAQ Ch. 14 - Q2. The equilibrium constant for the reaction...Ch. 14 - Q3. Use the data shown here to find the...Ch. 14 - Prob. 4SAQ Ch. 14 - Prob. 5SAQ Ch. 14 - Q6. For the reaction 2 A(g) B(g), the equilibrium...Ch. 14 - Q7. Consider the reaction between iodine gas and...Ch. 14 - Prob. 8SAQ Ch. 14 - Prob. 9SAQ Ch. 14 - Prob. 10SAQ

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