Chapter 14, Problem 14.8P

Interpretation Introduction

(a)

Interpretation:

The tensile strength for the given aluminium alloys needs to be determined.

1100-H14.

Concept Introduction:

The amount of force required to pull any object like rope, wire or structural beam until its point of breakage and its measurement is called tensile strength.

The tensile strength of any material is the maximum amount of tensile stress occurred that can be handled by specimen before its failure or breakage.

Answer to Problem 14.8P

The tensile strength of aluminium alloy 1100-H14.

Explanation of Solution

To calculate the tensile strength of 1100-H14 the formula to be used is:

  $(1100-H14)=\frac{(1100-0)+(1100-H18)}{2}$

Where, TS = tensile strength

From properties table, value of

  $(1100-0)$ alloy = 90 MPa and

  $(1100-H18)$ alloy = 166 MPa

  $(1100-H14)=\frac{90+166}{2}$

  $(1100-H14)=182MPa$

Interpretation Introduction

(b)

Interpretation:

The tensile strength for the given aluminium alloys needs to be determined.

5182-H12.

Concept Introduction:

The amount of force required to pull any object like rope, wire or structural beam until its point of breakage and its measurement is called tensile strength.

The tensile strength of any material is the maximum amount of tensile stress occurred that can be handled by specimen before its failure or breakage.

Answer to Problem 14.8P

The tensile strength of aluminium alloy 5182-H12 obtained is 319.205 MPa.

Explanation of Solution

To calculate the tensile strength of 5182-H12 the formula to be used is:

  $(5182-H12)=\frac{(5182-0)+(5182-H14)}{2}$ ....1

  $(5182-H14)=\frac{(5182-0)+(5182-H18)}{2}$ ....2

For 5182-H18,

  $(5182-H18)=(5182-H19)-14MPa$

From the properties table $(5182-H19)=421MPa$

  $(5182-H18)$ = 421-14

= 407 MPa

Substituting values of $(5182-H18)$

= 407 MPa and $(5182-0)$ = 290 MPa

In Eq. 2. We get

  $(5182-H14)$ = 348.5 MPa

Substituting value of $(5182-H14)$ = 348.5 MPa and $(5182-0)$ = 290 MPa

In Eq. 1. We get

  $(5182-H12)=319.25MPa$

Interpretation Introduction

(c)

Interpretation:

The tensile strength for the given aluminium alloys needs to be determined.

3004-H16.

Concept Introduction:

The amount of force required to pull any object like rope, wire or structural beam until its point of breakage and its measurement is called tensile strength.

The tensile strength of any material is the maximum amount of tensile stress occurred that can be handled by specimen before its failure or breakage.

Answer to Problem 14.8P

The tensile strength obtained of aluminium alloy 3004-H16 is 257 MPa.

Explanation of Solution

  $(3004-H16)=\frac{(3004-H14)+(3004-H16)}{2}$ ....3

Where,

  $(3004-H14)=\frac{(3004-0)+(3004-H18)}{2}$ ....4

From properties table of aluminum alloys we get;

  $\begin{array}{l}(_{3004}^{-}{}_H{}^{18}{}_{)}=283MPa\\ (_{3004}^{-}{}_0{}^{)}=179MPa\end{array}$

Substituting these values in Eq. 4. We get,

TS = $(3004-H14)$ =231 MPa.

Substituting the value of

  $(3004-H14)$ inEq. 3. We get,

  $(3004-H16)=257MPa$