Explanation Given information: The tube is made up of 2014-T6 aluminum alloy. The cross-section of the tube is square. The length of the tube is L = 10 ft . The tube is fixed at its bottom and pinned at its top. The axial load on the tube is P . Calculation: Consider the width of the outer square as a o = 6 in . The thickness of the tube is t = 0.25 in . Consider the inner width of the tube is a i . Calculate the inner side of the tube using the relation: a i = a o − 2 t (1) Substitute 6 in . for a o and 0.25 in . for t in Equation (1). a i = a o − 2 t = 6 in . − 2 × 0.25 in = 6 in . − 0.5 in . = 5 .5 in . Calculate the area of the cross-section of the tube using the relation: A = a o 2 − a i 2 (2) Here, a o is the outer side of the square and a i is the inner side of the tube. Substitute 6 in . for a o and 5.5 in . for a i in Equation (2). A = a o 2 − a i 2 = 6 2 − 5.5 2 = 36 − 30.25 = 5.75 in . 2 Show the expression for moment of inertia for the hollow square cross-section as follows: I = a o × a o 3 12 − a i × a i 3 12 = a o 4 12 − a i 4 12 = 1 12 ( a o 4 − a i 4 ) (3) Substitute 6 in . for a o and 5.5 in . for a i in Equation (3). I = 1 12 ( 6 4 − 5.5 4 ) = 1 12 ( 1 , 296 − 915.0625 ) = 380.937 12 = 31.744 in

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ISBN: 9780133254426

Author: Russell C. Hibbeler

Publisher: Prentice Hall

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Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial …

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Chapter 13.6, Problem 13.97P

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The value of largest axial load the tube can support.

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Chapter 13.6, Problem 13.96P

Chapter 13.6, Problem 13.98P

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The value of largest axial load the tube can support.

Solution Summary: The author calculates the value of largest axial load the tube can support using the following equations.

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