Physics
Physics
3rd Edition
ISBN: 9780073512150
Author: Alan Giambattista, Betty Richardson, Robert C. Richardson Dr.
Publisher: McGraw-Hill Education
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Chapter 14, Problem 39P
To determine

The heat energy required.

Expert Solution & Answer
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Answer to Problem 39P

The heat energy required is 3100kJ.

Explanation of Solution

Write the expression for energy needed to raise the temperature of ice to 0.0°C.

Q1=mcice(TicefTicei)

Here, Q1 is the heat energy, m is the mass, cice is the specific heat capacity of ice, Ticef is the final temperature and Ticei is the initial temperature.

Write the expression for energy needed for melting of ice.

Q2=mLf

Here, Q2 is the heat energy and Lf is the latent heat of fusion.

Write the expression for energy needed to raise the temperature of water to 100°C.

Q3=mcwater(TwaterfTwateri)

Here, Q3 is the heat energy, m is the mass, cwater is the specific heat capacity of water, Twaterf is the final temperature and Twateri is the initial temperature.

Write the expression for energy needed for evaporation of water.

Q4=mLv

Here, Q4 is the heat energy and Lv is the latent heat of vaporization.

Write the expression for energy needed to raise the temperature of steam to 110°C.

Q5=mcsteam(TsteamfTsteami)

Here, Q3 is the heat energy, m is the mass, csteam is the specific heat capacity of water vapor, Tsteamf is the final temperature and Tsteami is the initial temperature.

The total heat required is given by,

Qtotal=Q1+Q2+Q3+Q4+Q5

Use the corresponding expressions in the above equation.

Qtotal=m[cice(TicefTicei)+Lf+cwater(TwaterfTwateri)+Lv+csteam(TsteamfTsteami)]

Conclusion:

Substitute 1.0kg for m, 0.0°C for Ticef,20.0°C for Ticei,2.1kJ/kgK for cice,333.7kJ/kg for Lf,4.186kJ/kgK for cwater,100°C for Twaterf,0.0°C for Twateri,2256kJ/kg for Lv,2.01kJ/kgK for csteam,110°C for Twaterf and 100°C for Twateri to get Qtotal.

Qtotal={(1.0kg)[(2.1kJ/kgK)(0.0°C(20.0°C))+(333.7kJ/kg)+(4.186kJ/kgK)(100°C0.0°C)+(2256kJ/kg)+(2.01kJ/kgK)(110°C100°C)]}3100kJ

Therefore, heat energy required is 3100kJ.

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Chapter 14 Solutions

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