Chapter 14, Problem 14B.2E

Interpretation Introduction

Interpretation:

Surface tension of the ethanol has to be calculated.

Concept introduction:

The surface tension can be calculated by using following formula,

  $\begin{array}{l}\gamma =\frac{1}{2}\rho ghr\\ \frac{2\gamma }{\rho gr}=h\end{array}$

where,

  $\begin{array}{l}\text{γ}\text{=}\text{surface}\text{tension}\\ \text{h}\text{=}\text{height}\\ \text{ρ}\text{= Mass}\text{density of the liquid}\\ \text{g}\text{=}\text{acceleration of free fall}\\ \text{r}\text{=}\text{radius}\end{array}$

Unit conversion:

${\text{1 kg m s}}^{\text{-2}}\text{ = 1 N}$