a. Explanation Given data: The stretch is 2.3 m . Formula used: Write the expression for period of pendulum ( T ) . T = 2 π I m g d (1) Here, I is moment of inertia, m is mass, d is distance from pivot to center of gravity, and g is free-fall acceleration on earth is 9.80 m s 2 . Explanation: Consider the leg of elephant as pendulum and the leg of elephant as a bar pivoted at one end. Write the expression for moment of inertia for a bar pivoted at one end ( I ) . I = 1 3 m L 2 (2) Here, L is length of stretch. The elephant legs have uniform cross-section and hence the distance between the pivot and point of center of gravity ( d ) is equal to the half the length of stretch. d = 1 2 L Substitute 1 3 m L 2 for I and 1 2 L for d in equation (1), T = 2 π 1 3 m L 2 m g ( 1 2 L ) = 2 π 2 L 3 g Substitute 2 b. To determine The frequency of elephant’s stride in steps per minute.

College Physics: A Strategic Approach (4th Edition)

4th Edition

ISBN: 9780134704180

Author: Knight

Publisher: PEARSON

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Question

Chapter 14, Problem 37P

To determine

The time required for one leg to swing forward after completing a stride.

To determine

The frequency of elephant’s stride in steps per minute.

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Chapter 14, Problem 35P

Chapter 14, Problem 38P

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