
(a)
Interpretation:
Lewis structure of
Concept-Introduction:
Lewis structure:
Electron dot structure also known as Lewis dot structure represents the number of valence electrons of an atom or constituent atoms bonded in a molecule. Each dot corresponds to one electron.
(b)
Interpretation:
MO diagrams of
Concept-Introduction:
Molecular orbital (MO) theory: It is a method for determining molecular structure in which electrons are not assigned to individual bonds between atoms, but are treated as moving under the influence of the nuclei in the whole molecule.
According to this theory there are two types of orbitals,
- (1) Bonding orbitals
- (2) Antibonding orbitals
Electrons in molecules are filled in accordance with the energy; the anti-bonding orbital has more energy than the bonding orbitals.
The electronic configuration of oxygen molecule
The * represent the antibonding orbital
Orbital diagram represents each orbital with a box, with orbital’s in the same subshell in connected boxes, electrons are shown as arrows in the boxes, pointing up or down to indicate their spins.
Bond order: It is the measure of number of electron pairs shared between two atoms.
Bond length is inversely proportional to the bond order.
If two or more different chemical species having same number of valence electrons are known as isoelectronic species.

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Chapter 14 Solutions
Chemistry: The Molecular Nature of Matter and Change
- Using a cell of known pathlength b = 1.25115 x 10-3 cm, a water absorption spectrum was measured. The band at 1645 cm-1, assigned to the O-H bending, showed an absorbance, A, of 1.40. a) Assuming that water density is 1.00 g/mL, calculate the water molar concentration c (hint: M= mole/L) b) Calculate the molar absorptivity, a, of the 1645 cm-1 band c) The transmitted light, I, can be written as I= Ioexp(-xb), where x is the absorption coefficient (sometimes designated as alpha), Io is the input light, and b is the cell pathlength. Prove that x= (ln10)*x*c. (Please provide a full derivation of the equation for x from the equation for I). d) Calculate x for the 1645 cm-1 bandarrow_forwardI need help with the follloaingarrow_forwardFor a CARS experiment on a Raman band 918 cm-1, if omega1= 1280 nm, calculate the omega2 in wavelength (nm) and the CARS output in wavelength (nm).arrow_forward
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- Using a cell of known pathlength b = 1.25115 x 10-3 cm, a water absorption spectrum was measured. The band at 1645 cm-1, assigned to the O-H bending, showed an absorbance, A, of 1.40. a) Assuming that water density is 1.00 g/mL, calculate the water molar concentration c (hint: M= mole/L) b) Calculate the molar absorptivity, a, of the 1645 cm-1 band c) The transmitted light, I, can be written as I= Ioexp(-xb), where x is the absorption coefficient (sometimes designated as alpha), Io is the input light, and b is the cell pathlength. Prove that x= (ln10)*x*c d) Calculate x for the 1645 cm-1 bandarrow_forwardConvert 1.38 eV into wavelength (nm) and wavenumber (cm-1) (c = 2.998 x 108 m/s; h = 6.626 x 10-34 J*s).arrow_forwardCan you help me understand the CBC method on metal bridging by looking at this problem?arrow_forward
- A partir de Aluminio y Co(NO3)2ꞏ6H2O, indicar las reacciones a realizar para obtener Azul de Thenard (Al2CoO4).arrow_forwardTo obtain Thenard Blue (Al2CoO4), the following reaction is correct (performed in an oven):Al(OH)3 + Co(OH)2 → Al2CoO4 + 4 H2Oarrow_forwardProblem 38 can u explain and solve thanks april 24arrow_forward
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