EBK GET READY FOR ORGANIC CHEMISTRY
EBK GET READY FOR ORGANIC CHEMISTRY
2nd Edition
ISBN: 9780321787989
Author: KARTY
Publisher: PEARSON CO
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Chapter 14, Problem 14.54P
Interpretation Introduction

Interpretation:

Whether the given compound will have a significant dipole moment is to be determined. If so, the direction of the dipole moment is to be determined.

Concept introduction:

If two rings are with conjugated double bonds and are joined by a double bond, it is possible that one or both may achieve aromatic stabilization if the π electron pair of the double bond in the middle moves to one carbon.

The resulting charge separation will make the molecule polar. Additionally, the delocalization of the charge due to the aromatic character of the ring(s) will increase the separation between charges, giving the molecule a substantial dipole moment.

The direction of a molecular dipole is from the atom or region with a positive charge toward the atom or region with a negative charge.

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Choose the Lewis structure for the compound below: H2CCHOCH2CH(CH3)2 HH H :d H H H C. Η H H HH H H H H. H H H HH H H H H H- H H H C-H H H HHHH
Each of the highlighted carbon atoms is connected to hydrogen atoms.
く Complete the reaction in the drawing area below by adding the major products to the right-hand side. If there won't be any products, because nothing will happen under these reaction conditions, check the box under the drawing area instead. Note: if the products contain one or more pairs of enantiomers, don't worry about drawing each enantiomer with dash and wedge bonds. Just draw one molecule to represent each pair of enantiomers, using line bonds at the chiral center. More... No reaction. Explanation Check O + G 1. Na O Me Click and drag to start drawing a structure. 2. H + 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility 000 Ar P

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EBK GET READY FOR ORGANIC CHEMISTRY

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