Explanation Given Information: The distance covered by the dumbbell weighing 10 pound thrown by Prof. Strong is twice as high as Prof. Weak and the initial velocity is v 0 ft/sec . Formula used: The velocity of a projectile is given by the formula, v ( t ) = − 32 t + v 0 ft/sec Where t represents time and v 0 represents the initial velocity. The position of a projectile is given by the formula, s ( t ) = − 16 t 2 + v 0 t + s 0 feet Where t represents time and s 0 represents the initial position. Calculation: Consider that v 0 and u 0 be the velocity by which Prof. Strong and Prof. Weak throw the dumbbell respectively. The velocity of a dumbbell at time t , if the initial velocity is v 0 ft/sec , is given by the formula, v ( t ) = − 32 t + v 0 ft/sec Now compute the time taken by dumbbell to reach highest point by using v ( t ) = 0 , v ( t ) = − 32 ⋅ t + v 0 ft/sec 0 = − 32 t + v 0 32 t = v 0 Solve for t this gives, t = v 0 32 Therefore, the dumbbell reached at highest point after v 0 32 seconds. The position s ( t ) of a dumbbell at time t , if the initial position is s 0 feet , is given by the formula, s ( t ) = − 16 t 2 + v 0 t + s 0 feet Consider the initial position, s 0 = 0 feet Now compute the hi

Finite Mathematics and Applied Calculus (MindTap Course List)

7th Edition

ISBN: 9781337274203

Author: Stefan Waner, Steven Costenoble

Publisher: Cengage Learning

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Chapter 13.1, Problem 75E

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To calculate: The value by which Prof. Strong can throw a dumbbell with respect to Prof. Weak, if distance covered by the dumbbell weighing 10 pound thrown by Prof. Strong is twice as high as Prof. Weak and the initial velocity is v0 ft/sec.

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Chapter 13.1, Problem 74E

Chapter 13.1, Problem 76E

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Finite Mathematics and Applied Calculus (MindTap Course List)

Ch. 13.1 - In Exercises 142, evaluate the integral. [HinT:...Ch. 13.1 - Prob. 2E Ch. 13.1 - Prob. 3E Ch. 13.1 - Prob. 4E Ch. 13.1 - Prob. 5E Ch. 13.1 - Prob. 6E Ch. 13.1 - Prob. 7E Ch. 13.1 - Prob. 8E Ch. 13.1 - Prob. 9E Ch. 13.1 - Prob. 10E

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The value by which Prof. Strong can throw a dumbbell with respect to Prof. Weak, if distance covered by the dumbbell weighing 10 pound thrown by Prof. Strong is twice as high as Prof. Weak and the initial velocity is v 0 ft/sec .

Solution Summary: The author explains how Prof. Strong throws a dumbbell twice as fast as prof. Weak.

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To calculate: The value by which Prof. Strong can throw a dumbbell with respect to Prof. Weak, if distance covered by the dumbbell weighing 10 pound thrown by Prof. Strong is twice as high as Prof. Weak and the initial velocity is v0 ft/sec.

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Chapter 13 Solutions