(a) Explanation Given The hypothetical aqueous reaction is, A ( a q ) → B ( a q ) The number of moles of A in the reaction is 0.065 mol . (refer exercise 14.19) The volume of water in the given reaction is 100 mL . The reaction follows the following data: S .No . Time ( min ) Moles of A 1. 0 0.065 2. 10 0.051 3. 20 0.042 4. 30 0.036 5. 40 0.031 The conversion of volume from mL into L is done as, 1 mL = 10 − 3 L Hence, the conversion of volume from 100 mL into L is, 100 mL = 100 × 10 − 3 L = 0.100 L The concentration of A in the given reaction is calculated by using the formula, M = n V …… (1) Where, M is the molarity of the solution. n is the number of moles of solute. V is the volume of solution in liters. Substitute the values of n and V from data 1 in equation (1). M 1 = 0.065 mol 0.1 L = 0.65 M Substitute the values of n and V from data 2 in equation (1). M 2 = 0.051 mol 0.1 L = 0.51 M Substitute the values of n and V from data 3 in equation (1). M 3 = 0.042 mol 0.1 L = 0.42 M Substitute the values of n and V from data 4 in equation (1). M 4 = 0.036 mol 0.1 L = 0.36 M Substitute the values of n and V from data 5 in equation (1). M 5 = 0.031 mol 0.1 L = 0.31 M The integrated rate equation of first order reaction is, ln [ A ] t = − k t + ln [ A ] 0 Where, [ A ] t is the concentration of the reactant A at time t (b) Interpretation Introduction To determine: The rate constant for the given reaction. (c) Interpretation Introduction To determine: The half life of the given second order reaction

14th Edition

ISBN: 9780134809694

Author: Brown

Publisher: PEARSON

See similar textbooks

Videos

Question

Chapter 14, Problem 47E

(a)

Interpretation Introduction

To determine: The order of the given reaction by using appropriate graphs.

(b)

Interpretation Introduction

To determine: The rate constant for the given reaction.

(c)

Interpretation Introduction

To determine: The half life of the given second order reaction

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 14, Problem 46E

Chapter 14, Problem 48E

Students have asked these similar questions

✓ edict the products of this organic reaction: ---- ။ A CH3–C−NH–CH2–C−CH3 + KOH ? Specifically, in the drawing area below draw the condensed structure of the product, or products, of this reaction. If there's more than one product, draw them in any arrangement you like, so long as they aren't touching. If there aren't any products because this reaction won't happen, check the No reaction box under the drawing area. Explanation Check Click anywhere to draw the first atom of your structure. C 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibili

Predict the product of this organic reaction: A HO-C-CH3 + CH3NH2 P+ H2O Specifically, in the drawing area below draw the condensed structure of P. If there is no reasonable possibility for P, check the No answer box under the drawing area. Explanation Check Click anywhere to draw the first atom of your structure. m

H 1) OsO4, pyridine 2) Na2SO3 or NaHSO3 in H₂O 2 products

Chapter 14 Solutions

CHEMISTRY:CENTRAL SCIENCE-W/MOD.ACCESS

Ch. 14.2 - If the experiment in Figure 14.2 is run for 60 s,...Ch. 14.2 - Prob. 14.1.2PE Ch. 14.2 - Which of the following could be the instantaneous...Ch. 14.2 - Using Figure 14.3, determine the instantaneous...Ch. 14.2 - At a certain time in a reaction, substance A is...Ch. 14.2 - Prob. 14.3.2PE Ch. 14.3 - Suppose the rate law for the reaction in this...Ch. 14.3 - Assuming that rate = k[A][B], rank the mixtures...Ch. 14.3 - Prob. 14.5.1PE Ch. 14.3 - Prob. 14.5.2PE

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.