The cost of material per unit volume is more important in some cases than the cost per unit weight. The cost needs to be determined in terms of $ / cm 3 . Whether this affects the relationship between the different materials or not needs to be explained. Concept Introduction: Specific strength can be calculated as follows: Specific strength = strength Mass density It relates the specific strengths of steel, few high strength non-ferrous alloys, and polymer- matrix composites. Additional factor to study in designing with non-ferrous material is their rate, which also differs significantly.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 14, Problem 14.1P

Interpretation Introduction

Interpretation:

The cost of material per unit volume is more important in some cases than the cost per unit weight. The cost needs to be determined in terms of $/cm3. Whether this affects the relationship between the different materials or not needs to be explained.

Concept Introduction:

Specific strength can be calculated as follows:

Specific strength = strength Mass density

It relates the specific strengths of steel, few high strength non-ferrous alloys, and polymer- matrix composites. Additional factor to study in designing with non-ferrous material is their rate, which also differs significantly.

Expert Solution & Answer

Explanation of Solution

Table no.1

Metal	Density(g/ cm3)	Cost per kg($/kg)	Rank

Steels	7.87	0.22	1
Zinc	7.13	0.88	2
Lead	11.36	0.99	3
Aluminium	2.70	1.32	4
Copper	8.93	1.57	5
Magnesium	1.74	3.31	6
Titanium	4.51	8.82	7
Tungsten	19.25	8.82	8
Nickel	8.90	9.04	9
Beryllium	1.85	777.60	10

The cost of a material per unit volume can be converted from ($/kg) to ($/g) by dividing the cost of material by 1000, and multiplying the converted cost value with density.

Table no. 2

Metal	Density	Cost per kg	Cost per gram	Cost per volume	Rank

Steel	7.87	0.22	0.22 ×10−3	0.0017	1
Aluminium	2.70	1.32	1.32 ×10−3	0.0036	2
Magnesium	1.74	3.31	3.31 ×10−3	0.0057	3
Zinc	7.13	0.88	0.88 ×10−3	0.0063	4
Lead	11.36	0.99	0.99 ×10−3	0.0013	5
Copper	8.93	1.57	1.57 ×10−3	0.0140	6
Titanium	4.51	8.82	8.82 ×10−3	0.0397	7
Nickel	8.90	9.04	9.04 ×10−3	0.0804	8
Tungsten	19.25	8.82	8.82 ×10−3	0.1696	9
Beryllium	1.85	771.60	771.60 ×10−3	1.4247	10

From the above two tables, the different materials are related to each other in terms of cost per kilogram and cost per volume.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

Object-Oriented Programming In this separate files. ent, you'll need to build and run a small Zoo in Lennoxville. All classes must be created in Animal (5) First, start by building a class that describes an Animal at a Zoo. It should have one private instance variable for the name of the animal, and one for its hunger status (fed or hungry). Add methods for setting and getting the hunger satus variable, along with a getter for the name. Consider how these should be named for code clarity. For instance, using a method called hungry () to make the animal hungry could be used as a setter for the hunger field. The same logic could be applied to when it's being fed: public void feed () { this.fed = true; Furthermore, the getter for the fed variable could be named is Fed as it is more descriptive about what it answers when compared to get Fed. Keep this technique in mind for future class designs. Zoo (10) Now we have the animals designed and ready for building a little Zoo! Build a class…

1.[30 pts] Answer the following questions: a. [10 pts] Write a Boolean equation in sum-of-products canonical form for the truth table shown below: A B C Y 0 0 0 1 0 0 1 0 0 1 0 0 0 1 1 0 1 0 0 1 1 0 1 0 1 1 0 1 1 1 1 0 a. [10 pts] Minimize the Boolean equation you obtained in (a). b. [10 pts] Implement, using Logisim, the simplified logic circuit. Include an image of the circuit in your report. 2. [20 pts] Student A B will enjoy his picnic on sunny days that have no ants. He will also enjoy his picnic any day he sees a hummingbird, as well as on days where there are ants and ladybugs. a. Write a Boolean equation for his enjoyment (E) in terms of sun (S), ants (A), hummingbirds (H), and ladybugs (L). b. Implement in Logisim, the logic circuit of E function. Use the Circuit Analysis tool in Logisim to view the expression, include an image of the expression generated by Logisim in your report. 3.[20 pts] Find the minimum equivalent circuit for the one shown below (show your work): DAB C…

P = A piston having a cross-sectional area of 0.40 m² is located in a cylinder containing water as shown in the figure below. An open U-tube manometer is connected to the cylinder as shown. For h₁ = 83 mm and h = 111 mm what is the value of the applied force, P, acting on the piston? The weight of the piston is negligible. Hi 5597.97 N P Piston Water Mercury

Answer 2

Question

Chapter 14, Problem 14.1P

Interpretation Introduction

Interpretation:

The cost of material per unit volume is more important in some cases than the cost per unit weight. The cost needs to be determined in terms of $/cm3. Whether this affects the relationship between the different materials or not needs to be explained.

