Interpretation:
The rusted piece of iron is to be identified and the reason is to be explained.
Concept Introduction:
Oxidation is the addition of an electronegative element or the removal of an electropositive element in a
Reduction is the addition of an electropositive element or the removal of an electronegative element in a chemical reaction.
A chemical reaction in which oxidation process and reduction process take place simultaneously is called a
An oxidizing agent is a substance that has the capacity to oxidize the other substances and get reduced in a chemical reaction.
A reducing agent is a substance that has the capacity to reduce the other substances and get oxidized in a chemical reaction.
Non-metals are a better oxidizing agent than metals. They have the capacity to gain electrons and form negative ions. They have the capacity to oxidize the other substances and get reduced.
Metals are a better reducing agent. They have a tendency to lose electrons and form positive ions. They have the capacity to reduce the other substances and get oxidized.
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Chapter 14 Solutions
Bundle: Chemistry In Focus: A Molecular View Of Our World, 7th + Owlv2 With Mindtap Reader, 1 Term (6 Months) Printed Access Card
- 1A H 2A Li Be Use the References to access important values if needed for this question. 8A 3A 4A 5A 6A 7A He B C N O F Ne Na Mg 3B 4B 5B 6B 7B 8B-1B 2B Al Si P 1B 2B Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe * Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Ac Rf Ha ****** Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr Analyze the following reaction by looking at the electron configurations given below each box. Put a number and a symbol in each box to show the number and kind of the corresponding atom or ion. Use the smallest integers possible. cation anion + + Shell 1: 2 Shell 2: 8 Shell 3: 1 Shell 1 : 2 Shell 2 : 6 Shell 1 : 2 Shell 2: 8 Shell 1: 2 Shell 2: 8arrow_forwardNonearrow_forwardIV. Show the detailed synthesis strategy for the following compounds. a. CH3CH2CH2CH2Br CH3CH2CCH2CH2CH3arrow_forward
- Do the electrons on the OH participate in resonance with the ring through a p orbital? How many pi electrons are in the ring, 4 (from the two double bonds) or 6 (including the electrons on the O)?arrow_forwardPredict and draw the product of the following organic reaction:arrow_forwardNonearrow_forward
- Redraw the molecule below as a skeletal ("line") structure. Be sure to use wedge and dash bonds if necessary to accurately represent the direction of the bonds to ring substituents. Cl. Br Click and drag to start drawing a structure. : ☐ ☑ Parrow_forwardK m Choose the best reagents to complete the following reaction. L ZI 0 Problem 4 of 11 A 1. NaOH 2. CH3CH2CH2NH2 1. HCI B OH 2. CH3CH2CH2NH2 DII F1 F2 F3 F4 F5 A F6 C CH3CH2CH2NH2 1. SOCl2 D 2. CH3CH2CH2NH2 1. CH3CH2CH2NH2 E 2. SOCl2 Done PrtScn Home End FA FQ 510 * PgUp M Submit PgDn F11arrow_forwardNonearrow_forward
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