Chapter 13.5, Problem 13.6BFP

Interpretation Introduction

Interpretation:

The molality, molarity, and mole percent of ${\text{CaBr}}_{\text{2}}$ has to be calculated.

Concept introduction:

Molality: Dividing the moles of solute by the mass of solvent in kg.

$\text{Molality}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Mass}\text{of}\text{solvent}\text{inkg}}$

Molarity: Dividing moles of solute by the volume of solution in Liter.

$\text{Molarity}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Volume of solution in L}}$

Mole percent: Dividing moles of solute by the total moles in the solution and multiplying by 100.

$\text{Mole percent}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{total moles in solution}}\times 100$