Derive the source of variation.

Question

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Answer 1

Question

Chapter 14, Problem 113CE

To determine

Derive the source of variation.

Expert Solution & Answer

Explanation of Solution

The null and alternative hypotheses for reading can be written as follows:

H0:μ1=μ2=μ3=μ4H1:At least two means differ

Table -1 shows the ANOVA estimated value as follows:

Table -1

Source	Degree of freedom	Sum of square	Mean square	F	P -value	F crit
Between groups	3	2.12	0.705	9.17	0.0000	2.69
Within groups	104	7.99	0.0769
Total	107	10.11

From the estimation result, the F value is 9.17 and the p-value is 0. Here, there is adequate evidence to conclude that there is a difference in the changes to the TSE depending on the loss of the previous day.

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Answer 2

Question

Chapter 14, Problem 113CE

To determine

Derive the source of variation.

Expert Solution & Answer

Explanation of Solution

The null and alternative hypotheses for reading can be written as follows:

H0:μ1=μ2=μ3=μ4H1:At least two means differ

Table -1 shows the ANOVA estimated value as follows:

Table -1

Source	Degree of freedom	Sum of square	Mean square	F	P -value	F crit
Between groups	3	2.12	0.705	9.17	0.0000	2.69
Within groups	104	7.99	0.0769
Total	107	10.11

From the estimation result, the F value is 9.17 and the p-value is 0. Here, there is adequate evidence to conclude that there is a difference in the changes to the TSE depending on the loss of the previous day.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 14, Problem 113CE

To determine

Derive the source of variation.

Expert Solution & Answer

Explanation of Solution

The null and alternative hypotheses for reading can be written as follows:

H0:μ1=μ2=μ3=μ4H1:At least two means differ

Table -1 shows the ANOVA estimated value as follows:

Table -1

Source	Degree of freedom	Sum of square	Mean square	F	P -value	F crit
Between groups	3	2.12	0.705	9.17	0.0000	2.69
Within groups	104	7.99	0.0769
Total	107	10.11

From the estimation result, the F value is 9.17 and the p-value is 0. Here, there is adequate evidence to conclude that there is a difference in the changes to the TSE depending on the loss of the previous day.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 14, Problem 113CE

To determine

Derive the source of variation.

Expert Solution & Answer

Explanation of Solution

The null and alternative hypotheses for reading can be written as follows:

H0:μ1=μ2=μ3=μ4H1:At least two means differ

Table -1 shows the ANOVA estimated value as follows:

Table -1

Source	Degree of freedom	Sum of square	Mean square	F	P -value	F crit
Between groups	3	2.12	0.705	9.17	0.0000	2.69
Within groups	104	7.99	0.0769
Total	107	10.11

From the estimation result, the F value is 9.17 and the p-value is 0. Here, there is adequate evidence to conclude that there is a difference in the changes to the TSE depending on the loss of the previous day.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 14, Problem 113CE

To determine

Derive the source of variation.

Expert Solution & Answer

Explanation of Solution

The null and alternative hypotheses for reading can be written as follows:

H0:μ1=μ2=μ3=μ4H1:At least two means differ

Table -1 shows the ANOVA estimated value as follows:

Table -1

Source	Degree of freedom	Sum of square	Mean square	F	P -value	F crit
Between groups	3	2.12	0.705	9.17	0.0000	2.69
Within groups	104	7.99	0.0769
Total	107	10.11

From the estimation result, the F value is 9.17 and the p-value is 0. Here, there is adequate evidence to conclude that there is a difference in the changes to the TSE depending on the loss of the previous day.

Answer 6

Chapter 14, Problem 113CE

To determine

Derive the source of variation.

Expert Solution & Answer

Explanation of Solution

The null and alternative hypotheses for reading can be written as follows:

H0:μ1=μ2=μ3=μ4H1:At least two means differ

Table -1 shows the ANOVA estimated value as follows:

Table -1

Source	Degree of freedom	Sum of square	Mean square	F	P -value	F crit
Between groups	3	2.12	0.705	9.17	0.0000	2.69
Within groups	104	7.99	0.0769
Total	107	10.11

From the estimation result, the F value is 9.17 and the p-value is 0. Here, there is adequate evidence to conclude that there is a difference in the changes to the TSE depending on the loss of the previous day.

Answer 7

Chapter 14, Problem 113CE

To determine

Derive the source of variation.

Answer 8

Expert Solution & Answer

Explanation of Solution

The null and alternative hypotheses for reading can be written as follows:

H0:μ1=μ2=μ3=μ4H1:At least two means differ

Table -1 shows the ANOVA estimated value as follows:

Table -1

Source	Degree of freedom	Sum of square	Mean square	F	P -value	F crit
Between groups	3	2.12	0.705	9.17	0.0000	2.69
Within groups	104	7.99	0.0769
Total	107	10.11

From the estimation result, the F value is 9.17 and the p-value is 0. Here, there is adequate evidence to conclude that there is a difference in the changes to the TSE depending on the loss of the previous day.