The solution of the differential equation d x x ( 1000 − x ) = k d t if k = 0.001 . When the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease. Where, x represents the number of people infected by the disease at any time t (in days).

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Answer 1

Question

Chapter 13.5, Problem 42E

(a)

To determine

To calculate: The solution of the differential equation dxx(1000−x)=kdt if k=0.001. When the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease.

Where, x represents the number of people infected by the disease at any time t (in days).

(b)

To determine

To calculate: The time before half the population of the community is affected Where the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease.

(c)

To determine

To calculate: The rate of new cases dxdt for every alternate days till first 13 days Where the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease and differential equation is given by dxx(1000−x)=kdt if k=0.001.

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Answer 2

Question

Chapter 13.5, Problem 42E

(a)

To determine

To calculate: The solution of the differential equation dxx(1000−x)=kdt if k=0.001. When the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease.

Where, x represents the number of people infected by the disease at any time t (in days).

(b)

To determine

To calculate: The time before half the population of the community is affected Where the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease.

(c)

To determine

To calculate: The rate of new cases dxdt for every alternate days till first 13 days Where the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease and differential equation is given by dxx(1000−x)=kdt if k=0.001.

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Answer 3

Question

Chapter 13.5, Problem 42E

(a)

To determine

To calculate: The solution of the differential equation dxx(1000−x)=kdt if k=0.001. When the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease.

Where, x represents the number of people infected by the disease at any time t (in days).

(b)

To determine

To calculate: The time before half the population of the community is affected Where the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease.

(c)

To determine

To calculate: The rate of new cases dxdt for every alternate days till first 13 days Where the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease and differential equation is given by dxx(1000−x)=kdt if k=0.001.

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 4

Question

Chapter 13.5, Problem 42E

(a)

To determine

To calculate: The solution of the differential equation dxx(1000−x)=kdt if k=0.001. When the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease.

Where, x represents the number of people infected by the disease at any time t (in days).

(b)

To determine

To calculate: The time before half the population of the community is affected Where the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease.

(c)

To determine

To calculate: The rate of new cases dxdt for every alternate days till first 13 days Where the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease and differential equation is given by dxx(1000−x)=kdt if k=0.001.

Expert Solution & Answer

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Answer 5

Chapter 13.5, Problem 42E

(a)

To determine

To calculate: The solution of the differential equation dxx(1000−x)=kdt if k=0.001. When the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease.

Where, x represents the number of people infected by the disease at any time t (in days).

(b)

To determine

To calculate: The time before half the population of the community is affected Where the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease.

(c)

To determine

To calculate: The rate of new cases dxdt for every alternate days till first 13 days Where the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease and differential equation is given by dxx(1000−x)=kdt if k=0.001.

Answer 6

Chapter 13.5, Problem 42E

(a)

To determine

To calculate: The solution of the differential equation dxx(1000−x)=kdt if k=0.001. When the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease.

Where, x represents the number of people infected by the disease at any time t (in days).

Answer 7

Chapter 13.5, Problem 42E

(a)

To determine

To calculate: The solution of the differential equation dxx(1000−x)=kdt if k=0.001. When the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease.

Where, x represents the number of people infected by the disease at any time t (in days).

Answer 8

(b)

To determine

To calculate: The time before half the population of the community is affected Where the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease.

Answer 9

(b)

To determine

To calculate: The time before half the population of the community is affected Where the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease.

Answer 10

(c)

To determine

To calculate: The rate of new cases dxdt for every alternate days till first 13 days Where the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease and differential equation is given by dxx(1000−x)=kdt if k=0.001.

Answer 11

(c)

To determine

To calculate: The rate of new cases dxdt for every alternate days till first 13 days Where the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease and differential equation is given by dxx(1000−x)=kdt if k=0.001.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 13.1 - CHECKPOINT 1. For the interval [0, 2]. determine...Ch. 13.1 - Prob. 2CP Ch. 13.1 - Prob. 1E Ch. 13.1 - Prob. 2E Ch. 13.1 - Prob. 3E Ch. 13.1 - Prob. 4E Ch. 13.1 - Prob. 5E Ch. 13.1 - Prob. 6E Ch. 13.1 - Prob. 7E Ch. 13.1 - Prob. 8E

Solution Summary: The author calculates the solution of the differential equation, dxx, (1000-x-)=kdt.

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To calculate: The time before half the population of the community is affected Where the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease.

To calculate: The rate of new cases dxdt for every alternate days till first 13 days Where the specific community of 1000 people those are suffering from several disease is exposed when one of the member returns carrying the disease and differential equation is given by dxx(1000−x)=kdt if k=0.001.

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