FlipIt for College Physics (Algebra Version - Six Months Access)
FlipIt for College Physics (Algebra Version - Six Months Access)
17th Edition
ISBN: 9781319032432
Author: Todd Ruskell
Publisher: W.H. Freeman & Co
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 14, Problem 115QAP
To determine

(a)

The density of particles in the atmosphere of Titan.

Expert Solution
Check Mark

Answer to Problem 115QAP

The density of particles in the atmosphere of Titan is 1.2×1026particles/m3.

Explanation of Solution

Given info:

Temperature at Titan is, T1=179°C.

Pressure at Titan is, P1=1.5atm.

Mass of nitrogen molecule is, mN=4.7×1026kg.

Diameter of the sphere is, d=2.4×1010m.

Formula used:

Formula for the ideal gas equation is,

  PV=NkT

Calculation:

The density of particles can be calculated as,

  N1V=P1kT1ρ1=1.5×1.03×105Pa(1.38×1023J/K)(179+273)Kρ1=1.2×1026particles/m3

Conclusion:

Thus, the density of particles in the atmosphere of Titan is 1.2×1026particles/m3.

To determine

(b)

The body that have denser atmosphere, Titan or Earth.

Expert Solution
Check Mark

Answer to Problem 115QAP

Titan has denser atmosphere.

Explanation of Solution

Given info:

Temperature at Titan is, T1=179°C.

Pressure at Titan is, P1=1.5atm.

Mass of nitrogen molecule is, mN=4.7×1026kg.

Diameter of the sphere is, d=2.4×1010m.

Temperature at Earth is, T2=10°C.

Pressure at Earth is, P2=1atm.

Formula used:

Formula for the ideal gas equation is,

  PV=NkT

Calculation:

The particle density on Titan can be calculated as,

  ρ1=P1kT1  ...... (1)

The particle density on Earth can be calculated as,

  ρ2=P2kT2  ...... (2)

Dividing equation (1) by equation (2), we get

  ρ1ρ2=P1×T2P2×T1ρ1ρ2=1.5×(10+273)1.0×(179+273)ρ1ρ2=4.5ρ1=4.5ρ2

So, the particle density on Titan is 4.5times more than the particle density on Earth. Hence, Titan has denser atmosphere.

Conclusion:

Thus, Titan has denser atmosphere.

To determine

(c)

The average distance that a nitrogen molecule travels between collisions on Titan and compare it with the distance for oxygen.

Expert Solution
Check Mark

Answer to Problem 115QAP

The average distance that a nitrogen molecule travels between collisions on Titan is 3.3×108mand it is about 1.7times less than the average distance for oxygen. This result is unreasonable.

Explanation of Solution

Given info:

Diameter of the sphere is, d=2.4×1010m.

Density of particle at Titan is, NV=1.2×1026particles/m3

Formula used:

The formula for the mean free path is given as,

  λ=142πr2(NV)

Calculation:

The average distance that a nitrogen molecule travels between collisions can be calculated as,

  λ=142×3.14(1.2×1010)2×1.2×1026λ3.3×108m

The average distance for oxygen is 5.6×108mwhich is more than the average distance for nitrogen particles. The average distance each molecule of nitrogen travels in Titan's atmosphere is about 1.7time less than the average distance for oxygen.

The average distance that a nitrogen molecule travels between collisions is not reasonable because it is more than the diameter of the sphere. It shows that there will be no collision between the particles in the atmosphere of Titan.

Conclusion:

Thus, the average distance that a nitrogen molecule travels between collisions on Titan is 3.3×108mand it is about 1.7times less than the average distance for oxygen. This result is unreasonable.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Write an equation for the function shown. You may assume all intercepts and asymptotes are on integers. The blue dashed lines are the asymptotes. 10 9- 8- 7 6 5 4- 3- 2 4 5 15-14-13-12-11-10 -9 -8 -7 -6 -5 -4 -3 -2 1 1 2 3 -1 -2 -3 -4 1 -5 -6- -7 -8- -9 -10+ 60 7 8 9 10 11 12 13 14 15
Use the graph of the polynomial function of degree 5 to identify zeros and multiplicity. Order your zeros from least to greatest. -6 3 6+ 5 4 3 2 1 2 -1 -2 -3 -4 -5 3 4 6 Zero at with multiplicity Zero at with multiplicity Zero at with multiplicity
Use the graph to identify zeros and multiplicity. Order your zeros from least to greatest. 6 5 4 -6-5-4-3-2 3 21 2 1 2 4 5 ૪ 345 Zero at with multiplicity Zero at with multiplicity Zero at with multiplicity Zero at with multiplicity པ་

Chapter 14 Solutions

FlipIt for College Physics (Algebra Version - Six Months Access)