Concept Introduction:

Specific strength can be calculated as follows:

Specific strength = strength Mass density

It relates the specific strengths of steel, few high strength non-ferrous alloys, and polymer- matrix composites. Additional factor to study in designing with non-ferrous material is their rate, which also differs significantly.

Expert Solution & Answer

Explanation of Solution

Table no.1

Metal	Density(g/ cm3)	Cost per kg($/kg)	Rank

Steels	7.87	0.22	1
Zinc	7.13	0.88	2
Lead	11.36	0.99	3
Aluminium	2.70	1.32	4
Copper	8.93	1.57	5
Magnesium	1.74	3.31	6
Titanium	4.51	8.82	7
Tungsten	19.25	8.82	8
Nickel	8.90	9.04	9
Beryllium	1.85	777.60	10

The cost of a material per unit volume can be converted from ($/kg) to ($/g) by dividing the cost of material by 1000, and multiplying the converted cost value with density.

Table no. 2

Metal	Density	Cost per kg	Cost per gram	Cost per volume	Rank

Steel	7.87	0.22	0.22 ×10−3	0.0017	1
Aluminium	2.70	1.32	1.32 ×10−3	0.0036	2
Magnesium	1.74	3.31	3.31 ×10−3	0.0057	3
Zinc	7.13	0.88	0.88 ×10−3	0.0063	4
Lead	11.36	0.99	0.99 ×10−3	0.0013	5
Copper	8.93	1.57	1.57 ×10−3	0.0140	6
Titanium	4.51	8.82	8.82 ×10−3	0.0397	7
Nickel	8.90	9.04	9.04 ×10−3	0.0804	8
Tungsten	19.25	8.82	8.82 ×10−3	0.1696	9
Beryllium	1.85	771.60	771.60 ×10−3	1.4247	10

From the above two tables, the different materials are related to each other in terms of cost per kilogram and cost per volume.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 14, Problem 14.1P

Interpretation Introduction

Interpretation:

The cost of material per unit volume is more important in some cases than the cost per unit weight. The cost needs to be determined in terms of $/cm3. Whether this affects the relationship between the different materials or not needs to be explained.

Concept Introduction:

Specific strength can be calculated as follows:

Specific strength = strength Mass density

It relates the specific strengths of steel, few high strength non-ferrous alloys, and polymer- matrix composites. Additional factor to study in designing with non-ferrous material is their rate, which also differs significantly.

Expert Solution & Answer

Explanation of Solution

Table no.1

Metal	Density(g/ cm3)	Cost per kg($/kg)	Rank

Steels	7.87	0.22	1
Zinc	7.13	0.88	2
Lead	11.36	0.99	3
Aluminium	2.70	1.32	4
Copper	8.93	1.57	5
Magnesium	1.74	3.31	6
Titanium	4.51	8.82	7
Tungsten	19.25	8.82	8
Nickel	8.90	9.04	9
Beryllium	1.85	777.60	10

The cost of a material per unit volume can be converted from ($/kg) to ($/g) by dividing the cost of material by 1000, and multiplying the converted cost value with density.

Table no. 2

Metal	Density	Cost per kg	Cost per gram	Cost per volume	Rank

Steel	7.87	0.22	0.22 ×10−3	0.0017	1
Aluminium	2.70	1.32	1.32 ×10−3	0.0036	2
Magnesium	1.74	3.31	3.31 ×10−3	0.0057	3
Zinc	7.13	0.88	0.88 ×10−3	0.0063	4
Lead	11.36	0.99	0.99 ×10−3	0.0013	5
Copper	8.93	1.57	1.57 ×10−3	0.0140	6
Titanium	4.51	8.82	8.82 ×10−3	0.0397	7
Nickel	8.90	9.04	9.04 ×10−3	0.0804	8
Tungsten	19.25	8.82	8.82 ×10−3	0.1696	9
Beryllium	1.85	771.60	771.60 ×10−3	1.4247	10

From the above two tables, the different materials are related to each other in terms of cost per kilogram and cost per volume.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 14, Problem 14.1P

Interpretation Introduction

Interpretation:

The cost of material per unit volume is more important in some cases than the cost per unit weight. The cost needs to be determined in terms of $/cm3. Whether this affects the relationship between the different materials or not needs to be explained.

