OTHER APPLICATIONS Stopping Distance According to data from the National Traffic Safety Institute, the stopping distance y in feet of a car traveling x mph can be described by the equation y = 0.056057 x 2 + 1.06657 x . Source: National Traffic Safety Institute. a. Find the stopping distance for a car travelling 25 mph . b. How fast can you drive if you need to be certain of stopping within 150 ft ?
OTHER APPLICATIONS Stopping Distance According to data from the National Traffic Safety Institute, the stopping distance y in feet of a car traveling x mph can be described by the equation y = 0.056057 x 2 + 1.06657 x . Source: National Traffic Safety Institute. a. Find the stopping distance for a car travelling 25 mph . b. How fast can you drive if you need to be certain of stopping within 150 ft ?
Solution Summary: The author calculates the stopping distance in feet of a car traveling with the speed of 25mph.
Stopping Distance According to data from the National Traffic Safety Institute, the stopping distance
y
in feet of a car traveling
x
mph
can be described by the equation
y
=
0.056057
x
2
+
1.06657
x
. Source: National Traffic Safety Institute.
a. Find the stopping distance for a car travelling
25
mph
.
b. How fast can you drive if you need to be certain of stopping within
150
ft
?
Use Euler's method to numerically integrate
dy
dx
-2x+12x² - 20x +8.5
from x=0 to x=4 with a step size of 0.5. The initial condition at x=0 is y=1. Recall
that the exact solution is given by y = -0.5x+4x³- 10x² + 8.5x+1
Find an equation of the line tangent to the graph of f(x) = (5x-9)(x+4) at (2,6).
Find the point on the graph of the given function at which the slope of the tangent line is the given slope.
2
f(x)=8x²+4x-7; slope of the tangent line = -3
Chapter 1 Solutions
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