Statistics: The Art and Science of Learning from Data (4th Edition)
Statistics: The Art and Science of Learning from Data (4th Edition)
4th Edition
ISBN: 9780321997838
Author: Alan Agresti, Christine A. Franklin, Bernhard Klingenberg
Publisher: PEARSON
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Chapter 14, Problem 38CP

Singles watch more TV The 2014 General Social Survey asked 1475 subjects how many hours per day they watched TV, on average. Are there differences in population means according to the marital status of the subject (single, married, divorced)? The sample means were 3.27 for singles (n = 459), 2.64 for married subjects (n = 731), and 2.85 for divorced subjects (n = 285). In a one-way ANOVA, the between-groups estimate of the variance is 54.8 and the within-groups estimate is 6.0. (The dataset is available online as TV Hours 2014.)

  1. a. Conduct the ANOVA test and make a decision using a 0.05 significance level.
  2. b. The 95% confidence interval comparing the population means is (0.3, 0.9) for single and married subjects (0.06, 0.8) for single and divorced subjects and (–0.5, 0.1) for married and divorced subjects Based on the three confidence intervals indicate which pairs of means are significantly different Interpret.
  3. c. Based on the information given, show how to construct the confidence interval that compares the population mean TV watching for single and married subjects.
  4. d. Refer to part c. Would the corresponding interval formed with the Tukey method be wider or narrower? Explain why.
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Let us suppose we have some article reported on a study of potential sources of injury to equine veterinarians conducted at a university veterinary hospital. Forces on the hand were measured for several common activities that veterinarians engage in when examining or treating horses. We will consider the forces on the hands for two tasks, lifting and using ultrasound. Assume that both sample sizes are 6, the sample mean force for lifting was 6.2 pounds with standard deviation 1.5 pounds, and the sample mean force for using ultrasound was 6.4 pounds with standard deviation 0.3 pounds. Assume that the standard deviations are known. Suppose that you wanted to detect a true difference in mean force of 0.25 pounds on the hands for these two activities. Under the null hypothesis, 40 = 0. What level of type II error would you recommend here? Round your answer to four decimal places (e.g. 98.7654). Use a = 0.05. β = i What sample size would be required? Assume the sample sizes are to be equal.…
= Consider the hypothesis test Ho: μ₁ = μ₂ against H₁ μ₁ μ2. Suppose that sample sizes are n₁ = 15 and n₂ = 15, that x1 = 4.7 and X2 = 7.8 and that s² = 4 and s² = 6.26. Assume that o and that the data are drawn from normal distributions. Use απ 0.05. (a) Test the hypothesis and find the P-value. (b) What is the power of the test in part (a) for a true difference in means of 3? (c) Assuming equal sample sizes, what sample size should be used to obtain ẞ = 0.05 if the true difference in means is - 2? Assume that α = 0.05. (a) The null hypothesis is 98.7654). rejected. The P-value is 0.0008 (b) The power is 0.94 . Round your answer to four decimal places (e.g. Round your answer to two decimal places (e.g. 98.76). (c) n₁ = n2 = 1 . Round your answer to the nearest integer.
Consider the hypothesis test Ho: = 622 against H₁: 6 > 62. Suppose that the sample sizes are n₁ = 20 and n₂ = 8, and that = 4.5; s=2.3. Use a = 0.01. (a) Test the hypothesis. Round your answers to two decimal places (e.g. 98.76). The test statistic is fo = i The critical value is f = Conclusion: i the null hypothesis at a = 0.01. (b) Construct the confidence interval on 02/022 which can be used to test the hypothesis: (Round your answer to two decimal places (e.g. 98.76).) i

Chapter 14 Solutions

Statistics: The Art and Science of Learning from Data (4th Edition)

Ch. 14.1 - Prob. 11PBCh. 14.2 - House prices and age For the House Selling Prices...Ch. 14.2 - Time on Facebook Do freshmen spent significantly...Ch. 14.2 - Prob. 14PBCh. 14.2 - Tukey holding time comparisons Refer to the...Ch. 14.2 - Prob. 16PBCh. 14.2 - REM regression Refer to the previous exercise. a....Ch. 14.2 - Prob. 18PBCh. 14.2 - Regression for outsourcing Refer to the previous...Ch. 14.2 - Advertising effect oil sales Each of 100...Ch. 14.3 - Reducing cholesterol An experiment randomly...Ch. 14.3 - Prob. 24PBCh. 14.3 - Political ideology in 2014 The GSS measures...Ch. 14.3 - Prob. 26PBCh. 14.3 - Corn and manure In Example 10, the coefficient of...Ch. 14.3 - Prob. 28PBCh. 14.3 - Regression for telephone holding times Refer to...Ch. 14.3 - Prob. 30PBCh. 14.3 - Income by gender and degree In 2012, the...Ch. 14.3 - Prob. 32PBCh. 14.3 - Attractiveness and getting dates The results in...Ch. 14.3 - Prob. 34PBCh. 14.3 - Regression of weight gain on diet Refer to the...Ch. 14 - Good friends and marital status Is the number of...Ch. 14 - Prob. 37CPCh. 14 - Singles watch more TV The 2014 General Social...Ch. 14 - Prob. 39CPCh. 14 - Prob. 40CPCh. 14 - Prob. 41CPCh. 14 - Prob. 42CPCh. 14 - Prob. 43CPCh. 14 - Comparing therapies for anorexia The Anorexia data...Ch. 14 - Prob. 45CPCh. 14 - Prob. 46CPCh. 14 - Prob. 47CPCh. 14 - Prob. 48CPCh. 14 - Prob. 49CPCh. 14 - Prob. 50CPCh. 14 - Prob. 51CPCh. 14 - TV watching by gender and race When we use the...Ch. 14 - Prob. 53CPCh. 14 - Prob. 54CPCh. 14 - Prob. 55CPCh. 14 - Prob. 56CPCh. 14 - Prob. 57CPCh. 14 - Prob. 59CPCh. 14 - Prob. 60CPCh. 14 - Prob. 61CPCh. 14 - Prob. 62CPCh. 14 - Prob. 63CPCh. 14 - Prob. 64CPCh. 14 - Prob. 65CPCh. 14 - Prob. 66CPCh. 14 - Prob. 67CPCh. 14 - Prob. 68CPCh. 14 - Prob. 69CPCh. 14 - Prob. 70CPCh. 14 - Prob. 71CP
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