Concept explainers
a.
To write: an equation for the motion of the buoy. Assume that it is at equilibrium at t = 0 and that it is on the way up from the normal water level.
a.
Answer to Problem 76SR
The equation for the motion of the buoy:
Explanation of Solution
Given information: A harbor buoy bobs up and down with the waves. The distance
between the highest and lowest points is 4 feet. The buoy moves from its highest point to its lowest point and back to its highest point every 10 seconds.
Calculation:
The motion of the buoy can be modeled by the equation:
Therefore, the equation for the motion of the buoy:
b.
To draw: a graph showing the height of the buoy as a function of time.
b.
Answer to Problem 76SR
Explanation of Solution
Given information: A harbor buoy bobs up and down with the waves. The distance
between the highest and lowest points is 4 feet. The buoy moves from its highest point to its lowest point and back to its highest point every 10 seconds.
Calculation:
The graph of the equation for the motion of the buoy:
c.
To find: the height of the buoy after 12 seconds.
c.
Answer to Problem 76SR
The height of the buoy after 12 seconds is
Explanation of Solution
Given information: A harbor buoy bobs up and down with the waves. The distance
between the highest and lowest points is 4 feet. The buoy moves from its highest point to its lowest point and back to its highest point every 10 seconds.
Calculation:
The equation for the motion of the buoy:
Therefore, the height of the buoy after 12 seconds is
Chapter 13 Solutions
Glencoe Algebra 2 Student Edition C2014
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