Explanation Given Information: The given set of compound inequalitiesis x 2 + y 2 ≤ 36 or x + y ≥ 0 . Graph: Consider the first inequality, x 2 + y 2 ≤ 36 . The solution of the inequality x 2 + y 2 ≤ 36 is the set of points which is inside the circle x 2 + y 2 = 36 . Now, draw the graph of x 2 + y 2 = 36 and shade the region inside the circle x 2 + y 2 = 36 which is the graph of x 2 + y 2 ≤ 36 . Consider the second inequality, x + y ≥ 0 The solution of the inequality x + y ≥ 0 is the set of points which is away from the origin, that is, above the line x + y = 0 . Now, draw the graph of x + y = 0 and shade the region above the line x + y = 0 which is the graph of x + y ≥ 0 . The union of above two graph contains the solution of system of inequalities x 2 + y 2 ≤ 36 and x + y ≥ 0 . Now, the combined graph of system of inequality x 2 + y 2 ≤ 36 and x + y ≥ 0 is shown below, The system of inequalities divides the x y -plane in two regions. Consider a test point ( 0 , 0 ) from the graph to check that the statement is true or false for the inequality x 2 + y 2 ≤ 36 . Substitute 0 for x and 0 for y in inequality x 2 + y 2 ≤ 36 . x 2 + y 2 ≤ 36 0 2 + 0 2 ≤ 36 0 ≤ 36 The result is true for the inequality x 2 + y 2 ≤ 36

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ISBN: 9781260962024

Author: Miller

Publisher: MCG

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Chapter 13.5, Problem 52PE

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To graph: The solution set of the compound inequalities x2+y2≤36 or x+y≥0.

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Chapter 13.5, Problem 51PE

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Ch. 13.1 - Find the distance between the points ( − 4 , − 2 )...Ch. 13.1 - Prob. 2SP Ch. 13.1 - Prob. 3SP Ch. 13.1 - Prob. 4SP Ch. 13.1 - Prob. 5SP Ch. 13.1 - Prob. 6SP Ch. 13.1 - Prob. 7SP Ch. 13.1 - Prob. 8SP Ch. 13.1 - Prob. 1PE Ch. 13.1 - Prob. 2PE

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