Calculus: Early Transcendentals
4th Edition
ISBN: 9781319050740
Author: Jon Rogawski, Colin Adams, Robert Franzosa
Publisher: W. H. Freeman
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Chapter 13.3, Problem 2E
To determine
The arc length of the curve traced by
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3.15 (B). A beam ABCD is simply supported at B and C with ABCD=2m; BC 4 m. It
carries a point load of 60 KN at the free end A, a Uniformly distributed load of 60
KN/m between B and C and an anticlockwise moment of 80 KN m in the plane of
the beam applied at the free end D. Sketch and dimension the S.F. and B.M.
diagrams, and determine the position and magnitude of the maximum bending
moment. CEL.E.] CS.F. 60, 170, 70KN, B.M. 120, +120.1, +80 kNm, 120.1 kNm at 2.83 m to
right of 8.7
7.1 (A/B). A Uniform I-section beam has flanges 150 mm wide by 8 mm thick and a
web 180 mm wide and 8 mm thick. At a certain section there is a shearing force of
120 KN. Draw a diagram to illustrate the distribution of shear stress across the
section as a result of bending. What is the maximum shear stress? [86.7 MN/m².
1. Let Ả = −2x + 3y+42, B =
-
-
7x +lý +22, and C = −1x + 2y +
42. Find (a) Ả X B (b) ẢX B°C c)
→→
Ả B X C d) ẢB°C e) ẢX B XC.
Chapter 13 Solutions
Calculus: Early Transcendentals
Ch. 13.1 - Prob. 1PQCh. 13.1 - Prob. 2PQCh. 13.1 - Prob. 3PQCh. 13.1 - Prob. 4PQCh. 13.1 - Prob. 5PQCh. 13.1 - Prob. 6PQCh. 13.1 - Prob. 1ECh. 13.1 - Prob. 2ECh. 13.1 - Prob. 3ECh. 13.1 - Prob. 4E
Ch. 13.1 - Prob. 5ECh. 13.1 - Prob. 6ECh. 13.1 - Prob. 7ECh. 13.1 - Prob. 8ECh. 13.1 - Prob. 9ECh. 13.1 - Prob. 10ECh. 13.1 - Prob. 11ECh. 13.1 - Prob. 12ECh. 13.1 - Prob. 13ECh. 13.1 - Prob. 14ECh. 13.1 - Prob. 15ECh. 13.1 - Prob. 16ECh. 13.1 - Prob. 17ECh. 13.1 - Prob. 18ECh. 13.1 - Prob. 19ECh. 13.1 - Prob. 20ECh. 13.1 - Prob. 21ECh. 13.1 - Prob. 22ECh. 13.1 - Prob. 23ECh. 13.1 - Prob. 24ECh. 13.1 - Prob. 25ECh. 13.1 - Prob. 26ECh. 13.1 - Prob. 27ECh. 13.1 - Prob. 28ECh. 13.1 - Prob. 29ECh. 13.1 - Prob. 30ECh. 13.1 - Prob. 31ECh. 13.1 - Prob. 32ECh. 13.1 - Prob. 33ECh. 13.1 - Prob. 34ECh. 13.1 - Prob. 35ECh. 13.1 - Prob. 36ECh. 13.1 - Prob. 37ECh. 13.1 - Prob. 38ECh. 13.1 - Prob. 39ECh. 13.1 - Prob. 40ECh. 13.1 - Prob. 41ECh. 13.1 - Prob. 42ECh. 13.1 - Prob. 43ECh. 13.1 - Prob. 44ECh. 13.1 - Prob. 45ECh. 13.1 - Prob. 46ECh. 13.1 - Prob. 47ECh. 13.1 - Prob. 48ECh. 13.1 - Prob. 49ECh. 13.1 - Prob. 50ECh. 13.1 - Prob. 51ECh. 13.1 - Prob. 52ECh. 13.1 - Prob. 53ECh. 13.2 - Prob. 1PQCh. 13.2 - 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Prob. 46ECh. 13.2 - Prob. 47ECh. 13.2 - Prob. 48ECh. 13.2 - Prob. 49ECh. 13.2 - Prob. 50ECh. 13.2 - Prob. 51ECh. 13.2 - Prob. 52ECh. 13.2 - Prob. 53ECh. 13.2 - Prob. 54ECh. 13.2 - Prob. 55ECh. 13.2 - Prob. 56ECh. 13.2 - Prob. 57ECh. 13.2 - Prob. 58ECh. 13.2 - Prob. 59ECh. 13.2 - Prob. 60ECh. 13.2 - Prob. 61ECh. 13.2 - Prob. 62ECh. 13.2 - Prob. 63ECh. 13.2 - Prob. 64ECh. 13.2 - Prob. 65ECh. 13.2 - Prob. 66ECh. 13.2 - Prob. 67ECh. 13.2 - Prob. 68ECh. 13.2 - Prob. 69ECh. 13.2 - Prob. 70ECh. 13.2 - Prob. 71ECh. 13.2 - Prob. 72ECh. 13.2 - Prob. 73ECh. 13.2 - Prob. 74ECh. 13.2 - Prob. 75ECh. 13.2 - Prob. 76ECh. 13.2 - Prob. 77ECh. 13.2 - Prob. 78ECh. 13.3 - Prob. 1PQCh. 13.3 - Prob. 2PQCh. 13.3 - Prob. 3PQCh. 13.3 - Prob. 4PQCh. 13.3 - Prob. 1ECh. 13.3 - Prob. 2ECh. 13.3 - Prob. 3ECh. 13.3 - Prob. 4ECh. 13.3 - Prob. 5ECh. 13.3 - Prob. 6ECh. 13.3 - Prob. 7ECh. 13.3 - Prob. 8ECh. 13.3 - Prob. 9ECh. 13.3 - Prob. 10ECh. 13.3 - Prob. 11ECh. 13.3 - Prob. 12ECh. 13.3 - Prob. 13ECh. 13.3 - Prob. 14ECh. 13.3 - Prob. 15ECh. 13.3 - Prob. 16ECh. 13.3 - Prob. 17ECh. 13.3 - Prob. 18ECh. 13.3 - Prob. 19ECh. 13.3 - Prob. 20ECh. 13.3 - Prob. 21ECh. 13.3 - Prob. 22ECh. 13.3 - Prob. 23ECh. 13.3 - Prob. 24ECh. 13.3 - Prob. 25ECh. 13.3 - Prob. 26ECh. 13.3 - Prob. 27ECh. 13.3 - Prob. 28ECh. 13.3 - Prob. 29ECh. 13.3 - Prob. 30ECh. 13.3 - Prob. 31ECh. 13.3 - Prob. 32ECh. 13.3 - Prob. 33ECh. 13.3 - Prob. 34ECh. 13.3 - Prob. 35ECh. 13.3 - Prob. 36ECh. 13.3 - Prob. 37ECh. 13.3 - Prob. 38ECh. 13.3 - Prob. 39ECh. 13.3 - Prob. 40ECh. 13.3 - Prob. 41ECh. 13.3 - Prob. 42ECh. 13.3 - Prob. 43ECh. 13.4 - Prob. 1PQCh. 13.4 - Prob. 2PQCh. 13.4 - Prob. 3PQCh. 13.4 - Prob. 4PQCh. 13.4 - Prob. 5PQCh. 13.4 - Prob. 6PQCh. 13.4 - Prob. 7PQCh. 13.4 - Prob. 1ECh. 13.4 - Prob. 2ECh. 13.4 - Prob. 3ECh. 13.4 - Prob. 4ECh. 13.4 - Prob. 5ECh. 13.4 - Prob. 6ECh. 13.4 - Prob. 7ECh. 13.4 - Prob. 8ECh. 13.4 - Prob. 9ECh. 13.4 - Prob. 10ECh. 13.4 - Prob. 11ECh. 13.4 - Prob. 12ECh. 13.4 - Prob. 13ECh. 13.4 - Prob. 14ECh. 13.4 - Prob. 15ECh. 13.4 - Prob. 16ECh. 13.4 - Prob. 17ECh. 13.4 - Prob. 18ECh. 13.4 - Prob. 19ECh. 13.4 - Prob. 20ECh. 13.4 - Prob. 21ECh. 13.4 - Prob. 22ECh. 13.4 - Prob. 23ECh. 13.4 - Prob. 24ECh. 13.4 - Prob. 25ECh. 13.4 - Prob. 26ECh. 13.4 - Prob. 27ECh. 13.4 - Prob. 28ECh. 13.4 - Prob. 29ECh. 13.4 - Prob. 30ECh. 13.4 - Prob. 31ECh. 13.4 - Prob. 32ECh. 13.4 - Prob. 33ECh. 13.4 - Prob. 34ECh. 13.4 - Prob. 35ECh. 13.4 - Prob. 36ECh. 13.4 - Prob. 37ECh. 13.4 - Prob. 38ECh. 13.4 - Prob. 39ECh. 13.4 - Prob. 40ECh. 13.4 - Prob. 41ECh. 13.4 - Prob. 42ECh. 13.4 - Prob. 43ECh. 13.4 - Prob. 44ECh. 13.4 - Prob. 45ECh. 13.4 - Prob. 46ECh. 13.4 - Prob. 47ECh. 13.4 - Prob. 48ECh. 13.4 - Prob. 49ECh. 13.4 - Prob. 50ECh. 13.4 - Prob. 