(a) Explanation Given Info: The mass of the monkey wrench is 1.80 kg , the monkey wrench is pivoted 0.250 m from its centre of mass and allowed to swing as physical pendulum and the period of oscillation of the wrench is 0.940 s . Formula to calculate the period of oscillation of the monkey wrench is, T = 2 π I m g d T is the period of oscillation. I is the moment of inertia of the wrench. m is the mass of the monkey wrench. g is the acceleration due to gravitation. d is the distance of centre of the gravity of the wrench from the pivot. Substitute 0.940 s for T , 1.80 kg for m , 9.81 m/s 2 for g and 0.250 m for d in the above equation to find I . 0 (b) To determine The angular speed of the wrench when it passes through the equilibrium position.

14th Edition

ISBN: 9780133969290

Author: Hugh D. Young, Roger A. Freedman

Publisher: PEARSON

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Question

Chapter 14, Problem 14.56E

(a)

To determine

The moment of inertia of the wrench about an axis through the pivot.

(b)

To determine

The angular speed of the wrench when it passes through the equilibrium position.

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Chapter 14, Problem 14.55E

Chapter 14, Problem 14.57E

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