Explanation If total number of alpha particles incident on the silver foil is N i n c = 10 10 . Differential cross section is d σ d Ω = 0.5 barn/sr . The counter is a distance r = 1 cm from the scattering surface. Surface area of the counter is A = 0.1 mm 2 . Solid angle subtended would be d Ω = A r 2 = 0.1 mm 2 ( 10 − 6 m 2 1 mm 2 ) 1 cm ( 10 − 2 m 1 cm ) = 10 − 3 Density of silver is 10.5 × 10 3 kg/m 3 . Number of silver atoms in 1 kg of silver are 6.023 × 10 23 × 10 3 108 atoms/kg . Thus number of silver per unit volume is given by 10.5 × 10 3 kg/m 3 ( 6

Total number of scattered alpha particles.

Classical Mechanics

5th Edition

ISBN: 9781891389221

Author: John R. Taylor

Publisher: University Science Books

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Rutherford's scattering experiment

Rutherford’s scattering experiment is also known as the gold foil experiment. This experiment disproved the plum pudding model of J.J. Thomson. In a gold foil experiment, high-energy alpha particles are made to strike a thin gold foil. The scattered alph…

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Chapter 14, Problem 14.11P

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Total number of scattered alpha particles.

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