The Physics of Everyday Phenomena
The Physics of Everyday Phenomena
8th Edition
ISBN: 9780073513904
Author: W. Thomas Griffith, Juliet Brosing Professor
Publisher: McGraw-Hill Education
Question
Book Icon
Chapter 14, Problem 3SP

(a)

To determine

The area bounded by the rectangular coil.

(a)

Expert Solution
Check Mark

Answer to Problem 3SP

The area bounded by the rectangular coil is 0.0018m2.

Explanation of Solution

Given info: The length of rectangular coil is 6cm and breadth of coil is 3cm.

The coil provided is rectangular in shape. Therefore area of coil is found by multiplying the breadth and length.

Write the equation to find the area of a rectangular loop.

A=lb

Here,

A is the area of the rectangular coil

l is the length of the rectangular coil

b is the breadth of the rectangular coil

Substitute 6cm for l and 3cm for b in the equation to get A.

A=6cm(1m100cm)×3cm(1m100cm)=0.0018m2

Conclusion:

Therefore, the area of the rectangular coil is 0.0018m2.

(b)

To determine

The maximum value of magnetic flux passing through the rectangular coil as it is turned.

(b)

Expert Solution
Check Mark

Answer to Problem 3SP

The maximum value of magnetic flux that is passing through the rectangular coil is 0.043Tm2.

Explanation of Solution

Given info: Magnetic field applied is 0.4T , area of rectangular coil is 0.0018m2 , number of turns in the rectangular coil is 60.

Write the equation to find the magnetic flux passing through an area.

ϕ=NBAcosθ

Here,

ϕ is the magnetic flux passing through the rectangular coil

N is the number of turns in the rectangular coil

B is the magnetic field intensity applied

A is the area of the rectangular coil

θ is the angle between the rectangular coil and the magnetic field

Maximum value of magnetic flux passes through the coil when the magnetic field and the rectangular coil are parallel to each other. Therefore the angle between rectangular coil and magnetic field θ is 0°.

Substitute 60 for N , 0.4T for B , 0.0018m2 for A ,and 0° for θ in the equation to get ϕ.

ϕ=60×0.4T×0.0018m2cos0°=0.0432Tm2

Conclusion:

Therefore, the maximum value of magnetic flux that passes through the rectangular coil is 0.043Tm2.

(c)

To determine

The minimum value of flux that passes through the rectangular coil as it is rotated.

(c)

Expert Solution
Check Mark

Answer to Problem 3SP

The minimum value of magnetic flux that passes through the rectangular coil is zero.

Explanation of Solution

Given info: Magnetic field applied is 0.4T , area of rectangular coil is 0.0018m2 , number of turns in the rectangular coil is 60.

Write the equation to find the magnetic flux passing through an area.

ϕ=NBAcosθ

Here,

ϕ is the magnetic flux passing through the rectangular coil

N is the number of turns in the rectangular coil

B is the magnetic field intensity applied

A is the area of the rectangular coil

θ is the angle between the rectangular coil and the magnetic field

Minimum value of magnetic flux passes through the coil when the magnetic field and the rectangular coil are perpendicular to each other. Therefore the angle between rectangular coil and magnetic field θ is 90°.

Substitute 60 for N , 0.4T for B , 0.0018m2 for A ,and 90° for θ in the equation to get ϕ.

ϕ=60×0.4T×0.0018m2cos90°=0Tm2

Conclusion:

Therefore, the minimum value of magnetic flux that passes through the rectangular coil is zero.

(d)

To determine

The time taken to change the flux from a maximum to minimum in a complete cycle.

(d)

Expert Solution
Check Mark

Answer to Problem 3SP

The time taken for a change from maximum flux to minimum flux is 0.25s.

Explanation of Solution

A complete turn of the rectangular coil takes one second. A complete turn means a 360° turn of the rectangular coil. During a complete turn the coil experiences three maximum and two minimums.

The first change from maximum to minimum flux occurs between the 0° to 90° change. Therefore a change from maximum to minimum flux occurs during every 90° rotation. In a complete cycle there are four 90° changes. Therefore the time required for one of such change is found by dividing the time taken by a complete rotation into four rotations.

Time for one complete rotation is 1sec. Therefore time for a change from a maximum flux to minimum flux is 0.25sec

Conclusion:

Therefore, the time taken for a change from maximum flux to a minimum flux is 0.25sec.

(e)

To determine

Maximum value of voltage developed in the coil when the flux changes from a maximum to a minimum.

(e)

Expert Solution
Check Mark

Answer to Problem 3SP

The maximum value of voltage developed when the flux changes from maximum value to minimum value is 0.1728V.

Explanation of Solution

Write the equation to find the voltage developed when magnetic flux changes from maximum value to minimum value.

=dϕdt

Here,

is the voltage developed in the rectangular coil

dϕ is the change in flux from a maximum to a minimum

dt is the time taken for the change in value of flux

dϕ is the difference between the maximum flux value and minimum flux value.

dϕ=0.043Tm20Tm2=0.043Tm2

dt is the time taken for a change between a maximum flux to a minimum flux value which is equal to 0.25s.

Substitute 0.043Tm2 for dϕ , 0.25s for dt in the equation to find .

=0.043Tm20.25s=0.1728V

Conclusion:

Therefore, the maximum value of voltage induced when flux changes from a maximum value to a minimum value is 0.1728V.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Consider a image that is located 30 cm in front of a lens. It forms an upright image 7.5 cm from the lens. Theillumination is so bright that that a faint inverted image, due to reflection off the front of the lens, is observedat 6.0 cm on the incident side of the lens. The lens is then turned around. Then it is observed that the faint,inverted image is now 10 cm on the incident side of the lens.What is the index of refraction of the lens?
2. In class, we discussed several different flow scenarios for which we can make enough assumptions to simplify the Navier-Stokes equations enough to solve them and obtain an exact solution. Consulting the cylindrical form of the Navier-Stokes equations copied below, please answer the following questions. др a 1 a + +0x- + +O₂ = Pgr + μl 18²v, 2 ave ²v₁] az2 + at or r de r Əz dr ar Vodvz др [18 + + +Or + +Vz = Pgz +fl at ar r 20 ôz ôz dr ave дов V,Ve ave +Or + + = pge at dr r 80 Əz + az2 a.) In class, we discussed how the Navier-Stokes equations are an embodiment of Newton's 2nd law, F = ma (where bolded terms are vectors). Name the 3 forces that we are considering in our analysis of fluid flow for this class. др a 10 1 ve 2 av 2200] + +μ or 42 30 b.) If we make the assumption that flow is "fully developed" in the z direction, which term(s) would go to zero? Write the term below, describe what the term means in simple language (i.e. do not simply state "it is the derivative of a with…
1. Consult the form of the x-direction Navier-Stokes equation below that we discussed in class. (For this problem, only the x direction equation is shown for simplicity). Note that the equation provided is for a Cartesian coordinate system. In the spaces below, indicate which of the following assumptions would allow you to eliminate a term from the equation. If one of the assumptions provided would not allow you to eliminate a particular term, write "none" in the space provided. du ди at ( + + + 매일) du ди = - Pgx dy др dx ²u Fu u + fl + ax2 ay² az2 - дх - Əz 1 2 3 4 5 6 7 8 9 Assumption Flow is in the horizontal direction (e.g. patient lying on hospital bed) Flow is unidirectional in the x-direction Steady flow We consider the flow to be between two flat, infinitely wide plates There is no pressure gradient Flow is axisymmetric Term(s) in equation

Chapter 14 Solutions

The Physics of Everyday Phenomena

Ch. 14 - A uniform magnetic field is directed horizontally...Ch. 14 - A positively charged particle is momentarily at...Ch. 14 - If a uniform magnetic field is directed...Ch. 14 - Why does the magnetic force on a current-carrying...Ch. 14 - If we look down at the top of a circular loop of...Ch. 14 - If we were to represent the current loop of...Ch. 14 - A current-carrying rectangular loop of wire is...Ch. 14 - If the rectangular loop of wire shown in question...Ch. 14 - Because the magnetic fields of a coil of wire and...Ch. 14 - In what respect is a simple ammeter designed to...Ch. 14 - Does an ac motor require a split-ring commutator...Ch. 14 - Which type of motor typically runs at a fixed...Ch. 14 - If Faraday wound enough turns of wire on the...Ch. 14 - Is a magnetic flux the same as a magnetic field?...Ch. 14 - A horizontal loop of wire has a magnetic field...Ch. 14 - Suppose the magnetic flux through a coil of wire...Ch. 14 - Two coils of wire are identical except that coil....Ch. 14 - Do the sensors that detect vehicles at stoplights...Ch. 14 - Under which conditions are inductive detectors...Ch. 14 - If the magnetic field produced by the magnets in a...Ch. 14 - Does a simple generator produce a steady direct...Ch. 14 - A simple generator and a simple electric motor...Ch. 14 - Can a transformer be used, as shown in the...Ch. 14 - By stepping up the voltage of an...Ch. 14 - Prob. 1ECh. 14 - Prob. 2ECh. 14 - Prob. 3ECh. 14 - Prob. 4ECh. 14 - Prob. 5ECh. 14 - Prob. 6ECh. 14 - Prob. 7ECh. 14 - Prob. 8ECh. 14 - Prob. 9ECh. 14 - Prob. 10ECh. 14 - Prob. 11ECh. 14 - Prob. 12ECh. 14 - Prob. 13ECh. 14 - Prob. 14ECh. 14 - Prob. 15ECh. 14 - Prob. 16ECh. 14 - Prob. 1SPCh. 14 - Prob. 2SPCh. 14 - Prob. 3SPCh. 14 - Prob. 4SP
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON
Text book image
Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press
Text book image
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley
Text book image
College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON