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WebAssign Homework Only for Moaveni's Engineering Fundamentals: An Introduction to Engineering, SI Edition, 6th Edition, [Instant Access]
6th Edition
ISBN: 9780357126677
Author: MOAVENI
Publisher: Cengage Learning US
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Chapter 14, Problem 10P
To determine
Using Excel, create a table showing a relationship between the units of power in watts and horsepower in the range of
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please solve and neglect the distance between the two angles for simplecalculations
Determine the required solids retention time (SRT) of a completely mixed
activated sludge aeration tank for a conventional activated sludge system
treating a design flow rate of 34,560 m³/d, where the effluent standards are
30.0 mg/L for BODs and 30.0 mg/L for total suspended solids (TSS). Assume
that the BOD5 of the effluent TSS is 70% of the TSS concentration. Assume the
BODs concentration leaving the primary clarifier is 128 mg/L that the MLVSS
concentration (X₂) is 2,500 mg/L. Assume the following values for the growth
constants:
Ks 100 mg/L BODS
⚫ Hm - 2.5 d 1
kd = 0.050 d 1
Y = 0.50 mg VSS/mg BODs removed
Express your answer in days and round to the nearest 0.1.
For the gravity concrete dam shown in the figure, the following data are available:
Unit weight of concrete (7)-2.4 ton/m
Neglect Wave pressure, silt pressure, ice force and earth quake force)
-0.65, (7)-1 ton/m'
Solve on paper and sketch
Find factor of safety against sliding and overturning (F.Sa & F.S), If heel and toe stresses (Pain &
P) are 57.17ton/m2 and 84.53 ton/m² respectively.
Solve in table on paper
w.s.l
83m
10m
8m
80m
Chapter 14 Solutions
WebAssign Homework Only for Moaveni's Engineering Fundamentals: An Introduction to Engineering, SI Edition, 6th Edition, [Instant Access]
Ch. 14.2 - Prob. 1BYGCh. 14.2 - Prob. 2BYGCh. 14.2 - Prob. 3BYGCh. 14.2 - Prob. 4BYGCh. 14.2 - Prob. 5BYGCh. 14.2 - Prob. BYGVCh. 14.4 - Prob. 1BYGCh. 14.4 - Prob. 2BYGCh. 14.4 - Prob. 3BYGCh. 14.4 - Prob. 4BYG
Ch. 14.4 - Prob. 5BYGCh. 14.4 - Prob. BYGVCh. 14.5 - Prob. 1BYGCh. 14.5 - Prob. 2BYGCh. 14.5 - Prob. 3BYGCh. 14.5 - Prob. 4BYGCh. 14.5 - Prob. BYGVCh. 14 - Prob. 1PCh. 14 - Prob. 2PCh. 14 - Prob. 3PCh. 14 - Prob. 4PCh. 14 - Prob. 5PCh. 14 - Prob. 6PCh. 14 - Prob. 7PCh. 14 - Using Excel, create a table that shows the...Ch. 14 - Using Excel, create a table that shows the...Ch. 14 - Prob. 10PCh. 14 - Prob. 11PCh. 14 - Prob. 12PCh. 14 - Prob. 13PCh. 14 - Prob. 14PCh. 14 - Prob. 15PCh. 14 - Prob. 16PCh. 14 - Prob. 17PCh. 14 - Prob. 18PCh. 14 - Prob. 19PCh. 14 - Prob. 20PCh. 14 - Prob. 21PCh. 14 - Prob. 22PCh. 14 - Prob. 23PCh. 14 - Prob. 24PCh. 14 - Prob. 25PCh. 14 - Prob. 26PCh. 14 - Prob. 27PCh. 14 - Prob. 28PCh. 14 - Prob. 29PCh. 14 - Prob. 30PCh. 14 - Prob. 31PCh. 14 - Prob. 32PCh. 14 - Prob. 33PCh. 14 - Prob. 34PCh. 14 - Prob. 35P
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- Calculate the dry mass of activated sludge (✗a) produced in wastewater treatment system where the flow rate is 7,500 m³/day, the BOD concentration in the primary effluent (i.e., the BOD concentration in the wastewater going to the aeration basin) is 75 mg/L, the soluble BOD concentration in the liquid effluent of the secondary clarifier is 10 mg/L, and the system is operating with an SRT of 3 days. Assume true yield is 0.5 g VSS per g BOD and the decay rate (i.e., bч or kd) is equal to 0.1 days 1. Assume the system does not achieve nitrification and that the mass of cell debris, nonbiodegradable VSS, and influent inert TSS is negigible. Express your answer in kg/day and round to the nearest 0.1.arrow_forwardIn a school, there are three clubs: Drama Club, Music Club, and debating Club. Some students are members of multiple clubs, while others are only members of one club. a. How would you represent this scenario using set notation and Venn Diagram?arrow_forwardDetermine the required volume of a completely mixed activated sludge aeration tank for a conventional activated sludge system treating a design flow rate of 34,560 m³/d, where the effluent standards are 30.0 mg/L for BOD5 and 30.0 mg/L for total suspended solids (TSS). Assume that the BOD5 of the effluent TSS is 70% of the TSS concentration. Assume the BOD5 concentration leaving the primary clarifier is 128 mg/L that the MLVSS concentration (Xa) is 2,500 mg/L. Assume the following values for the growth constants: • K = 100 mg/L BOD5 • μm = 2.5 d−1 • kd = 0.050 d 1 Y = 0.50 mg VSS/mg BOD5 removed Express your answer in m³ and round to the nearest integer.arrow_forward
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- For the gravity concrete dam shown in the figure, the following data are available: - Unit weight of concrete (Yeone) = 2.4 ton/m³ - Horizontal earth quake coefficient (Kh) = 0.1 Neglect( Wave pressure, silt pressure, ice force) H=0.65, (Ywater) -1 ton/m³ Find :- a- heel and toe stresses (Pain & Pmas) b- factor of safety against sliding and overturning (F.S. & F.Sover). Solve in table on paper W 8m 6m 8m 94m 0.9arrow_forwardA market segment consists of 500 individuals. A Logit mode choice model (with logit parameter equal to 1) has been estimated for this market resulting in the following utility function: U = ẞm 0.40C 0.037 where C is out-of-pocket cost in $ and T is travel time in min. Values of ẞm are: Bus: 0.00; Rail: 0.50; Car: 1.50. For a particular origin-destination pair, the cost of a car trip is $2 and the duration 8 minutes, a rail trip is $1.50 and takes 12 minutes, while a bus takes 20 minutes and costs $1.25. a. Predict the number of trips for each mode. b. Which one of the following policies would lead to the largest increase in bus passengers? Why? (i) An increase in the price of gas that increases the cost of a car trip to $3, while all other parameters remain constant. (ii) Introducing an express service that decreases the travel time of the rail to 10 min, while all other parameters remain constant. (iii) Decrease the cost of the bus to $1, while all other parameters remain constant.arrow_forwardQ1: For the gravity concrete dam shown in the figure, the following data are available: -Unit weight of concrete (Y)-2.4 ton/m Neglect Wave pressure, silt pressure, ice force and carth quake force) -0.65, (7) 1 ton/m' Find factor of safety against sliding and overturning (F.Sas & F.Ser), If heel and toe stresses (P & Pan) are 57.17ton/m² and 84.53 ton/m² respectively. Solve in table on paper w.s.i 83m 10m 8m 80marrow_forward
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