Concept Introduction:

Specific strength can be calculated as follows:

Specific strength = strength Mass density

It relates the specific strengths of steel, few high strength non-ferrous alloys, and polymer- matrix composites. Additional factor to study in designing with non-ferrous material is their rate, which also differs significantly.

Expert Solution & Answer

Explanation of Solution

Table no.1

Metal	Density(g/ cm3)	Cost per kg($/kg)	Rank

Steels	7.87	0.22	1
Zinc	7.13	0.88	2
Lead	11.36	0.99	3
Aluminium	2.70	1.32	4
Copper	8.93	1.57	5
Magnesium	1.74	3.31	6
Titanium	4.51	8.82	7
Tungsten	19.25	8.82	8
Nickel	8.90	9.04	9
Beryllium	1.85	777.60	10

The cost of a material per unit volume can be converted from ($/kg) to ($/g) by dividing the cost of material by 1000, and multiplying the converted cost value with density.

Table no. 2

Metal	Density	Cost per kg	Cost per gram	Cost per volume	Rank

Steel	7.87	0.22	0.22 ×10−3	0.0017	1
Aluminium	2.70	1.32	1.32 ×10−3	0.0036	2
Magnesium	1.74	3.31	3.31 ×10−3	0.0057	3
Zinc	7.13	0.88	0.88 ×10−3	0.0063	4
Lead	11.36	0.99	0.99 ×10−3	0.0013	5
Copper	8.93	1.57	1.57 ×10−3	0.0140	6
Titanium	4.51	8.82	8.82 ×10−3	0.0397	7
Nickel	8.90	9.04	9.04 ×10−3	0.0804	8
Tungsten	19.25	8.82	8.82 ×10−3	0.1696	9
Beryllium	1.85	771.60	771.60 ×10−3	1.4247	10

From the above two tables, the different materials are related to each other in terms of cost per kilogram and cost per volume.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 14, Problem 14.1P

Interpretation Introduction

Interpretation:

The cost of material per unit volume is more important in some cases than the cost per unit weight. The cost needs to be determined in terms of $/cm3. Whether this affects the relationship between the different materials or not needs to be explained.

Concept Introduction:

Specific strength can be calculated as follows:

Specific strength = strength Mass density

It relates the specific strengths of steel, few high strength non-ferrous alloys, and polymer- matrix composites. Additional factor to study in designing with non-ferrous material is their rate, which also differs significantly.

Expert Solution & Answer

Explanation of Solution

Table no.1

Metal	Density(g/ cm3)	Cost per kg($/kg)	Rank

Steels	7.87	0.22	1
Zinc	7.13	0.88	2
Lead	11.36	0.99	3
Aluminium	2.70	1.32	4
Copper	8.93	1.57	5
Magnesium	1.74	3.31	6
Titanium	4.51	8.82	7
Tungsten	19.25	8.82	8
Nickel	8.90	9.04	9
Beryllium	1.85	777.60	10

The cost of a material per unit volume can be converted from ($/kg) to ($/g) by dividing the cost of material by 1000, and multiplying the converted cost value with density.

Table no. 2

Metal	Density	Cost per kg	Cost per gram	Cost per volume	Rank

Steel	7.87	0.22	0.22 ×10−3	0.0017	1
Aluminium	2.70	1.32	1.32 ×10−3	0.0036	2
Magnesium	1.74	3.31	3.31 ×10−3	0.0057	3
Zinc	7.13	0.88	0.88 ×10−3	0.0063	4
Lead	11.36	0.99	0.99 ×10−3	0.0013	5
Copper	8.93	1.57	1.57 ×10−3	0.0140	6
Titanium	4.51	8.82	8.82 ×10−3	0.0397	7
Nickel	8.90	9.04	9.04 ×10−3	0.0804	8
Tungsten	19.25	8.82	8.82 ×10−3	0.1696	9
Beryllium	1.85	771.60	771.60 ×10−3	1.4247	10

From the above two tables, the different materials are related to each other in terms of cost per kilogram and cost per volume.

Answer 6

Chapter 14, Problem 14.1P

Interpretation Introduction

Interpretation:

The cost of material per unit volume is more important in some cases than the cost per unit weight. The cost needs to be determined in terms of $/cm3. Whether this affects the relationship between the different materials or not needs to be explained.

