
Computer Science Illuminated
7th Edition
ISBN: 9781284155617
Author: Nell Dale, John Lewis
Publisher: Jones & Bartlett Learning
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Chapter 14, Problem 2TQ
Program Plan Intro
Queue:
- This is the abstract data type in which access of data is made at both the ends.
- The data is inserted at one end or removed at the other end.
- So, the first item inserted at one end can be retrieved first at the other end. This
mechanism is referred to as first-in-first-out (FIFO). - Insertion and deletion are the common operations of a queue.
- Inserting an item into the queue is called “Enqueue”.
- Removing an item from the queue is called “Dequeue”.
- Diagrammatic representation of enqueue operation:
|
In the above diagram,
- After inserting the item “1” to the empty queue, the “front” and the “rear” pointers point to this first item.
- After inserting the item “9”, the “rear” pointer moves from the item “1” to the item “9”.
- After inserting the item “3”, the “rear” pointer moves from the item “9” to the item “3” and during insertion, the “front” pointer points only to the first item.
Priority queue:
- If the items in the queue are assigned with a priority, then it is called priority queue.
- When inserting an item into the priority queue, the item is added with the priority.
- When removing an item from the priority queue, the item with higher priority is first removed. Then, based on the priority, the other items are removed.
- The maximum number or the minimum number can be deleted by using deletemaximum() or deleteminimum() function.
- Deletemaximum() is a function which deletes the number which is having the highest priority.
- Deleteminimum() is a function which deletes the number which is having the lowest priority.
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Specifications: Part-1Part-1: DescriptionIn this part of the lab you will build a single operation ALU. This ALU will implement a bitwise left rotation. Forthis lab assignment you are not allowed to use Digital's Arithmetic components.IF YOU ARE FOUND USING THEM, YOU WILL RECEIVE A ZERO FOR LAB2!The ALU you will be implementing consists of two 4-bit inputs (named inA and inB) and one 4-bit output (named
out). Your ALU must rotate the bits in inA by the amount given by inB (i.e. 0-15).Part-1: User InterfaceYou are provided an interface file lab2_part1.dig; start Part-1 from this file.NOTE: You are not permitted to edit the content inside the dotted lines rectangle.Part-1: ExampleIn the figure above, the input values that we have selected to test are inA = {inA_3, inA_2, inA_1, inA_0} = {0, 1, 0,0} and inB = {inB_3, inB_2, inB_1, inB_0} = {0, 0, 1, 0}. Therefore, we must rotate the bus 0100 bitwise left by00102, or 2 in base 10, to get {0, 0, 0, 1}. Please note that a rotation left is…
Chapter 14 Solutions
Computer Science Illuminated
Ch. 14 - Prob. 1ECh. 14 - Prob. 2ECh. 14 - Prob. 3ECh. 14 - Prob. 4ECh. 14 - Prob. 5ECh. 14 - Prob. 6ECh. 14 - Prob. 7ECh. 14 - Prob. 8ECh. 14 - Prob. 9ECh. 14 - Prob. 10E
Ch. 14 - Prob. 11ECh. 14 - Prob. 12ECh. 14 - Prob. 13ECh. 14 - Prob. 14ECh. 14 - Prob. 15ECh. 14 - Prob. 16ECh. 14 - Prob. 17ECh. 14 - Prob. 18ECh. 14 - Prob. 19ECh. 14 - Prob. 20ECh. 14 - Prob. 21ECh. 14 - Prob. 22ECh. 14 - Prob. 23ECh. 14 - Prob. 24ECh. 14 - Prob. 25ECh. 14 - Prob. 26ECh. 14 - Prob. 27ECh. 14 - Prob. 28ECh. 14 - Prob. 29ECh. 14 - Prob. 30ECh. 14 - Prob. 31ECh. 14 - Prob. 32ECh. 14 - Prob. 33ECh. 14 - Prob. 34ECh. 14 - Prob. 35ECh. 14 - Prob. 36ECh. 14 - Prob. 37ECh. 14 - Prob. 38ECh. 14 - Prob. 39ECh. 14 - Prob. 40ECh. 14 - Prob. 41ECh. 14 - Prob. 42ECh. 14 - Prob. 43ECh. 14 - Prob. 44ECh. 14 - Prob. 45ECh. 14 - Prob. 46ECh. 14 - Prob. 47ECh. 14 - Prob. 48ECh. 14 - Prob. 49ECh. 14 - Prob. 50ECh. 14 - Prob. 51ECh. 14 - Prob. 52ECh. 14 - Prob. 1TQCh. 14 - Prob. 2TQCh. 14 - Prob. 3TQCh. 14 - Prob. 4TQCh. 14 - Prob. 5TQCh. 14 - Prob. 6TQCh. 14 - Prob. 7TQCh. 14 - Prob. 8TQ
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