Concept explainers
(a)
The density of particles in the atmosphere of Titan.

Answer to Problem 115QAP
The density of particles in the atmosphere of Titan is
Explanation of Solution
Given info:
Temperature at Titan is,
Pressure at Titan is,
Mass of nitrogen molecule is,
Diameter of the sphere is,
Formula used:
Formula for the ideal gas equation is,
Calculation:
The density of particles can be calculated as,
Conclusion:
Thus, the density of particles in the atmosphere of Titan is
(b)
The body that have denser atmosphere, Titan or Earth.

Answer to Problem 115QAP
Titan has denser atmosphere.
Explanation of Solution
Given info:
Temperature at Titan is,
Pressure at Titan is,
Mass of nitrogen molecule is,
Diameter of the sphere is,
Temperature at Earth is,
Pressure at Earth is,
Formula used:
Formula for the ideal gas equation is,
Calculation:
The particle density on Titan can be calculated as,
The particle density on Earth can be calculated as,
Dividing equation (1) by equation (2), we get
So, the particle density on Titan is
Conclusion:
Thus, Titan has denser atmosphere.
(c)
The average distance that a nitrogen molecule travels between collisions on Titan and compare it with the distance for oxygen.

Answer to Problem 115QAP
The average distance that a nitrogen molecule travels between collisions on Titan is
Explanation of Solution
Given info:
Diameter of the sphere is,
Density of particle at Titan is,
Formula used:
The formula for the mean free path is given as,
Calculation:
The average distance that a nitrogen molecule travels between collisions can be calculated as,
The average distance for oxygen is
The average distance that a nitrogen molecule travels between collisions is not reasonable because it is more than the diameter of the sphere. It shows that there will be no collision between the particles in the atmosphere of Titan.
Conclusion:
Thus, the average distance that a nitrogen molecule travels between collisions on Titan is
Want to see more full solutions like this?
Chapter 14 Solutions
COLLEGE PHYSICS,VOLUME 1
- Please help with calculating the impusle, thanks! Having calculated the impact and rebound velocities of the ping pong ball and the tennis ball calculate the rebounding impulse: 1.Measure the weight of the balls and determine their mass. Tennis ball: 0.57 kg Ping Pong Ball: 0.00246 kg The impulse, I, is equal to the change in momentum, Pf-Pi. Note the sign change, i.e., going down is negative and up is positive. The unit for momentum is kg-m/s. The change is momentum, impulse, is often givens the equivalent unit of N-S, Newton-Secondarrow_forward5. Three blocks, each with mass m, are connected by strings and are pulled to the right along the surface of a frictionless table with a constant force of magnitude F. The tensions in the strings connecting the masses are T1 and T2 as shown. m T1 T2 F m m How does the magnitude of tension T₁ compare to F? A) T₁ = F B) T₁ = (1/2)F C) T₁ = (1/3)F D) T₁ = 2F E) T₁ = 3Farrow_forwardUsing Coulombs Law, what is the magnitude of the electrical force between two protons located 1 meter apart from each other in Newtons?arrow_forward
- Calculate the magnitude of the gravitational force between 2 protons located 1 meter apart from each other in Newtons using Newton's Law of Universal Gravitation.arrow_forwardIf the metal sphere on the Van de Graff has a charge of 0.14 Coulombs and the person has a mass of 62 kg, how much excess charge would the person need in order to levitate at a distance 25 cm from the center of the charged metal sphere if there is a distance 25 cm from the person to the sphere using Coulomb's Law to calculate the electrical force. Give your answer as the number of Coulombs (with no unit label, as usual).arrow_forwardA balloon is rubbed on a sweater, giving the balloon a negative charge by adding an extra 3.9 x 107 electrons compared to its neutral state. What is the magnitude of the net charge on the balloon, in Coulombs?arrow_forward
- A ping pong ball and a tennis ball are dropped and there is a very small gap between them when the tennis ball hits the floor. Indicate the directions of the momentums of the ping pong ball and the tennis ball after the tennis ball collides with the floor, but before the balls collide with each other. (Drawing a diagram may be helpful.)arrow_forwardDescribe how the momentum of a single ball changes as it free falls from a height of approximately 1 m, collides with a hard floor, and rebounds.arrow_forwardIf the answer is 2.8, -2.8 or -8.4, it is not CORRECTarrow_forward
- Three blocks, light connecting ropes, and a light frictionless pulley comprise a system, as shown in the figure. An external force of magnitude P is applied downward on block A, causing block A to accelerate downward at a constant 2.5 m/s2. The tension in the rope connecting block B and block C is equal to 60 N. (a) What is the magnitude of the force P? (b) What is the mass of block C?arrow_forwardCurrent Attempt in Progress In the figure what is the net electric potential at point P due to the four particles if V = 0 at infinity, q = 2.12 fC, and d = 1.75 cm? d Number MI Units +qarrow_forwardCurrent Attempt in Progress In the figure what is the net electric potential at point P due to the four particles if V = 0 at infinity, q = 2.12 fC, and d = 1.75 cm? d Number MI Units +qarrow_forward
- College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax CollegePrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning





