
The data in the table are for the reaction of NO and O2 at 660 K.
NO(g) + ½ O2(g) → NO2(g)
- (a) Determine the order of the reaction for each reactant.
- (b) Write the rate equation for the reaction.
- (c) Calculate the rate constant.
- (d) Calculate the rate (in mol/L · s) at the instant when [NO] = 0.015 mol/L and [O2] = 0.0050 mol/L.
- (e) At the instant when NO is reacting at the rate 1.0 × 10−4 mol/L · s, what is the rate at which O2 is reacting and NO2 is forming?
(a)

Interpretation:
The order of the reaction for each reactant has to be determined
Concept Introduction:
Rate law or rate equation: The relationship between the reactant concentrations and reaction rate is expressed by an equation.
Order of a reaction: The order of a reaction with respect to a particular reactant is the exponent of its concentration term in the rate law expression, and the overall reaction order is the sum of the exponents on all concentration terms.
Rate constant, k: It is a proportionality constant that relates rate and concentration at a given temperature.
Answer to Problem 11PS
The order of
Explanation of Solution
The reaction rate of the chemical reaction is given as,
In order to figure out the reaction equation the order of the reactants needed, which is calculated by comparing any two experiments where the concentration of
(b)

Interpretation:
The rate equation for the reaction has to be written.
Concept Introduction:
Rate law or rate equation: The relationship between the reactant concentrations and reaction rate is expressed by an equation.
Order of a reaction: The order of a reaction with respect to a particular reactant is the exponent of its concentration term in the rate law expression, and the overall reaction order is the sum of the exponents on all concentration terms.
Rate constant, k: It is a proportionality constant that relates rate and concentration at a given temperature.
Answer to Problem 11PS
The rate equation is
Explanation of Solution
The reaction rate is given as,
Hence, Rate equation is
(c)

Interpretation:
The rate constant has to be calculated.
Concept Introduction:
Rate law or rate equation: The relationship between the reactant concentrations and reaction rate is expressed by an equation.
Order of a reaction: The order of a reaction with respect to a particular reactant is the exponent of its concentration term in the rate law expression, and the overall reaction order is the sum of the exponents on all concentration terms.
Rate constant, k: It is a proportionality constant that relates rate and concentration at a given temperature.
Answer to Problem 11PS
The value of rate constant is
Explanation of Solution
The rate constant is calculated as,
The rate constant value is obtained as shown above. By substituting the any one of the concentrations of reactants and the initial rate into the reaction equation obtained at first.
Hence, the value of rate constant is
(d)

Interpretation:
The rate in
Concept Introduction:
Rate law or rate equation: The relationship between the reactant concentrations and reaction rate is expressed by an equation.
Order of a reaction: The order of a reaction with respect to a particular reactant is the exponent of its concentration term in the rate law expression, and the overall reaction order is the sum of the exponents on all concentration terms.
Rate constant, k: It is a proportionality constant that relates rate and concentration at a given temperature.
Answer to Problem 11PS
The instantaneous rate of the reaction is
Explanation of Solution
The rate is calculated as,
The instantaneous rate of the reaction is
(e)

Interpretation:
The rate at which
Concept Introduction:
Rate law or rate equation: The relationship between the reactant concentrations and reaction rate is expressed by an equation.
Order of a reaction: The order of a reaction with respect to a particular reactant is the exponent of its concentration term in the rate law expression, and the overall reaction order is the sum of the exponents on all concentration terms.
Rate constant, k: It is a proportionality constant that relates rate and concentration at a given temperature.
Answer to Problem 11PS
The rate when oxygen reacting is
Explanation of Solution
The rate is calculated as,
The rate when oxygen reacting is
Want to see more full solutions like this?
Chapter 14 Solutions
Chemistry & Chemical Reactivity
Additional Science Textbook Solutions
Microbiology Fundamentals: A Clinical Approach
Fundamentals Of Thermodynamics
Campbell Essential Biology (7th Edition)
Biology: Life on Earth with Physiology (11th Edition)
Physical Science
Organic Chemistry
- Indicate the variation in conductivity with concentration in solutions of strong electrolytes and weak electrolytes.arrow_forwardThe molar conductivity of a very dilute solution of NaCl has been determined. If it is diluted to one-fourth of the initial concentration, qualitatively explain how the molar conductivity of the new solution will compare with the first.arrow_forwardWhat does the phrase mean, if instead of 1 Faraday of electricity, Q coulombs (Q/F Faradays) pass through?arrow_forward
- What characteristics should an interface that forms an electrode have?arrow_forwardFor a weak acid AcH, calculate the dissociated fraction (alpha), if its concentration is 1.540 mol L-1 and the concentration [H+] is 5.01x10-4 mol L-1.arrow_forwardIf the molar conductivity at infinite dilution of HAC is A0 = 390.5 S cm² mol¹. Calculate the Arrhenius conductivity of a 9.3% by weight solution of HAc with a pH of 3.3. Data: molecular weight of HAC is 60.05 g/mol and the density of the solution is 1 g/cm³.arrow_forward
- If the molar conductivity at infinite dilution of HAC is A0 = 390.5 S cm² mol¹. Calculate the Arrhenius conductivity of a 9.3% by weight solution of HAc with a pH of 3.3. Data: molecular weight of HAC is 60.05 g/mol and the density of the solution is 1 g/cm³.arrow_forwardIf the molar conductivity at infinite dilution of HAC is A0 = 390.5 S cm² mol¹. Calculate the Arrhenius conductivity of a 9.3% by weight solution of HAc with a pH of 3.3. Data: molecular weight of HAC is 60.05 g/mol and the density of the solution is 1 g/cm³.arrow_forwardDetermine the distance between the metal and the OHP layer using the Helm- holtz model when the electrode's differential capacitance is 145 μF cm². DATA: dielectric constant of the medium for the interfacial zone &r= lectric constant of the vacuum &0 = 8.85-10-12 F m-1 = 50, die-arrow_forward
- Describe a sequence of photophysical processes that can be followed by radiation adsorbed by a molecule in the ground state to give rise to phosphorescent emission.arrow_forwardState two similarities between fluorescence and phosphorescence.arrow_forwardState three photophysical processes that can be related to the effects of incident radiation on a molecule in its ground state. Consider that radiation can give rise to fluorescent emission, but not phosphorescent emission.arrow_forward
- Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co
- Principles of Modern ChemistryChemistryISBN:9781305079113Author:David W. Oxtoby, H. Pat Gillis, Laurie J. ButlerPublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning




