Chemistry
4th Edition
ISBN: 9780393919370
Author: Thomas R. Gilbert
Publisher: NORTON
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Chapter 14, Problem 14.116QP
Interpretation Introduction
Interpretation: The reactions involved in the depletion of Ozone are given. The reason behind the role of
Concept introduction: The minimum amount of energy that is required for a reaction to occur is known as the activation energy.
To determine: The reason behind the role of
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Please help, this is all the calculations
i got!!! I will rate!!!Approx mass of
KMnO in vial: 3.464
4
Moss of beaker 3×~0. z Nax200:
= 29.9219
Massof weacerv after remosimgain
N2C2O4. Need to fill in all the
missing blanks.
ง
ง
Approx mass of KMnO4 in vials 3.464
Mass of beaker + 3x ~0-304: 29.9219
2~0.20
Miss of beaker + 2x-
29.7239
Mass of beaker + 1x~0.2g Naz (204
29-5249
Mass of beaver after removing as
qa Na₂ C₂O
T1
T2
T3
Final Buiet reading
Initial butet reading (int))
Hass of NaOr used for Titration
-reading (mL)
calculation Results:
8.5ml
17mL
27.4mL
Oml
Om
Oml
T1
T2
T3
Moles of No CO
Moles of KMO used
LOF KM. O used
Molenty of KMNO
Averagem Of KMOWL
Draw the skeletal ("line") structure of 2-hydroxy-4-methylpentanal.
Click and drag to start drawing a
structure.
X
Determine whether the following molecule is a hemiacetal, acetal, or neither and select the appropriate box below.
Also, highlight the hemiacetal or acetal carbon if there is one.
hemiacetal acetal Oneither
OH
Chapter 14 Solutions
Chemistry
Ch. 14.2 - Prob. 1PECh. 14.2 - Prob. 2PECh. 14.2 - Prob. 3PECh. 14.3 - Prob. 4PECh. 14.3 - Prob. 5PECh. 14.3 - Prob. 6PECh. 14.3 - Prob. 7PECh. 14.3 - Prob. 8PECh. 14.3 - Prob. 9PECh. 14.3 - Prob. 10PE
Ch. 14.4 - Prob. 11PECh. 14.5 - Prob. 12PECh. 14.5 - Prob. 13PECh. 14.6 - Prob. 14PECh. 14 - Prob. 14.1VPCh. 14 - Prob. 14.2VPCh. 14 - Prob. 14.3VPCh. 14 - Prob. 14.4VPCh. 14 - Prob. 14.5VPCh. 14 - Prob. 14.6VPCh. 14 - Prob. 14.7VPCh. 14 - Prob. 14.8VPCh. 14 - Prob. 14.9VPCh. 14 - Prob. 14.10VPCh. 14 - Prob. 14.11VPCh. 14 - Prob. 14.12VPCh. 14 - Prob. 14.13VPCh. 14 - Prob. 14.14VPCh. 14 - Prob. 14.15VPCh. 14 - Prob. 14.16VPCh. 14 - Prob. 14.17QPCh. 14 - Prob. 14.18QPCh. 14 - Prob. 14.19QPCh. 14 - Prob. 14.20QPCh. 14 - Prob. 14.21QPCh. 14 - Prob. 14.22QPCh. 14 - Prob. 14.23QPCh. 14 - Prob. 14.24QPCh. 14 - Prob. 14.25QPCh. 14 - Prob. 14.26QPCh. 14 - Prob. 14.27QPCh. 14 - Prob. 14.28QPCh. 14 - Prob. 14.29QPCh. 14 - Prob. 14.30QPCh. 14 - Prob. 14.31QPCh. 14 - Prob. 14.32QPCh. 14 - Prob. 14.33QPCh. 14 - Prob. 14.34QPCh. 14 - Prob. 14.35QPCh. 14 - Prob. 14.36QPCh. 14 - Prob. 14.37QPCh. 14 - Prob. 14.38QPCh. 14 - Prob. 14.39QPCh. 14 - Prob. 14.40QPCh. 14 - Prob. 14.41QPCh. 14 - Prob. 14.42QPCh. 14 - Prob. 14.43QPCh. 14 - Prob. 14.44QPCh. 14 - Prob. 14.45QPCh. 14 - Prob. 14.46QPCh. 14 - Prob. 14.47QPCh. 14 - Prob. 14.48QPCh. 14 - Prob. 14.49QPCh. 14 - Prob. 14.50QPCh. 14 - Prob. 14.51QPCh. 14 - Prob. 14.52QPCh. 14 - Prob. 14.53QPCh. 14 - Prob. 14.54QPCh. 14 - Prob. 14.55QPCh. 14 - Prob. 14.56QPCh. 14 - Prob. 14.57QPCh. 14 - Prob. 14.58QPCh. 14 - Prob. 14.59QPCh. 14 - Prob. 14.60QPCh. 14 - Prob. 14.61QPCh. 14 - Prob. 14.62QPCh. 14 - Prob. 14.63QPCh. 14 - Prob. 14.64QPCh. 14 - Prob. 14.65QPCh. 14 - Prob. 14.66QPCh. 14 - Prob. 14.67QPCh. 14 - Prob. 14.68QPCh. 14 - Prob. 14.69QPCh. 14 - Prob. 14.70QPCh. 14 - Prob. 14.71QPCh. 14 - Prob. 14.72QPCh. 14 - Prob. 14.73QPCh. 14 - Prob. 14.74QPCh. 14 - Prob. 14.75QPCh. 14 - Prob. 14.76QPCh. 14 - Prob. 14.77QPCh. 14 - Prob. 14.78QPCh. 14 - Prob. 14.79QPCh. 14 - Prob. 14.80QPCh. 14 - Prob. 14.81QPCh. 14 - Prob. 14.82QPCh. 14 - Prob. 14.83QPCh. 14 - Prob. 14.84QPCh. 14 - Prob. 14.85QPCh. 14 - Prob. 14.86QPCh. 14 - Prob. 14.87QPCh. 14 - Prob. 14.88QPCh. 14 - Prob. 14.89QPCh. 14 - Prob. 14.90QPCh. 14 - Prob. 14.91QPCh. 14 - Prob. 14.93QPCh. 14 - Prob. 14.94QPCh. 14 - Prob. 14.95QPCh. 14 - Prob. 14.96QPCh. 14 - Prob. 14.97QPCh. 14 - Prob. 14.98QPCh. 14 - Prob. 