Explanation Introduction: Bernoulli’s equation states that for laminar fluid flow without any resistance, the sum of kinetic energy density, the gravitational potential energy density, and pressure of the fluid is a constant. The Bernoulli bar chart is used for representation and easy visualization of fluid dynamic processes. The bar represents pressures and energy densities. Continuity equation defines the relationship between the cross-sectional area and the average speed of fluid flow. It is based on the principle of conservation of mass which states that mass can be neither created nor destroyed. Explanation: Write the continuity equation. A 1 v 1 = A 2 v 2 Here, A 1 ⋅ v 1 is average flow rate through point 1, A 2 ⋅ v 2 is average flow rate through point 2, A 1 is cross-sectional area at point 1, v 1 is speed of fluid at point 1, A 2 is cross-sectional area at point 2, and v 2 is speed of fluid at point 2. Write the Bernoulli’s equation. P 1 + K ˜ 1 + U ˜ g 2 = P 2 + K ˜ 2 + U ˜ g 2 Or P 1 + 1 2 ρ v 1 2 + ρ g y 1 = P 2 + 1 2 ρ v 2 2 + ρ g y 2 Here, P 1 is the fluid pressure at point 1, K ˜ 1 is the kinetic energy density at point 1, U ˜ g 1 is the gravitational potential energy density at point 1, ρ is the fluid density, v 1 is the speed of flow at point 1, g is acceleration due to gravity, and y 1 is the elevation of point 1, P 2 is the fluid pressure at point 2, K ˜ 2 is the kinetic energy density at point 2, U ˜ g 1 is the gravitational potential energy density at point 2, v 2 is the speed of flow at point 2, and y 2 is the elevation of point 2

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ISBN: 9780134862897

Author: ETKINA

Publisher: PEARSON

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Density of Solids

The density of a substance refers to how much matter is present in a given amount of space. It is expressed as the ratio of the mass of the substance to its volume.

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Chapter 14, Problem 15P

To determine

The Bernoulli’s bar chart and draw the sketch of a situation that satisfies the given equation.

0.5ρv12+(P1−P2)=0.5ρv22+ρgy2

And, P1<P2

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Chapter 14, Problem 14P

Chapter 14, Problem 16P

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Chapter 14 Solutions

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The Bernoulli’s bar chart and draw the sketch of a situation that satisfies the given equation. 0.5 ρ v 1 2 + ( P 1 − P 2 ) = 0.5 ρ v 2 2 + ρ g y 2 And, P 1 &lt; P 2

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The Bernoulli’s bar chart and draw the sketch of a situation that satisfies the given equation. 0.5ρv12+(P1−P2)=0.5ρv22+ρgy2 And, P1<P2

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Chapter 14 Solutions

The Bernoulli’s bar chart and draw the sketch of a situation that satisfies the given equation. 0.5 ρ v 1 2 + ( P 1 − P 2 ) = 0.5 ρ v 2 2 + ρ g y 2 And, P 1 < P 2

The Bernoulli’s bar chart and draw the sketch of a situation that satisfies the given equation.

0.5ρv12+(P1−P2)=0.5ρv22+ρgy2

And, P1<P2