INDUSTRIAL MOTOR CONTROL
7th Edition
ISBN: 9780357670590
Author: Herman
Publisher: CENGAGE L
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Chapter 14, Problem 7RQ
To determine
Thermopile.
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in this scenario, when it comes to matrix iterations it states this system is assumed out of phase. why is this?
Q1. A curved beam of a circular cross section of diameter "d" is fixed at one end and
subjected to a concentrated load P at the free end (Fig. 1). Calculate stresses at points
A and C. Given: P = 800 N, d = 30 mm, a 25 mm, and b = 15 mm.
Fig.1
P
b
B
(10 Marks)
You are working as an engineer in a bearing systems design company. The flow of
lubricant inside a hydrodynamic bearing (p = 0.001 kg m-1 s-1) can be approximated
as a parallel, steady, two-dimensional, incompressible flow between two parallel plates.
The top plate, representing the moving part of the bearing, travels at a constant speed,
U, while the bottom plate remains stationary (Figure Q1). The plates are separated by
a distance of 2h = 1 cm and are W = 20 cm wide. Their length is L = 10 cm. By
applying the above approximations to the Navier-Stokes equations and assuming that
end effects can be neglected, the horizontal velocity profile can be shown to be
y = +h
I
2h = 1 cm
x1
y = -h
u(y)
1 dP
2μ dx
-y² + Ay + B
moving plate
stationary plate
U
2
I2
L = 10 cm
Figure Q1: Flow in a hydrodynamic bearing. The plates extend a width, W = 20 cm,
into the page.
Chapter 14 Solutions
INDUSTRIAL MOTOR CONTROL
Ch. 14 - Should a metal bar be heated or cooled to make it...Ch. 14 - Prob. 2RQCh. 14 - Prob. 3RQCh. 14 - Why are bimetal strips often formed into a spiral...Ch. 14 - Why should electrical contacts never be permitted...Ch. 14 - What two factors determine the amount of voltage...Ch. 14 - Prob. 7RQCh. 14 - Prob. 8RQCh. 14 - Prob. 9RQCh. 14 - Prob. 10RQ
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- You are working as an engineer in a bearing systems design company. The flow of lubricant inside a hydrodynamic bearing (µ = 0.001 kg m¯¹ s¯¹) can be approximated as a parallel, steady, two-dimensional, incompressible flow between two parallel plates. The top plate, representing the moving part of the bearing, travels at a constant speed, U, while the bottom plate remains stationary (Figure Q1). The plates are separated by a distance of 2h = 1 cm and are W = 20 cm wide. Their length is L = 10 cm. By applying the above approximations to the Navier-Stokes equations and assuming that end effects can be neglected, the horizontal velocity profile can be shown to be U y = +h У 2h = 1 cm 1 x1 y=-h u(y) = 1 dP 2μ dx -y² + Ay + B moving plate - U stationary plate 2 I2 L = 10 cm Figure Q1: Flow in a hydrodynamic bearing. The plates extend a width, W = 20 cm, into the page. (a) By considering the appropriate boundary conditions, show that the constants take the following forms: A = U 2h U 1 dP…arrow_forwardQuestion 2 You are an engineer working in the propulsion team for a supersonic civil transport aircraft driven by a turbojet engine, where you have oversight of the design for the engine intake and the exhaust nozzle, indicated in Figure Q2a. The turbojet engine can operate when provided with air flow in the Mach number range, 0.60 to 0.80. You are asked to analyse a condition where the aircraft is flying at 472 m/s at an altitude of 14,000 m. For all parts of the question, you can assume that the flow path of air through the engine has a circular cross section. (a) normal shock 472 m/s A B (b) intake engine altitude: 14,000 m D exhaust nozzle→ exit to atmosphere 472 m/s 50 m/s B diameter: DE = 0.30 m EX diameter: DF = 0.66 m Figure Q2: Propulsion system for a supersonic aircraft. F a) When the aircraft is at an altitude of 14,000 m, use the International Standard Atmosphere in the Module Data Book to state the local air pressure and tempera- ture. Thus show that the aircraft speed of…arrow_forwardgiven below: A rectangular wing with wing twist yields the spanwise circulation distribution kbV1 roy) = kbv. (2) where k is a constant, b is the span length and V. is the free-stream velocity. The wing has an aspect ratio of 4. For all wing sections, the lift curve slope (ag) is 2 and the zero-lift angle of attack (a=0) is 0. a. Derive expressions for the downwash (w) and induced angle of attack a distributions along the span. b. Derive an expression for the induced drag coefficient. c. Calculate the span efficiency factor. d. Calculate the value of k if the wing has a washout and the difference between the geometric angles of attack of the root (y = 0) and the tip (y = tb/2) is: a(y = 0) a(y = ±b/2) = /18 Hint: Use the coordinate transformation y = cos (0)arrow_forward
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