Physics, 11e WileyPLUS + Loose-leaf
11th Edition
ISBN: 9781119394112
Author: John D. Cutnell, Kenneth W. Johnson, David Young, Shane Stadler
Publisher: Wiley (WileyPLUS Products)
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Chapter 14, Problem 13P
(a)
To determine
To Find: The number of moles of gas.
(b)
To determine
To Find: The pressure of the gas when volume and temperature are raised.
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Three charged particles are located at the corners of an equilateral triangle as shown in the figure below (let q = 1.00 μC, and L = 0.850 m). Calculate the total electric force on the 7.00-μC charge.
magnitude
direction
N
° (counterclockwise from the +x axis)
y
7.00 με
9
L
60.0°
x
-4.00 μC ①
(a) Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 9.0 g. Silver has 47 electrons per atom, and its molar mass is 107.87 g/mol.
(b) Imagine adding electrons to the pin until the negative charge has the very large value 1.00 mC. How many electrons are added for every 109 electrons already present?
(a) A physics lab instructor is working on a new demonstration. She attaches two identical copper spheres with mass m = 0.180 g to cords of length L as shown in the figure.
A
Both spheres have the same charge of 6.80 nC, and are in static equilibrium when 0 = 4.95°. What is L (in m)? Assume the cords are massless.
0.180
Draw a free-body diagram, apply Newton's second law for a particle in equilibrium to one of the spheres. Find an equation for the distance between the two spheres in terms of L and 0, and use this expression in your
Coulomb force equation. m
(b) What If? The charge on both spheres is increased until each cord makes an angle of 0 = 9.90° with the vertical. If both spheres have the same electric charge, what is the charge (in nC) on each sphere in this case?
9.60
Use the same reasoning as in part (a), only now, use the length found in part (a) and the new angle to solve for the charge. nc
Chapter 14 Solutions
Physics, 11e WileyPLUS + Loose-leaf
Ch. 14 - Hemoglobin has a molecular mass of 64500u. Find...Ch. 14 - Prob. 2PCh. 14 - Prob. 3PCh. 14 - Prob. 4PCh. 14 - Prob. 5PCh. 14 - Prob. 6PCh. 14 - Prob. 7PCh. 14 - Prob. 8PCh. 14 - Prob. 10PCh. 14 - Prob. 11P
Ch. 14 - Prob. 12PCh. 14 - Prob. 13PCh. 14 - Prob. 15PCh. 14 - Prob. 16PCh. 14 - Prob. 17PCh. 14 - Prob. 18PCh. 14 - Prob. 20PCh. 14 - Prob. 21PCh. 14 - Prob. 22PCh. 14 - Prob. 24PCh. 14 - Prob. 25PCh. 14 - Prob. 27PCh. 14 - Prob. 29PCh. 14 - Prob. 30PCh. 14 - Prob. 32PCh. 14 - Prob. 33PCh. 14 - Prob. 35PCh. 14 - Prob. 36PCh. 14 - Prob. 38PCh. 14 - Prob. 40PCh. 14 - Prob. 41PCh. 14 - Prob. 42PCh. 14 - Prob. 44PCh. 14 - Prob. 45PCh. 14 - Prob. 46PCh. 14 - Prob. 48PCh. 14 - Prob. 53APCh. 14 - Prob. 55APCh. 14 - Prob. 56APCh. 14 - Prob. 58APCh. 14 - Prob. 59APCh. 14 - Prob. 62APCh. 14 - Prob. 65AP
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