Explanation The K w value of water at 30 ∘ C and 50 ∘ C are 1.47 × 10 − 14 a n d 5.48 × 10 − 14 respectively. Using Clausius-Clapeyron equation, the value of Δ H ∘ for water can be calculated as shown below. ln ( K 1 K 2 ) = Δ H ∘ R ( 1 T 2 − 1 T 1 ) ln ( 5.48 × 10 − 14 1.47 × 10 − 14 ) = Δ H ∘ 0.008314 k J K − 1 m o l − 1 ( 1 303 K − 1 323 K ) Δ H ∘ = 5 2 . 0 9 k J / m o l . W h e r e , T 2 = 30 + 273 = 303 K a n d T 1 = 50 + 273 = 323 K The value of Δ H ∘ for water is 5 2 . 0 9 k J / m o l . Now, the value of K w at 200 ∘ C can also be calculated by using again Clausius-Clapeyron equation. ln ( K 1 K 2 ) = Δ H ∘ R ( 1 T 2 − 1 T 1 ) ln ( K w 5.48 × 10 − 14 ) = 52 .09 kJ/mol 0

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Chapter 14, Problem 14.ACP

Interpretation Introduction

Interpretation:

The pH of water at 200∘C has to be calculated.

Concept Introduction:

The Clausius-Clapeyron equation is given below.

ln(K1K2)=ΔH∘R(1T2−1T1)

Where, K1 and K2 are equilibrium constants at temperature T1 and T2.

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Chapter 14, Problem 135QRT

Chapter 14, Problem 14.BCP

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Chapter 14 Solutions

OWLV2 FOR MOORE/STANITSKI'S CHEMISTRY:

Ch. 14.1 - Identify each molecule or ion as a Brnsted-Lowry...Ch. 14.1 - Using Le Chatelier’s Principle Use Le Chatelier’s...Ch. 14.1 - Prob. 14.3E Ch. 14.1 - Complete the table. Ch. 14.1 - Prob. 14.4E Ch. 14.1 - Prob. 14.5E Ch. 14.2 - Prob. 14.6CE Ch. 14.2 - Prob. 14.7E Ch. 14.3 - Prob. 14.2PSP Ch. 14.3 - Prob. 14.3PSP

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The p H of water at 200 ∘ C has to be calculated. Concept Introduction: The Clausius-Clapeyron equation is given below. ln ( K 1 K 2 ) = Δ H ∘ R ( 1 T 2 − 1 T 1 ) Where, K 1 a n d K 2 are equilibrium constants at temperature T 1 a n d T 2 .

Solution Summary: The author explains the Clausius-Clapeyron equation for the pH of water at 200circ

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Interpretation:

The pH of water at 200∘C has to be calculated.

Concept Introduction:

The Clausius-Clapeyron equation is given below.

ln(K1K2)=ΔH∘R(1T2−1T1)

Where, K1 and K2 are equilibrium constants at temperature T1 and T2.

Want to see the full answer?

Chapter 14 Solutions

The p H of water at 200 ∘ C has to be calculated. Concept Introduction: The Clausius-Clapeyron equation is given below. ln ( K 1 K 2 ) = Δ H ∘ R ( 1 T 2 − 1 T 1 ) Where, K 1 a n d K 2 are equilibrium constants at temperature T 1 a n d T 2 .

Solution Summary: The author explains the Clausius-Clapeyron equation for the pH of water at 200circ

Concept explainers

Videos

Interpretation: The pH of water at 200∘C has to be calculated. Concept Introduction: The Clausius-Clapeyron equation is given below. ln(K1K2)=ΔH∘R(1T2−1T1) Where, K1 and K2 are equilibrium constants at temperature T1 and T2.

Want to see the full answer?

Chapter 14 Solutions

Interpretation:

The pH of water at 200∘C has to be calculated.

Concept Introduction:

The Clausius-Clapeyron equation is given below.

ln(K1K2)=ΔH∘R(1T2−1T1)

Where, K1 and K2 are equilibrium constants at temperature T1 and T2.