14.99QPCh. 14 - Prob. 14.100QPCh. 14 - Prob. 14.101QPCh. 14 - Prob. 14.102QPCh. 14 - Prob. 14.103QPCh. 14 - Prob. 14.104QPCh. 14 - Prob. 14.105QPCh. 14 - Prob. 14.106QPCh. 14 - Prob. 14.107QPCh. 14 - Prob. 14.108QPCh. 14 - Prob. 14.109QPCh. 14 - Prob. 14.110QPCh. 14 - Prob. 14.111QPCh. 14 - Prob. 14.112QPCh. 14 - Prob. 14.113QPCh. 14 - Prob. 14.114QPCh. 14 - Prob. 14.115QPCh. 14 - Prob. 14.116QPCh. 14 - Prob. 14.117QPCh. 14 - Prob. 14.118QPCh. 14 - Prob. 14.119APCh. 14 - Prob. 14.120APCh. 14 - Prob. 14.121APCh. 14 - Prob. 14.122APCh. 14 - Prob. 14.123APCh. 14 - Prob. 14.124APCh. 14 - Prob. 14.125APCh. 14 - Prob. 14.126APCh. 14 - Prob. 14.127APCh. 14 - Prob. 14.128APCh. 14 - Prob. 14.129APCh. 14 - Prob. 14.130APCh. 14 - Prob. 14.131APCh. 14 - Prob. 14.132APCh. 14 - Prob. 14.133APCh. 14 - Prob. 14.134APCh. 14 - Prob. 14.135APCh. 14 - Prob. 14.136APCh. 14 - Prob. 14.137APCh. 14 - Prob. 14.138APCh. 14 - Prob. 14.139APCh. 14 - Prob. 14.140APCh. 14 - Prob. 14.141AP
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- What is the missing reactant R in this organic reaction? ་ ་ ་ ་ ་ ་ ་ ་ ་ ་ +R H3O+ • Draw the structure of R in the drawing area below. N • Be sure to use wedge and dash bonds if it's necessary to draw one particular enantiomer. Click and drag to start drawing a structure.arrow_forwardWrite the systematic name of each organic molecule: H structure H OH OH H OH name ☐ OHarrow_forwardDetermine whether each of the following molecules is a hemiacetal, acetal, or neither and select the appropriate box in the table. CH3O OH OH OH hemiacetal acetal neither hemiacetal acetal neither Xarrow_forward
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- -AG|F=2E|V 3. Before proceeding with this problem you may want to glance at p. 466 of your textbook where various oxo-phosphorus derivatives and their oxidation states are summarized. Shown below are Latimer diagrams for phosphorus at pH values at 0 and 14: Acidic solution -0.93 +0.38 -0.51 -0.06 H3PO4 →H4P206 H3PO3 H3PO2 → P→ PH3 -0.28 -0.50 → -0.50 Basic solution 3-1.12 -1.57 -2.05 -0.89 PO HPO →→H2PO2 P PH3 -1.73 a) Under acidic conditions, H3PO4 can be reduced into H3PO3 directly (-0.28V), or via the formation and reduction of H4P2O6 (-0.93/+0.38V). Calculate the values of AG's for both processes; comment. (3 points) 0.5 PH, 0.0 -0.5- 2 3 9 3 -1.5 -2.0 Pa H,PO H,PO H,PO -3 -1 0 2 4 Oxidation state, N 2 b) Frost diagram for phosphorus under acidic conditions is shown. Identify possible disproportionation and comproportionation processes; write out chemical equations describing them. (2 points) c) Elemental phosphorus tends to disproportionate under basic conditions. Use data in…arrow_forwardThese two reactions appear to start with the same starting materials but result in different products. How do the chemicals know which product to form? Are both products formed, or is there some information missing that will direct them a particular way?arrow_forwardWhat would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 3 1 2 2. n-BuLi • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. • Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Explanation Check Click and drag to start drawing a structure. 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Priva ×arrow_forward
- Predict the products of this organic reaction: Explanation Check IN NaBH3CN H+ ? Click and drag to start drawing a structure. D 5 C +arrow_forwardPredict the products of this organic reaction: H3O+ + ? • Draw all the reasonable products in the drawing area below. If there are no products, because no reaction will occur, check the box under the drawing area. • Include both major and minor products, if some of the products will be more common than others. • Be sure to use wedge and dash bonds if you need to distinguish between enantiomers. No reaction. Click and drag to start drawing a structure. dmarrow_forwardIarrow_forward
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