51ECh. 13.4 - Prob. 52ECh. 13.4 - Prob. 53ECh. 13.4 - Prob. 54ECh. 13.4 - Prob. 55ECh. 13.4 - Prob. 56ECh. 13.4 - Prob. 57ECh. 13.4 - Prob. 58ECh. 13.4 - Prob. 59ECh. 13.4 - Prob. 60ECh. 13.4 - Prob. 61ECh. 13.4 - Prob. 62ECh. 13.4 - Prob. 63ECh. 13.4 - Prob. 64ECh. 13.4 - Prob. 65ECh. 13.4 - Prob. 66ECh. 13.4 - Prob. 67ECh. 13.4 - Prob. 68ECh. 13.4 - Prob. 69ECh. 13.4 - Prob. 70ECh. 13.4 - Prob. 71ECh. 13.4 - Prob. 72ECh. 13.4 - Prob. 73ECh. 13.4 - Prob. 74ECh. 13.4 - Prob. 75ECh. 13.4 - Prob. 76ECh. 13.4 - Prob. 77ECh. 13.4 - Prob. 78ECh. 13.4 - Prob. 79ECh. 13.4 - Prob. 80ECh. 13.4 - Prob. 81ECh. 13.4 - Prob. 82ECh. 13.4 - Prob. 83ECh. 13.4 - Prob. 84ECh. 13.4 - Prob. 85ECh. 13.4 - Prob. 86ECh. 13.4 - Prob. 87ECh. 13.4 - Prob. 88ECh. 13.4 - Prob. 89ECh. 13.4 - Prob. 90ECh. 13.4 - Prob. 91ECh. 13.4 - Prob. 92ECh. 13.4 - Prob. 93ECh. 13.5 - Prob. 1PQCh. 13.5 - Prob. 2PQCh. 13.5 - Prob. 3PQCh. 13.5 - Prob. 4PQCh. 13.5 - Prob. 5PQCh. 13.5 - Prob. 6PQCh. 13.5 - Prob. 7PQCh. 13.5 - Prob. 1ECh. 13.5 - Prob. 2ECh. 13.5 - Prob. 3ECh. 13.5 - Prob. 4ECh. 13.5 - Prob. 5ECh. 13.5 - Prob. 6ECh. 13.5 - Prob. 7ECh. 13.5 - Prob. 8ECh. 13.5 - Prob. 9ECh. 13.5 - Prob. 10ECh. 13.5 - Prob. 11ECh. 13.5 - Prob. 12ECh. 13.5 - Prob. 13ECh. 13.5 - Prob. 14ECh. 13.5 - Prob. 15ECh. 13.5 - Prob. 16ECh. 13.5 - Prob. 17ECh. 13.5 - Prob. 18ECh. 13.5 - Prob. 19ECh. 13.5 - Prob. 20ECh. 13.5 - Prob. 21ECh. 13.5 - Prob. 22ECh. 13.5 - Prob. 23ECh. 13.5 - Prob. 24ECh. 13.5 - Prob. 25ECh. 13.5 - Prob. 26ECh. 13.5 - Prob. 27ECh. 13.5 - Prob. 28ECh. 13.5 - Prob. 29ECh. 13.5 - Prob. 30ECh. 13.5 - Prob. 31ECh. 13.5 - Prob. 32ECh. 13.5 - Prob. 33ECh. 13.5 - Prob. 34ECh. 13.5 - Prob. 35ECh. 13.5 - Prob. 36ECh. 13.5 - Prob. 37ECh. 13.5 - Prob. 38ECh. 13.5 - Prob. 39ECh. 13.5 - Prob. 40ECh. 13.5 - Prob. 41ECh. 13.5 - Prob. 42ECh. 13.5 - Prob. 43ECh. 13.5 - Prob. 44ECh. 13.5 - Prob. 45ECh. 13.5 - Prob. 46ECh. 13.5 - Prob. 47ECh. 13.5 - Prob. 48ECh. 13.5 - Prob. 49ECh. 13.5 - Prob. 50ECh. 13.5 - Prob. 51ECh. 13.5 - Prob. 52ECh. 13.5 - Prob. 53ECh. 13.5 - Prob. 54ECh. 13.5 - Prob. 55ECh. 13.5 - Prob. 56ECh. 13.5 - Prob. 57ECh. 13.5 - Prob. 58ECh. 13.5 - Prob. 59ECh. 13.5 - Prob. 60ECh. 13.5 - Prob. 61ECh. 13.6 - Prob. 1PQCh. 13.6 - Prob. 2PQCh. 13.6 - Prob. 3PQCh. 13.6 - Prob. 1ECh. 13.6 - Prob. 2ECh. 13.6 - Prob. 3ECh. 13.6 - Prob. 4ECh. 13.6 - Prob. 5ECh. 13.6 - Prob. 6ECh. 13.6 - Prob. 7ECh. 13.6 - Prob. 8ECh. 13.6 - Prob. 9ECh. 13.6 - Prob. 10ECh. 13.6 - Prob. 11ECh. 13.6 - Prob. 12ECh. 13.6 - Prob. 13ECh. 13.6 - Prob. 14ECh. 13.6 - Prob. 15ECh. 13.6 - Prob. 16ECh. 13.6 - Prob. 17ECh. 13.6 - Prob. 18ECh. 13.6 - Prob. 19ECh. 13.6 - Prob. 20ECh. 13.6 - Prob. 21ECh. 13.6 - Prob. 22ECh. 13.6 - Prob. 23ECh. 13.6 - Prob. 24ECh. 13.6 - Prob. 25ECh. 13 - Prob. 1CRECh. 