Get Ready for Organic Chemistry
Get Ready for Organic Chemistry
2nd Edition
ISBN: 9780321774125
Author: KARTY, Joel
Publisher: PEARSON
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Chapter 14, Problem 14.18P
Interpretation Introduction

(a)

Interpretation:

Whether the given compound is aromatic, antiaromatic, or nonaromatic is to be determined.

Concept introduction:

The rule for aromaticity applies only if the system is planar, cyclic, and has a continuous overlap of p-orbitals.

As per Huckel’s rules for aromaticity, the molecule must possess a pi system of molecular orbitals constructed from p-orbitals that are fully conjugated around a ring. The number of electrons in the π system must be (4n + 2), n = 0, 1, 2, ...

If the number of electrons in the π system is 4n, n = 0, 1, 2, ..., the compound is antiaromatic.

All other compounds are nonaromatic.

Interpretation Introduction

(b)

Interpretation:

Whether the given compound is aromatic, antiaromatic, or nonaromatic is to be determined.

Concept introduction:

The rule for aromaticity applies only if the system is planar, cyclic, and has a continuous overlap of p-orbitals.

As per Huckel’s rule for aromaticity, The molecule must possess a pi system of molecular orbitals constructed from p-orbitals that are fully conjugated around a ring. The number of electrons in the π system must be (4n + 2), n = 0, 1, 2, ...

If the number of electrons in the π system is 4n, n = 0, 1, 2, ..., the compound is antiaromatic.

All other compounds are nonaromatic.

Interpretation Introduction

(c)

Interpretation:

Whether the given compound is aromatic, antiaromatic, or nonaromatic is to be determined.

Concept introduction:

The rule for aromaticity applies only if the system is planar, cyclic, and has a continuous overlap of p-orbitals.

As per Huckel’s rule for aromaticity, the molecule must possess a π system of molecular orbitals constructed from p-orbitals that are fully conjugated around a ring. The number of electrons in the π system must be (4n + 2), n = 0, 1, 2, ...

If the number of electrons in the π system is 4n, n = 0, 1, 2, ..., the compound is antiaromatic.

All other compounds are nonaromatic.

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Chapter 14 Solutions

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