Concept Introduction:

Specific strength can be calculated as follows:

Specific strength = strength Mass density

It relates the specific strengths of steel, few high strength non-ferrous alloys, and polymer- matrix composites. Additional factor to study in designing with non-ferrous material is their rate, which also differs significantly.

Expert Solution & Answer

Explanation of Solution

Table no.1

Metal	Density(g/ cm3)	Cost per kg($/kg)	Rank

Steels	7.87	0.22	1
Zinc	7.13	0.88	2
Lead	11.36	0.99	3
Aluminium	2.70	1.32	4
Copper	8.93	1.57	5
Magnesium	1.74	3.31	6
Titanium	4.51	8.82	7
Tungsten	19.25	8.82	8
Nickel	8.90	9.04	9
Beryllium	1.85	777.60	10

The cost of a material per unit volume can be converted from ($/kg) to ($/g) by dividing the cost of material by 1000, and multiplying the converted cost value with density.

Table no. 2

Metal	Density	Cost per kg	Cost per gram	Cost per volume	Rank

Steel	7.87	0.22	0.22 ×10−3	0.0017	1
Aluminium	2.70	1.32	1.32 ×10−3	0.0036	2
Magnesium	1.74	3.31	3.31 ×10−3	0.0057	3
Zinc	7.13	0.88	0.88 ×10−3	0.0063	4
Lead	11.36	0.99	0.99 ×10−3	0.0013	5
Copper	8.93	1.57	1.57 ×10−3	0.0140	6
Titanium	4.51	8.82	8.82 ×10−3	0.0397	7
Nickel	8.90	9.04	9.04 ×10−3	0.0804	8
Tungsten	19.25	8.82	8.82 ×10−3	0.1696	9
Beryllium	1.85	771.60	771.60 ×10−3	1.4247	10

From the above two tables, the different materials are related to each other in terms of cost per kilogram and cost per volume.

Answer 7

Chapter 14, Problem 14.1P

Interpretation Introduction

Interpretation:

The cost of material per unit volume is more important in some cases than the cost per unit weight. The cost needs to be determined in terms of $/cm3. Whether this affects the relationship between the different materials or not needs to be explained.

Concept Introduction:

Specific strength can be calculated as follows:

Specific strength = strength Mass density

It relates the specific strengths of steel, few high strength non-ferrous alloys, and polymer- matrix composites. Additional factor to study in designing with non-ferrous material is their rate, which also differs significantly.

Answer 8

Expert Solution & Answer

Explanation of Solution

Table no.1

Metal	Density(g/ cm3)	Cost per kg($/kg)	Rank

Steels	7.87	0.22	1
Zinc	7.13	0.88	2
Lead	11.36	0.99	3
Aluminium	2.70	1.32	4
Copper	8.93	1.57	5
Magnesium	1.74	3.31	6
Titanium	4.51	8.82	7
Tungsten	19.25	8.82	8
Nickel	8.90	9.04	9
Beryllium	1.85	777.60	10

The cost of a material per unit volume can be converted from ($/kg) to ($/g) by dividing the cost of material by 1000, and multiplying the converted cost value with density.

Table no. 2

Metal	Density	Cost per kg	Cost per gram	Cost per volume	Rank

Steel	7.87	0.22	0.22 ×10−3	0.0017	1
Aluminium	2.70	1.32	1.32 ×10−3	0.0036	2
Magnesium	1.74	3.31	3.31 ×10−3	0.0057	3
Zinc	7.13	0.88	0.88 ×10−3	0.0063	4
Lead	11.36	0.99	0.99 ×10−3	0.0013	5
Copper	8.93	1.57	1.57 ×10−3	0.0140	6
Titanium	4.51	8.82	8.82 ×10−3	0.0397	7
Nickel	8.90	9.04	9.04 ×10−3	0.0804	8
Tungsten	19.25	8.82	8.82 ×10−3	0.1696	9
Beryllium	1.85	771.60	771.60 ×10−3	1.4247	10

From the above two tables, the different materials are related to each other in terms of cost per kilogram and cost per volume.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Ch. 14 - Prob. 14.1P Ch. 14 - Prob. 14.2P Ch. 14 - Prob. 14.3P Ch. 14 - Prob. 14.4P Ch. 14 - Prob. 14.5P Ch. 14 - Prob. 14.6P Ch. 14 - Prob. 14.7P Ch. 14 - Prob. 14.8P Ch. 14 - Prob. 14.9P Ch. 14 - Prob. 14.10P

Explanation of Solution

Want to see more full solutions like this?

Chapter 14 Solutions