13 - Prob. 2CRECh. 13 - Prob. 3CRECh. 13 - Prob. 4CRECh. 13 - Prob. 5CRECh. 13 - Prob. 6CRECh. 13 - Prob. 7CRECh. 13 - Prob. 8CRECh. 13 - Prob. 9CRECh. 13 - Prob. 10CRECh. 13 - Prob. 11CRECh. 13 - Prob. 12CRECh. 13 - Prob. 13CRECh. 13 - Prob. 14CRECh. 13 - Prob. 15CRECh. 13 - Prob. 16CRECh. 13 - Prob. 17CRECh. 13 - Prob. 18CRECh. 13 - Prob. 19CRECh. 13 - Prob. 20CRECh. 13 - Prob. 21CRECh. 13 - Prob. 22CRECh. 13 - Prob. 23CRECh. 13 - Prob. 24CRECh. 13 - Prob. 25CRECh. 13 - Prob. 26CRECh. 13 - Prob. 27CRECh. 13 - Prob. 28CRECh. 13 - Prob. 29CRECh. 13 - 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- 3.13 (B). A beam ABC, 6 m long, is simply-supported at the left-hand end A and at B I'm from the right-hand end C. The beam is of weight 100 N/metre run. (a) Determine the reactions at A and B. (b) Construct to scales of 20 mm = 1 m and 20 mm = 100 N, the shearing-force diagram for the beam, indicating thereon the principal values. (c) Determine the magnitude and position of the maximum bending moment. (You may, if you so wish, deduce the answers from the shearing force diagram without constructing a full or partial bending-moment diagram.) [C.G.] C240 N, 360 N, 288 Nm, 2.4 m from A.]arrow_forward5. Using parentheses make sense of the expression V · VXVV · Å where Ả = Ã(x, y, z). Is the result a vector or a scaler?arrow_forward3.10 (A/B). A beam ABCDE is simply supported at A and D. It carries the following loading: a distributed load of 30 kN/m between A and B, a concentrated load of 20 KN at B, a concentrated load of 20 KN at C, a concentrated load of 10 KN at E; a distributed load of 60 kN/m between 0 and E. Span AB = 1.5 BC = CD = DE 1 m. Calculate the value of the reactions at A and D and hence draw the S.F. and B.M. diagrams. What are the magnitude and position of the maximum B.M. on the beam? [41.1, 113.9 KN, 28.15 kNm; 1.37 m from A.J m,arrow_forward
- 3.14 (B). A beam ABCD, 6 m long, is simply-supported at the right-hand end and at a point B Im from the left-hand end A. It carries a vertical load of 10 KN at A, a second concentrated load of 20 KN at C, 3 m from D, and a uniformly distributed load of 10 kN/m between C and D. Determine: (a) the values of the reactions at B and 0, (6) the position and magnitude of the maximum bending moment. [33 KN, 27 KN, 2.7 m from D, 36.45k Nm.]arrow_forward3.17 (B). A simply supported beam has a span of 6 m and carries a distributed load which varies in a linea manner from 30 kN/m at one support to 90 kN/m at the other support. Locate the point of maximum bendin moment and calculate the value of this maximum. Sketch the S.F. and B.M. diagrams. [U.L.] [3.25 m from l.h. end; 272 KN m 30. 