ORGANIC CHEM. VOL.1+2-W/WILEYPLUS
ORGANIC CHEM. VOL.1+2-W/WILEYPLUS
12th Edition
ISBN: 9781119304241
Author: Solomons
Publisher: WILEY C
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Chapter 14, Problem 10PP
Interpretation Introduction

Interpretation:

The 13CNMR signals are to be predicted for the various given aromatic compounds.

Concept introduction:

Carbon nuclear magnetic resonance (13CNMR) is considered homologous to proton nuclear magnetic resonance (1HNMR).

In NMR spectroscopy, the proton and 13C nuclear magnetic resonance (1HNMR) is used to find out the structure of molecules.

The splitting of the molecules is determined by the (2nI+1) rule. For 1H, I= ½, hence 2nI+1 = n+1, which dictates the splitting pattern. where, n is the number of hydrogens on the adjacent atom.

For 13C NMR, generally we plot the proton decoupled spectrum and hence it comes as single sharp singlet lines. The number of peaks correspond to the number of equivalent carbon atoms in the molecule.

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10. Complete the following halogenation reactions for alkanes. Draw the structures of one of the many possible products for each reaction. Name the reactant and product. a) CH₂- CH-CH2-CH3 + Br₂ CH₂ UV UV b) + Cl2 c) CH3-CH₂ CHICHCHICH-CH CH₂-CH₂ + F2 UV
Which of the following processes involves the largest photon energy? Group of answer choices Electron promotion from n=2 to n=5 Electron relaxing from n=4 to n=3 Ionization of an electron from n=2 Ionization of an electron from n=4

Chapter 14 Solutions

ORGANIC CHEM. VOL.1+2-W/WILEYPLUS

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