When a block with a hole in it is heated, why doesn’t the material around the hole expand into the hole and make it smaller? Explain this behavior by looking at the forces operating at the molecular level.
When a block with a hole in it is heated, why doesn’t the material around the hole expand into the hole and make it smaller? Explain this behavior by looking at the forces operating at the molecular level.
When a block with a hole in it is heated, why doesn’t the material around the hole expand into the hole and make it smaller? Explain this behavior by looking at the forces operating at the molecular level.
Expert Solution & Answer
To determine
The reason for which, while heating a block with a hole in it, the material around the hole does not expand into the hole and make it smaller.
Answer to Problem 1CQ
The expansion of materials upon heating is due to the increase in molecular separations which take place uniformly and hence the expansion of the solid material as well as the hole is identical so that the material around the hole does not expand into the hole and make it smaller.
Explanation of Solution
Upon heating all the materials expands. This expansion is due to the increase in the average molecular separation in the material due to the gain of heat energy. The increase in the average separation between the atoms or molecules take place uniformly in all directions.
The expansion of a material block with a hole in it is identical to that of a solid block. The hole in the block expands just like the solid piece of the material. Therefore, while heating a block with a hole in it, the material around the hole does not expand into the hole and make it smaller.
Want to see more full solutions like this?
Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Four capacitors are connected as shown in the figure below. (Let C = 12.0 μF.)
a
C
3.00 με
Hh.
6.00 με
20.0 με
HE
(a) Find the equivalent capacitance between points a and b.
5.92
HF
(b) Calculate the charge on each capacitor, taking AV ab = 16.0 V.
20.0 uF capacitor 94.7
6.00 uF capacitor 67.6
32.14
3.00 µF capacitor
capacitor C
☑
με
με
The 3 µF and 12.0 uF capacitors are in series and that combination is in parallel with the 6 μF capacitor. What quantity is the same for capacitors in parallel? μC
32.14
☑
You are correct that the charge on this capacitor will be the same as the charge on the 3 μF capacitor. μC
Four capacitors are connected as shown in the figure below. (Let C = 12.0 µF.)
A circuit consists of four capacitors. It begins at point a before the wire splits in two directions. On the upper split, there is a capacitor C followed by a 3.00 µF capacitor. On the lower split, there is a 6.00 µF capacitor. The two splits reconnect and are followed by a 20.0 µF capacitor, which is then followed by point b.
(a) Find the equivalent capacitance between points a and b. µF(b) Calculate the charge on each capacitor, taking ΔVab = 16.0 V.
20.0 µF capacitor
µC
6.00 µF capacitor
µC
3.00 µF capacitor
µC
capacitor C
µC
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.