90arrow_forward3.11 (B). A beam, 12 m long, is to be simply supported at 2m from each end and to carry a U.d.l of 30kN/m together with a 30 KN point load at the right-hand end. For ease of transportation the beam is to be jointed in two places, one joint being Situated 5 m from the left-hand end. What load (to the nearest KN) must be applied to the left-hand end to ensure that there is no B.M. at the joint (i.e. the joint is to be a point of contraflexure)? What will then be the best position on the beam for the other joint? Determine the position and magnitude of the maximum B.M. present on the beam. [114 KN, 1.6 m from r.h. reaction; 4.7 m from 1.h. reaction; 43.35 KN m.]arrow_forward
- 2. Using vector algebraic operations, if - Ả = 2ây – mây – C - B = mây tây – 2, C = ây + mây + 20, D = m x + mây tậ Z Find the value(s) of m such that (a) Ả is perpendicular to B (b) B is parallel to Carrow_forward1. Determine whether the following sets are subspaces of $\mathbb{R}^3$ under the operations of addition and scalar multiplication defined on $\mathbb{R}^3$. Justify your answers.(a) $W_1=\left\{\left(a_1, a_2, a_3\right) \in \mathbb{R}^3: a_1=3 a_2\right.$ and $\left.a_3=\mid a_2\right\}$(b) $W_2=\left\{\left(a_1, a_2, a_3\right) \in \mathbb{R}^3: a_1=a_3+2\right\}$(c) $W_3=\left\{\left(a_1, a_2, a_3\right) \in \mathbb{R}^3: 2 a_1-7 a_2+a_3=0\right\}$(d) $W_4=\left\{\left(a_1, a_2, a_3\right) \in \mathbb{R}^3: a_1-4 a_2-a_3=0\right\}$(e) $W_s=\left\{\left(a_1, a_2, a_3\right) \in \mathbb{R}^3: a_1+2 a_2-3 a_3=1\right\}$(f) $W_6=\left\{\left(a_1, a_2, a_3\right) \in \mathbb{R}^3: 5 a_1^2-3 a_2^2+6 a_3^2=0\right\}$arrow_forward3 Evaluate the double integral 10 y√x dy dx. First sketch the area of the integral involved, then carry out the integral in both ways, first over x and next over y, and vice versa.arrow_forward
- Question 2. i. Suppose that the random variable X takes two possible values 1 and -1, and P(X = 1) = P(X-1)=1/2. Let Y=-X. Are X and Y the same random variable? Do X and Y have the same distribution? Explain your answer. ii. Suppose that the random variable X~N(0, 1), let Y=-X. Are X and Y the same random variable? Do X and Y have the same distribution? Explain your answer.arrow_forwardProblem 4. Let f(x, y) = { Find P(X <1/2|Y = 1/2). c(x + y²) 0arrow_forwardQize f(x) x + 2x2 - 2 x² + 4x² - 4 Solve the equation using Newton Raphsonarrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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