Explanation Given information: sin 2 x cos 2 x Formula used: cos 2 θ = 2 cos 2 θ − 1 Calculation: Derive that sin 2 x cos 2 x = 1 − cos 4 x 8 Now let us start with 1 − cos 4 x 8 = 1 − ( 2 cos 2 2 x − 1 ) 8 ( Use cos 2 θ = 2 cos 2 θ − 1 ) = 1 − 2 cos 2 2 x + 1 8 = 2 − 2 cos 2 2 x 8 ( again cos 2 θ = 2 cos 2 θ − 1 ) = 2 − 2 (

4th Edition

ISBN: 9781319309671

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 1.4, Problem 56E

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To erive the identity sin2xcos2x=1−cos4x8.

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Chapter 1.4, Problem 55E

Chapter 1.4, Problem 57E

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Chapter 1 Solutions

CALCULUS: EARLY TRANS 4TH ED W/ ACCESS

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To erive the identity sin 2 x cos 2 x = 1 − cos 4 x 8 .

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To erive the identity sin2xcos2x=1−cos4x8.

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