Ch. 14 - Prob. 11QAPCh. 14 - Prob. 12QAPCh. 14 - Prob. 13QAPCh. 14 - Prob. 14QAPCh. 14 - Prob. 15QAPCh. 14 - Prob. 16QAPCh. 14 - Prob. 17QAPCh. 14 - Prob. 18QAPCh. 14 - Prob. 19QAPCh. 14 - Prob. 20QAPCh. 14 - Prob. 21QAPCh. 14 - Prob. 22QAPCh. 14 - Prob. 23QAPCh. 14 - Prob. 24QAPCh. 14 - Prob. 25QAPCh. 14 - Prob. 26QAPCh. 14 - Prob. 27QAPCh. 14 - Prob. 28QAPCh. 14 - Prob. 29QAPCh. 14 - Prob. 30QAPCh. 14 - Prob. 31QAPCh. 14 - Prob. 32QAPCh. 14 - Prob. 33QAPCh. 14 - Prob. 34QAPCh. 14 - Prob. 35QAPCh. 14 - Prob. 36QAPCh. 14 - Prob. 37QAPCh. 14 - Prob. 38QAPCh. 14 - Prob. 39QAPCh. 14 - Prob. 40QAPCh. 14 - Prob. 41QAPCh. 14 - Prob. 42QAPCh. 14 - Prob. 43QAPCh. 14 - Prob. 44QAPCh. 14 - Prob. 45QAPCh. 14 - Prob. 46QAPCh. 14 - Prob. 47QAPCh. 14 - Prob. 48QAPCh. 14 - Prob. 49QAPCh. 14 - Prob. 50QAPCh. 14 - Prob. 51QAPCh. 14 - Prob. 52QAPCh. 14 - Prob. 53QAPCh. 14 - Prob. 54QAPCh. 14 - Prob. 55QAPCh. 14 - Prob. 56QAPCh. 14 - Prob. 57QAPCh. 14 - Prob. 58QAPCh. 14 - Prob. 59QAPCh. 14 - Prob. 60QAPCh. 14 - Prob. 61QAPCh. 14 - Prob. 62QAPCh. 14 - Prob. 63QAPCh. 14 - Prob. 64QAPCh. 14 - Prob. 65QAPCh. 14 - Prob. 66QAPCh. 14 - Prob. 67QAPCh. 14 - Prob. 68QAPCh. 14 - Prob. 69QAPCh. 14 - Prob. 70QAPCh. 14 - Prob. 71QAPCh. 14 - Prob. 72QAPCh. 14 - Prob. 73QAPCh. 14 - Prob. 74QAPCh. 14 - Prob. 75QAPCh. 14 - Prob. 76QAPCh. 14 - Prob. 77QAPCh. 14 - Prob. 78QAPCh. 14 - Prob. 79QAPCh. 14 - Prob. 80QAPCh. 14 - Prob. 81QAPCh. 14 - Prob. 82QAPCh. 14 - Prob. 83QAPCh. 14 - Prob. 84QAPCh. 14 - Prob. 85QAPCh. 14 - Prob. 86QAPCh. 14 - Prob. 87QAPCh. 14 - Prob. 88QAPCh. 14 - Prob. 89QAPCh. 14 - Prob. 90QAPCh. 14 - Prob. 91QAPCh. 14 - Prob. 92QAPCh. 14 - Prob. 93QAPCh. 14 - Prob. 94QAPCh. 14 - Prob. 95QAPCh. 14 - Prob. 96QAPCh. 14 - Prob. 97QAPCh. 14 - Prob. 98QAPCh. 14 - Prob. 99QAPCh. 14 - Prob. 100QAPCh. 14 - Prob. 101QAPCh. 14 - Prob. 102QAPCh. 14 - Prob. 103QAPCh. 14 - Prob. 104QAPCh. 14 - Prob. 105QAPCh. 14 - Prob. 106QAPCh. 14 - Prob. 107QAPCh. 14 - Prob. 108QAPCh. 14 - Prob. 109QAPCh. 14 - Prob. 110QAPCh. 14 - Prob. 111QAPCh. 14 - Prob. 112QAPCh. 14 - Prob. 113QAPCh. 14 - Prob. 114QAPCh. 14 - Prob. 115QAPCh. 14 - Prob. 116QAPCh. 14 - Prob. 117QAPCh. 14 - Prob. 118QAPCh. 14 - Prob. 119QAPCh. 14 - Prob. 120QAPCh. 14 - Prob. 121QAPCh. 14 - Prob. 122QAPCh. 14 - Prob. 123QAPCh. 14 - Prob. 124QAPCh. 14 - Prob. 125QAPCh. 14 - Prob. 126QAPCh. 14 - Prob. 127QAPCh. 14 - Prob. 128QAPCh. 14 - Prob. 129QAP
Knowledge Booster
Background pattern image
Algebra
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Mathematics For Machine Technology
Advanced Math
ISBN:9781337798310
Author:Peterson, John.
Publisher:Cengage Learning,
Text book image
College Algebra
Algebra
ISBN:9781337282291
Author:Ron Larson
Publisher:Cengage Learning
Text book image
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:9781133382119
Author:Swokowski
Publisher:Cengage
Text book image
Algebra: Structure And Method, Book 1
Algebra
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:McDougal Littell
Kinetic Molecular Theory and its Postulates; Author: Professor Dave Explains;https://www.youtube.com/watch?v=o3f_VJ87Df0;License: Standard YouTube License, CC-BY