Chapter 1.4, Problem 51PPS

To determine

To simplify the expression:

  $6\left(2c-c{d}^2+d\right)$

Using the distributive property.

Answer to Problem 51PPS

  $6\left(2c-c{d}^2+d\right)=12c-6c{d}^2+6d$

Explanation of Solution

Given:

  $6\left(2c-c{d}^2+d\right)$

Concept Used:

Distributive property:

  $a\left(b\pm c\pm d\right)=ab\pm ac\pm ad$

Calculation:

In order tosimplify the expression $6\left(2c-c{d}^2+d\right)$

Use the distributive property which is:

  $a\left(b\pm c\pm d\right)=ab\pm ac\pm ad$

As,

  $\begin{array}{c}6\left(2c-c{d}^2+d\right)=6\times 2c-6\times c{d}^2+6d\\ =12c-6c{d}^2+6d\end{array}$

Thus, simplified form of given expression is:

  $6\left(2c-c{d}^2+d\right)=12c-6c{d}^2+6d$