Interpretation Introduction To determine: The equilibrium constant ( K c ) for the given reaction. Explanation Given: Concentration of [ FeSCN 2 + ] at equilibrium is 1.7 × 10 − 4 M . Initial concentration of ferric ions [ Fe 3 + ] is 1.0 × 10 − 3 M . Initial concentration of thiocyanate ions [ SCN − ] is 8.0 × 10 − 4 M . Explanation: Consider the reaction as follows: Fe 3 + ( aq ) + SCN − ( aq ) ⇌ FeSCN 2 + ( aq ) The equilibrium constant is expressed as follows: K c = [ FeSCN 2+ ] [ SCN − ] [ Fe 3 + ] Let x M of ferric iron react with thiocyanate ion to form x M of FeSCN 2 + . Construct the ICE table for the above reaction: Concentration Fe 3+ ( aq ) SCN − ( aq ) FeSCN 2 + ( aq ) Initial ( M ) 1.0 × 10 − 3 M 8.0 × 10 − 4 M 0 Change ( M ) − x − x + x Equilibrium ( M ) ( 1.0 × 10 − 3 − x ) M ( 8.0 × 10 − 4 − x ) M x At equilibrium, concentration of [ FeSCN 2 + ] is 1

Masteringchemistry With Pearson Etext -- Valuepack Access Card -- For Principles Of Chemistry: A Molecular Approach

3rd Edition

ISBN: 9780133890686

Author: Tro

Publisher: PEARSON

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Chapter 14, Problem 43E

Interpretation Introduction

To determine: The equilibrium constant (Kc) for the given reaction.

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Chapter 14, Problem 42E

Chapter 14, Problem 44E

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Chapter 14 Solutions

Masteringchemistry With Pearson Etext -- Valuepack Access Card -- For Principles Of Chemistry: A Molecular Approach

Ch. 14 - Prob. 1SAQ Ch. 14 - Q2. The equilibrium constant for the reaction...Ch. 14 - Q3. Use the data shown here to find the...Ch. 14 - Prob. 4SAQ Ch. 14 - Prob. 5SAQ Ch. 14 - Q6. For the reaction 2 A(g) B(g), the equilibrium...Ch. 14 - Q7. Consider the reaction between iodine gas and...Ch. 14 - Prob. 8SAQ Ch. 14 - Prob. 9SAQ Ch. 14 - Prob. 10SAQ

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