Explanation Given The reaction follows the following data: Temperature (K) k ( M − 1 s − 1 ) 600 0.028 650 0.22 700 1.3 750 6.0 800 23 According to Arrhenius equation, k = A e − E a R T ln k = − E a R T + ln A …... (1) Where, k is the rate constant of the reaction. A is the frequency factor. E a is the activation energy. R is the gas constant. T is the temperature. Equation (1) is an equation of straight line. Calculate the value of 1 T and ln k for the given data. T ( K ) 1 T ( K − 1 ) k ( M − 1 s − 1 ) ln k 600 1.667 × 10 − 3 0.028 − 3.576 650 1.538 × 10 − 3 0.22 − 1

14th Edition

ISBN: 9780134562230

Author: Brown

Publisher: PEARSON

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Chapter 14, Problem 64E

Interpretation Introduction

To determine: The activation energy and the frequency factor of the given reaction.

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Chapter 14, Problem 63E

Chapter 14, Problem 65E

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Chapter 14 Solutions

CHEMISTRY: THE CENTRAL SCIENCE

Ch. 14.2 - If the experiment in Figure 14.2 is run for 60 s,...Ch. 14.2 - Prob. 14.1.2PE Ch. 14.2 - Which of the following could be the instantaneous...Ch. 14.2 - Using Figure 14.3, determine the instantaneous...Ch. 14.2 - At a certain time in a reaction, substance A is...Ch. 14.2 - Prob. 14.3.2PE Ch. 14.3 - Suppose the rate law for the reaction in this...Ch. 14.3 - Assuming that rate = k[A][B], rank the mixtures...Ch. 14.3 - Prob. 14.5.1PE Ch. 14.3 - Prob. 14.5.2PE

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