For each of the given solution, the pH of the solution is to be determined from the given pOH values and based on the pH value, each solution is to be classified as acidic, basic or neutral. Concept introduction: The sum of pH and pOH in a solution is always equals to 14 at a constant temperature. At 25 ° C , mathematically it can be shown as follows: pH + pOH = 14 .0 The pH scale is used to classify whether the solution is acidic or basic. The three points for the solution are as follows: The solution with pH value less than 7 is acidic. The solution with pH value greater than 7 is basic. If the solution with pH equals to 7 is neutral.
For each of the given solution, the pH of the solution is to be determined from the given pOH values and based on the pH value, each solution is to be classified as acidic, basic or neutral. Concept introduction: The sum of pH and pOH in a solution is always equals to 14 at a constant temperature. At 25 ° C , mathematically it can be shown as follows: pH + pOH = 14 .0 The pH scale is used to classify whether the solution is acidic or basic. The three points for the solution are as follows: The solution with pH value less than 7 is acidic. The solution with pH value greater than 7 is basic. If the solution with pH equals to 7 is neutral.
Solution Summary: The author explains how the pH scale is used to classify whether the solution is acidic, basic or neutral.
For each of the given solution, the pH of the solution is to be determined from the given pOH values and based on the pH value, each solution is to be classified as acidic, basic or neutral.
Concept introduction:
The sum of pH and pOH in a solution is always equals to 14 at a constant temperature. At 25°C, mathematically it can be shown as follows:
pH+pOH=14.0
The pH scale is used to classify whether the solution is acidic or basic. The three points for the solution are as follows:
The solution with pH value less than 7 is acidic.
The solution with pH value greater than 7 is basic.
The initial rates method can be used to
determine the rate law for a reaction.
using the data for the reaction below, what is
the rate law for reaction?
A+B-C
-
ALA]
At
(mot
Trial [A] (mol)
(MD
2
1
0.075
[B](
0.075
mo
LS
01350
2
0.075
0.090 0.1944
3
0.090 0.075
0.1350
Report value of k with two significant Figure
Compare trials 1 and 2 where [B] is
constant.
The rate law can be written as: rate
= k[A][B]".
rate2
0.090
= 9.
rate1
0.010
[A]m
6.0m
= 3m
[A] m
2.0m
Can you please explain this problem to me and expand it so I can understand the full Lewis dot structure? Thanks!
Chapter 14 Solutions
Mastering Chemistry with Pearson eText -- Standalone Access Card -- for Introductory Chemistry (6th Edition)
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