The structure of compound Y is to be proposed on the basis of H 1 NMR and IR. Concept introduction: Nuclear Magnetic Resonance (NMR) is one of the most capable analytical techniques used for determining the functional groups and how the atoms are structured and arranged in a molecule. Few elements, such as 13 C and 1 H , have nuclei behaving as magnets about an axis. These elements are placed in magnetic field irradiated with electromagnetic energy of specific frequency and the nuclei tend to absorb energy via magnetic resonance. There is this graph that shows energy absorption frequencies and intensities of a sample kept in the magnetic field called nuclear magnetic resonance (NMR). In NMR spectroscopy, the proton nuclear magnetic resonance ( 1 H NMR) is used to find out the structure of molecules with the help of 1 H atom within the molecules. Induced magnetic field consists of electricity generated from movement in a magnetic field. Infrared spectroscopy is a simple, instrumental technique, which helps to determine the presence of various functional groups. It depends on the interactions of atoms or molecules with the electromagnetic radiation. Infrared spectroscopy is most commonly used in the identification of the structure of the compound. Infrared spectroscopy is the examination of the infrared light interacting with a molecule. The examination can be done in three ways, that is, by measuring absorption, emission, and reflection, and it can also measure the vibration of atoms. 13 C NMR is only used in the observation of isotopes of carbon atoms. The H 1 NMR signal for protons bonded to substituted benzene rings is between δ 6 and 8.5 . The IR (infrared) spectra of benzene show the absorption occurring at 3030 cm − 1 for the stretching of C-H bond. Further, the monosubstituted benzene results in the generation of peaks in the range of 690 and 710 cm − 1 , and in the range of 730 and 770 cm − 1 . The O-H group gives a broad peak at 3550-3200 cm − 1 .

Question

Want to see the full answer?

Answer 1

Question

Chapter 14, Problem 37P

Interpretation Introduction

Interpretation:

The structure of compound Y is to be proposed on the basis of H1NMR and IR.

Concept introduction:

Nuclear Magnetic Resonance (NMR) is one of the most capable analytical techniques used for determining the functional groups and how the atoms are structured and arranged in a molecule.

Few elements, such as 13C and 1H, have nuclei behaving as magnets about an axis. These elements are placed in magnetic field irradiated with electromagnetic energy of specific frequency and the nuclei tend to absorb energy via magnetic resonance. There is this graph that shows energy absorption frequencies and intensities of a sample kept in the magnetic field called nuclear magnetic resonance (NMR).

In NMR

spectroscopy, the proton nuclear magnetic resonance (1H NMR) is used to find out the structure of molecules with the help of 1H

atom within the molecules.

Induced magnetic field consists of electricity generated from movement in a magnetic field.

Infrared spectroscopy is a simple, instrumental technique, which helps to determine the presence of various functional groups.

It depends on the interactions of atoms or molecules with the electromagnetic radiation.

Infrared spectroscopy is most commonly used in the identification of the structure of the compound.

Infrared spectroscopy is the examination of the infrared light interacting with a molecule. The examination can be done in three ways, that is, by measuring absorption, emission, and reflection, and it can also measure the vibration of atoms.

13C

NMR is only used in the observation of isotopes of carbon atoms.

The H1NMR

signal for protons bonded to substituted benzene rings is between δ6 and 8.5.

The IR (infrared) spectra of benzene show the absorption occurring at 3030 cm−1 for the stretching of C-H

bond. Further, the monosubstituted benzene results in the generation of peaks in the range of 690 and 710 cm−1, and in the range of 730 and 770 cm−1. The O-H

group gives a broad peak at 3550-3200 cm−1.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

when performing the reaction that involves 2 equivalents of 3-(diethylamino)-phenol and Phthalic anhydride with sulfuric acid and water react to form rhodamine b where the Phthalic anhydride cleaves in acid and how does Excessive Washing (w/ Base) & Subsequent Resonance Structure get affected

3. The strongest acid of the following compounds is ___.A. p-nitrophenol; B. m-nitrophenol; C. o-chlorophenol;D. p-methoxyphenol; E. o-methylphenol Please explain your steps and thought process. Thank you!

Using the general properties of equilibrium constants At a certain temperature, the equilibrium constant K for the following reaction is 1.3 × 10 4: Cl2(g) + CHCl3(g) HCl(g) + CC₁(g) Use this information to complete the following table. Suppose a 16. L reaction vessel is filled with 1.6 mol of HCI and 1.6 mol of CCl4. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little Cl2 and CHCl3. ☐ x10 There will be very little HCI and CCl4. Neither of the above is true. What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. HCl(g)+CC14(g) 12 Cl2(9)+CHCl3(9) K = 0 ☐ What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 2 Cl₂(9)+2CHCl3(9) 2 HCl(9)+2CC₁₁(9) K = ✓ 00. 18 Ar