Explanation Given information: Show the integral as follows: ∫ − 1 1 ∫ − 1 − x 2 1 − x 2 2 d y d x ( 1 + x 2 + y 2 ) 2 (1) Calculation: Show the Equation as follows: y = 1 − x 2 x 2 + y 2 = 1 Here, the above Equation is a circle with radius r equal to 1. The value of θ ranges from 0 to 2 π . The value of r ranges from 0 to 1. Modify Equation (1) as follows: ∫ − 1 1 ∫ − 1 − x 2 1 − x 2 2 d y d x ( 1 + x 2 + y 2 ) 2 = ∫ 0 2 π ∫ 0 1 2 r ( 1 + r 2 ) 2 d r d θ = ∫ 0 2 π

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ISBN: 9780135910993

Author: Hass

Publisher: PEARSON

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Chapter 14, Problem 19PE

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Calculate the value of the integral by changing to polar coordinates.

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Chapter 14, Problem 18PE

Chapter 14, Problem 20PE

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Ch. 14.1 - In Exercises 1-14. evaluate the iterated...Ch. 14.1 - Prob. 2E Ch. 14.1 - Prob. 3E Ch. 14.1 - In Exercises 1-14, evaluate the iterated...Ch. 14.1 - In Exercises 1-14, evaluate the iterated...Ch. 14.1 - In Exercises 1-14, evaluate the iterated...Ch. 14.1 - In Exercises 1-14, evaluate the iterated integral....Ch. 14.1 - In Exercises 1-14, evaluate the iterated...Ch. 14.1 - In Exercises 1-14, evaluate the iterated integral....Ch. 14.1 - Prob. 10E

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