BROOKER BIOLOGY
BROOKER BIOLOGY
5th Edition
ISBN: 9781307656152
Author: BROOKER
Publisher: MCG/CREATE
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Chapter 13.5, Problem 1CS

Core Skill: Modeling The goal of this modeling challenge is to increase the complexity of the model shown in Figure 13.8d by including sequences in the crRNA and bacteriophage DNA that bind to each other.

Modeling Challenge: For simplicity, the structure of the crRNAs in Figure 13.8 is shown shorter than it really is. Let’s suppose that the part of a crRNA that recognizes the bacteriophage DNA is 20 nucleotides long with the following base sequence: 3'-GAUCCCAUACGGCUAAUCAA-5'. (Note: This is only part of the sequence of the crRNA; it does not include the part that binds to tracrRNA.) Suppose this crRNA is within a tracrRNA-crRNA-Cas9 complex, and draw a model that shows the binding of the complex to a bacteriophage. The general features of the model should be similar to those in Figure 13.8d, except you should include the sequences of the crRNA and the bacteriophage DNA that bind to each other. Label the 5' and 3' ends of the tracrRNA, crRNA and bacteriophage DNA.

Chapter 13.5, Problem 1CS, Core Skill: Modeling The goal of this modeling challenge is to increase the complexity of the model

Figure 13.8 The CRISPR-Cas system of genome defense in bacteria. The system shown here is a type II system, which is found in the chromosome of certain bacterial species but not in archaea. (a) Organization of the CRISPR-Cas system in a bacterial chromosome. This drawing shows a typical organization, but different species have variations. (b–d) A simplified mechanism of the CRISPR-Cas system. The defense occurs in three phases, called adaptation, expression, and interference.

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A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation?   The cell membranes are more resistant than normal.   An isotonic solution had been added instead of water.   A solution of 0.1 M NaCl had been added instead of water.   Not enough water had been added to the red blood cell pellet.   The man had sickle-cell anaemia.
A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation?   The cell membranes are more resistant than normal.   An isotonic solution had been added instead of water.   A solution of 0.1 M NaCl had been added instead of water.   Not enough water had been added to the red blood cell pellet.   The man had sickle-cell anaemia.
With reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobin
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